Chapter 4, Problem 45A

(a)

Interpretation Introduction

Interpretation: The ionic compound FeBr₂ needs to be named using the system that includes Roman numerical to specify the charge of the cations.

Concept introduction:Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 45A

Iron (II) bromide.

Explanation of Solution

The charge on the cation can be determined by taking the total charge on the compound to be zero.

The known charge on anion is then used to determine the charge on the cation.

Compound	Cation present	Anion present	Compound name	Comments
${\text{FeBr}}_2$	${\text{Fe}}^{2+}$	${\text{Br}}^{\text{-}}$	Iron(II)bromide	Iron can have more than 1 oxidation state, so one must include (II) to specify its charge.

(b)

Interpretation Introduction

Interpretation: The ionic compound CoS needs to be named using the system that includes Roman numerical to specify the charge of the cations.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 45A

Cobalt (II)sulfide.

Explanation of Solution

The charge on the cation can be determined by taking the total charge on the compound to be zero.

The known charge on anion is then used to determine the charge on the cation.

Compound	Cation present	Anion present	Compound name	Comments
$\text{CoS}$	${\text{C}}^{\text{2+}}$	${\text{S}}^{\text{2-}}$	Cobalt(II)sulfide	Cobalt can have more than 1 oxidation state, so one must include II to specify its charge.

(c)

Interpretation Introduction

Interpretation: The ionic compound ${\text{Co}}_2{\text{S}}_3$ needs to be named using the system that includes Roman numerical to specify the charge of the cations.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 45A

Cobalt(III)sulfide

Explanation of Solution

The charge on the cation can be determined by taking the total charge on the compound to be zero.

The known charge on anion is then used to determine the charge on the cation.

Compound	Cation present	Anion present	Compound name	Comments
${\text{Co}}_2{\text{S}}_3$	${\text{Co}}^{\text{2+}}$	${\text{S}}^{\text{2-}}$	Cobalt(III)sulfide	Cobalt can have more than 1 oxidation state, so one must include the III to specify its charge.

(d)

Interpretation Introduction

Interpretation: The ionic compound ${\text{SnO}}_2$ needs to be named using the system that includes Roman numerical to specify the charge of the cations.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 45A

Tin(IV)oxide

Explanation of Solution

The charge on the cation can be determined by taking the total charge on the compound to be zero.

The known charge on anion is then used to determine the charge on the cation.

Compound	Cation present	Anion present	Compound name	Comments
${\text{SnO}}_2$	${\text{Sn}}^{\text{4+}}$	${\text{O}}^{\text{2-}}$	Tin(IV)oxide	Tin can have more than 1 oxidation state so one must include IV to specify its charge.

(e)

Interpretation Introduction

Interpretation: The ionic compound ${\text{Hg}}_{\text{2}}{\text{Cl}}_{\text{2}}$ needs to be named using the system that includes Roman numerical to specify the charge of the cations.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 45A

Mercury(I)chloride

Explanation of Solution

The charge on the cation can be determined by taking the total charge on the compound to be zero.

The known charge on anion is then used to determine the charge on the cation.

Compound	Cation present	Anion present	Compound name	Comments
${\text{Hg}}_{\text{2}}{\text{Cl}}_{\text{2}}$	${\text{Hg}}^{\text{+}}$	${\text{Cl}}^{\text{-}}$	Mercury(I)chloride	Mercury can have more than 1 oxidation state so one must include I to specify its charge.

(f)

Interpretation Introduction

Interpretation: The ionic compound ${\text{HgCl}}_{\text{2}}$ needs to be named using the system that includes Roman numerical to specify the charge of the cations.

Concept introduction: Binary ionic compounds contain a metal that can form more than one type of cation.

Answer to Problem 45A

Mercury (II) chloride

Explanation of Solution

The charge on the cation can be determined by taking the total charge on the compound to be zero.

The known charge on anion is then used to determine the charge on the cation.

Compound	Cation present	Anion present	Compound name	Comments
${\text{HgCl}}_{\text{2}}$	${\text{Hg}}^{\text{+}}$	${\text{Cl}}^{\text{-}}$	Mercury (II) chloride	Mercury can have more than 1 oxidation state so one must include II to specify its charge.