EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
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Chapter 4, Problem 4.61P
To determine
The new internal diameter of the ring specimen.
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Check out a sample textbook solutionStudents have asked these similar questions
Q2/ Aluminum tensile specimen with 12.5mm diameter, a gauge length of 50.8mm and the final
diameter was 10.5mm.
• Plot the engineering stress-strain curve and the true stress- strain curve.
Determine proportion limit, young's modulus, the yield point, the ultimate tensile strength,
the failure stress on drawing?
• Determine Ductility?
• Determine Resilience modulus and toughness modulus?
0.006 0.008 0.012 0.017
Strain mm/mm
Apparent Stress N/mm 100
0.004
0.22
0.25
0.27
150
200
290
325
480
450
410
True stress N/mm
100.1
150.3 201
326
400
500
550
620
If the tensile specimen is not cylindrical rod shaped but a flat rectangular plate, how do
you expect necking to occur in this type of specimen?
The following results were obtained in a tensile test on a mild steel specimen of original diameter 28 mm and gauge length 56 mm.
Load at limit of proportionality : 96 kN
Extension at 96 kN load : 0.068 mm
Load at yield point : 105 kN
Maximum load : 170 kN
When the two parts were fitted together after being broken, the length between gauge length was found to be 65.8 mm and the diameter at the neck was 18.8 mm. Calculate:
(a). E,
(b).σy,
(c).σu,
(d). PRIA and PE
Chapter 4 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 4 - Prob. 4.1QCh. 4 - Prob. 4.2QCh. 4 - Prob. 4.3QCh. 4 - Prob. 4.4QCh. 4 - Prob. 4.5QCh. 4 - Prob. 4.6QCh. 4 - Prob. 4.7QCh. 4 - Prob. 4.8QCh. 4 - Prob. 4.9QCh. 4 - Prob. 4.10Q
Ch. 4 - Prob. 4.11QCh. 4 - Prob. 4.12QCh. 4 - Prob. 4.13QCh. 4 - Prob. 4.14QCh. 4 - Prob. 4.15QCh. 4 - Prob. 4.16QCh. 4 - Prob. 4.17QCh. 4 - Prob. 4.18QCh. 4 - Prob. 4.19QCh. 4 - Prob. 4.20QCh. 4 - Prob. 4.21QCh. 4 - Prob. 4.22QCh. 4 - Prob. 4.23QCh. 4 - Prob. 4.24QCh. 4 - Prob. 4.25QCh. 4 - Prob. 4.26QCh. 4 - Prob. 4.27QCh. 4 - Prob. 4.28QCh. 4 - Prob. 4.29QCh. 4 - Prob. 4.30QCh. 4 - Prob. 4.31QCh. 4 - Prob. 4.32QCh. 4 - Prob. 4.33QCh. 4 - Prob. 4.34QCh. 4 - Prob. 4.35QCh. 4 - Prob. 4.36QCh. 4 - Prob. 4.37QCh. 4 - Prob. 4.38QCh. 4 - Prob. 4.39QCh. 4 - Prob. 4.40QCh. 4 - Prob. 4.41QCh. 4 - Prob. 4.42QCh. 4 - Prob. 4.43QCh. 4 - Prob. 4.44QCh. 4 - Prob. 4.45QCh. 4 - Prob. 4.46QCh. 4 - Prob. 4.47QCh. 4 - Prob. 4.48QCh. 4 - Prob. 4.49QCh. 4 - Prob. 4.50QCh. 4 - Prob. 4.51QCh. 4 - Prob. 4.52QCh. 4 - Prob. 4.53QCh. 4 - Prob. 4.54QCh. 4 - Prob. 4.55QCh. 4 - Prob. 4.56QCh. 4 - Prob. 4.57PCh. 4 - Prob. 4.58PCh. 4 - Prob. 4.59PCh. 4 - Prob. 4.60PCh. 4 - Prob. 4.61PCh. 4 - Prob. 4.62PCh. 4 - Prob. 4.63PCh. 4 - Prob. 4.64PCh. 4 - Prob. 4.65PCh. 4 - Prob. 4.66PCh. 4 - Prob. 4.67PCh. 4 - Prob. 4.68PCh. 4 - Prob. 4.69PCh. 4 - Prob. 4.70PCh. 4 - Prob. 4.71P
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- 2 The bench vice shown in Fig. is used to fix a cubic wood sample with a hole. The wood sample has a length of 30 mm, and the hole has a 20mm-diameter. The wood compressive strength is 20 MPa. The pressure on the sample is intended not to exceed two-third of its strength. The bench vice is made of cast iron whose yield strength is 200 MPa. Suggest dimensions for a hollow circular cross section where its thickness in one-tenth the outer diameter to replace the current cross section at (m-n) and withstand the worst case of applied stress due to these working conditions. Wood Sample 11 -Centroidal axis 60 mm Figure 2 14 mm 11 mm 1=7800 mm A = 130 mm²arrow_forwardThe results of a tensile test are: Diameter of the specimen Gauge length Load at limit of Proportionality Extension at the limit of Proportionality Maximum Load : 10mm :40 mm :80kN : 0.06mm. :100 kN Calculate ultimate tensile stress and young's modulus.arrow_forwardLets assume that a block has been kept on a rough floor. We started applying a variable force "F" (assume that the force is being increased) on the block. Draw the graph of Frictional force (Y axis) vs Applied Force (X axis) ! Also tell the peculiar change observed in the latter part of the graph ! Don't Spam, Don't Copy from Internet. Explain Clearly. Thank you ! All the Best :)arrow_forward
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