Concept explainers
In rats, gene
a.
b. 3 brown, 3 yellow, 1 black, 1 cream
c. 9 black, 7 brown
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Genetic Analysis: An Integrated Approach (3rd Edition)
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Anatomy & Physiology
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- In mice, the A allele causes agouti fur, the AY allele causes yellow fur and is dominant to the A allele. The homozygous AY AY genotype is lethal. Why is the AYAY homozygous condition lethal? The AY allele highly transcribes the merc gene which is lethal in a homozygous AYAY individual. None of the other answers are correct. The AY allele lacks an upstream merc gene which is required for normal embryonic development. The AY allele contains a null mutation in the A gene, which is required for normal embryonic development. The yellow pigment produced by A allele is required for survival.arrow_forwardColored aleurone in the kernels of corn is due to the dominant allele R. The recessive allele r, when homozygous, produces colorless aleurone. The plant color (not the kernel color) is controlled by another gene with two alleles, Y and y. The dominant Y allele results in green color, whereas the homozygous presence of the recessive y allele causes the plant to appear yellow. In a testcross between a plant of unknown genotype and phenotype and a plant that is homozygous recessive for both traits, the following progeny were obtained: colored, green 88 colored, yellow 12 colorless, green 8 colorless, yellow 92 Explain how these results were obtained by determining the exact genotype and phenotype of the unknown plant, including the precise arrangement of the alleles on the homologs.arrow_forwardKernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of the offspring with the following genotypes: (Note: 4 contributing alleles – red; 3 contributing alleles – medium red; 2 contributing alleles – intermediate red; 1 contributing allele – red; and 0 – white (AAbb x AaBb, AABb x Aabb, aaBb x Aabb, AABb x aabb, AABb x AaBb) Refer to the problem above, a wheat plant producing medium red seed is crossed with another plant producing intermediate red seed. How many individuals will be? Red Medium red Intermediate red Light red Whitearrow_forward
- In onions, presence of gene C causes production of an enzyme which catalyzes theproduction of bulb-color pigment. Gene K prevents this enzyme from functioning, thuspreventing enzyme production. The two genes are inherited independently. A true breedingcolored variety is crossed with a white one of genotype ccKK. (b) Another pair of alleles R and r, independent of genes C and K controls the specific color for bulbs, R giving red and r, yellow bulbs. If the true-breeding colored variety are homozygous for R and the white ones homozygous for r, what would be the phenotypic ratios in the F1 and F2 of the above cross?arrow_forwardMiniature wings (Xm) in Drosophila result from an X-linked allele that is recessive to the allele for long wings (X*). Give the genotypes of the parents in the following cross: Male parent Female parent Male offspring Female offspring 231 long, 250 miniature Long Long 560 long O male: Xm/Y and female X* /X* male: X* / Y and female Xm /x O male: X* /Y and female X* /X* male: Xm/Y and female Xm /x+arrow_forwardFruit flies express both normal wing shape and vestigial wing shape. The pedigree shows the inheritance of the wing-shape trait over two generations. In the pedigree, squares represent males and circles represent females. Shaded symbols represent an individual with normal wing shape. A cross between individual 4 and individual 5 in the pedigree resulted in the data shown in the table. This data results in a chi-square value of 6.45. Female Male Normal 25 39 Vestigial 22 14 Degrees of Freedom p 1 2 0.05 3.84 5.99 0.01 6.64 9.32 Based on the data, which of the following best supports the claim that this trait exhibits an autosomal dominant inheritance pattern? The results of the cross show that there were no heterozygous dominant females. The chi-square value shows that these results are not typical of this type of cross. The results of the cross show that fewer males exhibited the recessive trait than females. The…arrow_forward
- In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus (genotype R_ P_). A rose comb is produced when at least one dominant gene is present at the first locus and two recessive genes are present at the second locus (genotype R_ pp). A pea comb is produced when two recessive genes are present at the first locus and at least one dominant gene is present at the second (genotype rr P_). If two recessive genes are present at the first and the second locus (rr pp), a single comb is produced. Give genotypes for comb shape of the parents in the following cross: Rose crossed with pea produces 20 walnut offspring. O A. Rr pp x Rr Pp B. Rr pp x rr PP C. Rr pp x rr Pp D. RR pp x rr PP O E. RR pp x rr Pp Reset Selection Mark for Douiouuarrow_forwardIn Drosophila fruit flies, the genes for warped wings (dwp), rumpled bristles (rmp), and pallid wings (pld) are linked. A trihybrid female for all three allleles is crossed with homozygous recessive male for all three alleles and the offspring obtained showed the following phenotypes: 3 pld rmp dwp 428 pld rmp + 427 + + dwp 48 + rmp + 47 pld + dwp 23 pld + + 2 + + + 22 + rmp dwp What is the order and map distance between these three alleles?arrow_forwardIn Drosophila, the sepia mutation (se, chromosome 3, position 26) results in dark brown eyes, while cinnabar (cn, chromosome 2, position 57.5) results in bright orange-red eyes. True breeding, wild type females are mated with true breeding males homozygous recessive for both traits. Using Drosophila notation, diagram the P1 and F1 crosses. P1 F1 Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work. Phenotype Females Males Overall (♀and ♂) =1 =1arrow_forward
- Pigment in the mouse is produced only when the C allele is present.Individuals of the cc genotype have no color. If color is present,it may be determined by the A and a alleles. AA or Aa resultsin agouti color, whereas aa results in black coats.(a) What F1 and F2 genotypic and phenotypic ratios areobtained from a cross between AACC and aacc mice?(b) In the three crosses shown here between agouti femaleswhose genotypes were unknown and males of the aaccgenotype, what are the genotypes of the female parents foreach of the following phenotypic ratios? (1) 8 agouti (2) 9 agouti (3) 4 agouti8 colorless 10 black 5 black 10 colorlessarrow_forwardKernel color in wheat is controlled by 2 pairs of genes (AABB). Determine the color of the offspring with the following genotypes: (Note: 4 contributing alleles – red; 3 contributing alleles – medium red; 2 contributing alleles – intermediate red; 1 contributing allele – red; and 0 – white (AAbb x AaBb, AABb x Aabb, aaBb x Aabb, AABb x aabb, AABb x AaBb) Show the solution through punnett square. Refer to the problem above, a wheat plant producing medium red seed is crossed with another plant producing intermediate red seed. How many individuals will be?Show the solution through punnett square. Red Medium red Intermediate red Light red Whitearrow_forwardIn aliens, the genes A, B, C, D and E are dominant to their respective alleles a, b, c, d and e: A = one eye a = two eyes B = pointed ears b = round ears C = red skin c = green skin D = two antennae d = three antennae E = square head e = triangular head An alien with genotype AA bb Cc dd Ee marries an alien with genotype Aa Bb Cc Dd Ee. If the genes segregate independently, what is the probability that they will have a child with one eye, pointed ears, red skin, three antennae and a triangular head? A. 9/512 B. 9/128 C. 27/1024 D. 3/64arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning