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Explain Flexure Test of Small, Clear Specimen (ASTM D143) ?

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Section: Chapter Questions

Problem 20R: What are the maximum acceptance criteria for bend test specimens?

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What are the maximum acceptance criteria for bend test specimens?
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Q2/ Aluminum tensile specimen with 12.5mm diameter, a gauge length of 50.8mm and the final diameter was 10.5mm. • Plot the engineering stress-strain curve and the true stress- strain curve. Determine proportion limit, young's modulus, the yield point, the ultimate tensile strength, the failure stress on drawing? • Determine Ductility? • Determine Resilience modulus and toughness modulus? 0.006 0.008 0.012 0.017 Strain mm/mm Apparent Stress N/mm 100 0.004 0.22 0.25 0.27 150 200 290 325 480 450 410 True stress N/mm 100.1 150.3 201 326 400 500 550 620
Hardness tests are performed more frequently than any other mechanical test for several reasons: (Choose all that apply): Other mechanical properties can be estimated from hardness data such as tensile strength The test is simple and inexpensive The test is nondestructive, which means that the specimen is neither fractured or excessively deformed after the test Testing apparatus is relatively expensive
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Your manager asked you to explain the difference between three-point bending test and four-pointbending test by using a standard specimen each one has the following dimensions:1. Force = 30 KN.2. Thickness= 5 cm.3. Width = 10 cm.4. Length = 25 cm.Calculate the stress on each specimen then justify your answer
In tensile testing a tensile load is applied to the specimen until it a. bend O b. fractures C. twist d. compressed fully
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