Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 47Q
To determine
The importance of the discovery of Neptune for the confirmation of Newton’s law of universal gravitation.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Use the Law of Gravitation with Kepler's third Law to determine the mass of the
Sun. Don't forget to include units!
What is planetary motion through Kepler's law?
Why, if the sun is so much more massive than the moon, isn’t it responsible for the Tides? Use Universal Law of Gravitation to explain.
Chapter 4 Solutions
Universe: Stars And Galaxies
Ch. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4QCh. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10Q
Ch. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 14QCh. 4 - Prob. 15QCh. 4 - Prob. 16QCh. 4 - Prob. 17QCh. 4 - Prob. 18QCh. 4 - Prob. 19QCh. 4 - Prob. 20QCh. 4 - Prob. 21QCh. 4 - Prob. 22QCh. 4 - Prob. 23QCh. 4 - Prob. 24QCh. 4 - Prob. 25QCh. 4 - Prob. 26QCh. 4 - Prob. 27QCh. 4 - Prob. 28QCh. 4 - Prob. 29QCh. 4 - Prob. 30QCh. 4 - Prob. 31QCh. 4 - Prob. 32QCh. 4 - Prob. 33QCh. 4 - Prob. 34QCh. 4 - Prob. 35QCh. 4 - Prob. 36QCh. 4 - Prob. 37QCh. 4 - Prob. 38QCh. 4 - Prob. 39QCh. 4 - Prob. 40QCh. 4 - Prob. 41QCh. 4 - Prob. 42QCh. 4 - Prob. 43QCh. 4 - Prob. 44QCh. 4 - Prob. 45QCh. 4 - Prob. 46QCh. 4 - Prob. 47QCh. 4 - Prob. 48QCh. 4 - Prob. 49QCh. 4 - Prob. 50QCh. 4 - Prob. 51QCh. 4 - Prob. 52QCh. 4 - Prob. 53QCh. 4 - Prob. 54QCh. 4 - Prob. 55QCh. 4 - Prob. 56QCh. 4 - Prob. 57QCh. 4 - Prob. 58Q
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A synchronous satellite, which always remains above the same point on a planet's equator, is put in circular orbit around Neptune so that scientists can study a surface feature. Neptune rotates once every 16.1 h. Use the data of this table to find the altitude of the satellite. kmarrow_forwardThe table below lists the average distance R to the Sun and orbital period T of the first planets:Distance Orbital PeriodMercury 0.39 AU 88 daysVenus 0.72 AU 225 daysEarth 1.00 AU 365 daysMars 1.52 AU 687 days(a) Calculate the average distance of Mercury, Venus and Mars to the Earth.Which one of these planets is the closest to Earth on average?(b) Calculate the average distance of Mercury, Venus and Earth to Mars.Which one of these planets is the closest to Mars on average?(c) What do you expect for the other planets?arrow_forwardJupiter has a mass of 1.9×10^27 kg, a radius of 7.1×10^4 km and one day lasts 9 hours and 55 minutes. How many times is the force of gravity bigger on Jupiters equator comared to Earth?arrow_forward
- The table below lists the average distance R to the Sun and orbital period T of the first planets:Distance Orbital PeriodMercury 0.39 AU 88 daysVenus 0.72 AU 225 daysEarth 1.00 AU 365 daysMars 1.52 AU 687 days(a) Calculate the average distance of Mercury, Venus and Mars to the Earth.Which one of these planets is the closest to Earth on average?(b) Calculate the average distance of Mercury, Venus and Earth to Mars.Which one of these planets is the closest to Mars on average?(c) What do you expect for the other planets?Hint: Assume circular orbits and use symmetries to make the distance calculation easier. You canapproximate the average distance by using four well-chosen points on the planet’s orbit.www.iaac.arrow_forwardThe mass of Jupiter is 1/1047 of the Sun's mass (that's 0.000955). We want to confirm this using Newton's version of Kepler's Third Law, following the examples in Lecture 7. We'll use the approximate data for two different moons of Jupiter to see how close the results are. Pick the closest answer in each case: (a) Ganymede is the third moon from the inside. It has an orbital period around Jupiter of approximately 0.0194 Earth years. Its semimajor axis is 0.0071 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data? (b) Europa is the second moon from the inside. It has an orbital period around Jupiter of approximately 0.0096 Earth years. Its semimajor axis is 0.0045 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data?arrow_forwardSaturn's mass is M= 5.69 x 1026 kg and its radius R=60,300 km. If a moon orbits Saturn at a distance equal to 5 times its planetary radius, what is its period of orbit? (Hint, use Newton's version of Kepler's 3rd law, and you can neglect the mass of the moon) Express your answer in days to three significant figures.arrow_forward
- 4000 km O Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display. Europa Ganymede Jupiter Callisto Titan Saturn Triton Neptune Suppose the moon of a planet has a mass of 1/93th the mass of the planet it is orbiting (note: the moons shown above actually are even a smaller fraction than that!). What is the ratio of the force the moon applies to the planet compared to the force the planet applies to the moon? (Express your answer as a number--don't enter anything like A:B or A/B, just the single number you get by dividing A by B.)arrow_forwardEstimate the length of period of Neptune assuming that the length of the semimajor axis of the ellipse is a = 449.51 x 101º m. For Earth, a = 15.0 × 1010 m. (Use decimal notation. Give your answer to two decimal places.)arrow_forwardIf the semi-major axis, a, is measured in AU and the orbital period, p, is measured in years, then Kepler's 3rd law allows us to calculate the mass of the object they are orbiting using the following equation: M = a3/p2 Furthermore, the mass that is calculated by this equation is given in solar masses (MSun) where, by definition, the Sun's mass is 1 MSun. Now, suppose I were to tell you that the mass of Jupiter is equal to 4.5e7 MSun. Does the stated mass of Jupiter make sense? it is to big or to small or makes sensearrow_forward
- If the semi-major axis, a, is measured in AU and the orbital period, p, is measured in years, then Kepler's 3rd law allows us to calculate the mass of the object they are orbiting using the following equation: M = a3/p2 Furthermore, the mass that is calculated by this equation is given in solar masses (MSun) where, by definition, the Sun's mass is 1 MSun. Now, suppose I were to tell you that the mass of Jupiter is equal to 4.5e7 MSun. Does the stated mass of Jupiter make sense? Group of answer choices - Yes - No, it's too big. - No, it's too smallarrow_forwardWhich of Kepler's law can be used to estimate the mass of a distant star system based on the period and semimajor axis of its planet?arrow_forwardNeptune circles the Sun at a distance of 4.50 x 1012 m once every 164 years. Saturn circles the Sun at a distance of 1.43 x 1012 m. What is the orbital period of Saturn? a) 88.6 y 702 b) 109 h C) 29.4 y d) 304 y Boş bırakarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY