Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
expand_more
expand_more
format_list_bulleted
Concept explainers
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Part C
Bond length is the distance between the centers of two bonded atoms. On
the potential energy curve, the bond length is the internuclear distance
between the two atoms when the potential energy of the system reaches
its lowest value.
Consider that the atomic radius (sometimes called the covalent or
bonding atomic radius) of an element is defined as one-half the distance
between the bonded atoms in a homonuclear diatomic molecule. Actual
bond lengths in molecules are determined experimentally by such
methods as X-ray diffraction and microwave spectroscopy. However,
these atomic radii values can be used to give an estimate of the upper
limit of bond length in other (heteronuclear) molecules.
Given that the atomic radii of H and F are 37.0 pm and 72.0 pm,
respectively, predict the upper limit of the bond length of the HF
molecule.
Express your answer to three significant figures and include the
appropriate units.
► View Available Hint(s)
Bond length upper
limit=
Submit
μÅ
Value…
How does the number of valence electrons vary within a group?
What is the relationship between the tendency of a main-group element to form a monatomic ion and its position in the periodic table? In what part of the table are the main-group ele-ments that typically form cations? Anions?
Chapter 4 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 4 - Prob. 4.3VPCh. 4 - Prob. 4.4VPCh. 4 - Prob. 4.8VPCh. 4 - Prob. 4.9VPCh. 4 - Prob. 4.10VPCh. 4 - Prob. 4.11VPCh. 4 - Prob. 4.12VPCh. 4 - Prob. 4.13QACh. 4 - Prob. 4.14QACh. 4 - Prob. 4.15QA
Ch. 4 - Prob. 4.16QACh. 4 - Prob. 4.17QACh. 4 - Prob. 4.18QACh. 4 - Prob. 4.19QACh. 4 - Prob. 4.20QACh. 4 - Prob. 4.21QACh. 4 - Prob. 4.22QACh. 4 - Prob. 4.23QACh. 4 - Prob. 4.24QACh. 4 - Prob. 4.25QACh. 4 - Prob. 4.26QACh. 4 - Prob. 4.27QACh. 4 - Prob. 4.28QACh. 4 - Prob. 4.29QACh. 4 - Prob. 4.30QACh. 4 - Prob. 4.31QACh. 4 - Prob. 4.32QACh. 4 - Prob. 4.33QACh. 4 - Prob. 4.34QACh. 4 - Prob. 4.35QACh. 4 - Prob. 4.36QACh. 4 - Prob. 4.37QACh. 4 - Prob. 4.38QACh. 4 - Prob. 4.39QACh. 4 - Prob. 4.40QACh. 4 - Prob. 4.41QACh. 4 - Prob. 4.42QACh. 4 - Prob. 4.43QACh. 4 - Prob. 4.44QACh. 4 - Prob. 4.45QACh. 4 - Prob. 4.46QACh. 4 - Prob. 4.49QACh. 4 - Prob. 4.50QACh. 4 - Prob. 4.51QACh. 4 - Prob. 4.52QACh. 4 - Prob. 4.53QACh. 4 - Prob. 4.54QACh. 4 - Prob. 4.55QACh. 4 - Prob. 4.56QACh. 4 - Prob. 4.57QACh. 4 - Prob. 4.58QACh. 4 - Prob. 4.59QACh. 4 - Prob. 4.60QACh. 4 - Prob. 4.61QACh. 4 - Prob. 4.62QACh. 4 - Prob. 4.63QACh. 4 - Prob. 4.64QACh. 4 - Prob. 4.66QACh. 4 - Prob. 4.67QACh. 4 - Prob. 4.68QACh. 4 - Prob. 4.69QACh. 4 - Prob. 4.70QACh. 4 - Prob. 4.71QACh. 4 - Prob. 4.72QACh. 4 - Prob. 4.73QACh. 4 - Prob. 4.74QACh. 4 - Prob. 4.75QACh. 4 - Prob. 4.76QACh. 4 - Prob. 4.77QACh. 4 - Prob. 4.78QACh. 4 - Prob. 4.79QACh. 4 - Prob. 4.80QACh. 4 - Prob. 4.81QACh. 4 - Prob. 4.82QACh. 4 - Prob. 4.83QACh. 4 - Prob. 4.84QACh. 4 - Prob. 4.85QACh. 4 - Prob. 4.86QACh. 4 - Prob. 4.87QACh. 4 - Prob. 4.88QACh. 4 - Prob. 4.89QACh. 4 - Prob. 4.90QACh. 4 - Prob. 4.91QACh. 4 - Prob. 4.92QACh. 4 - Prob. 4.93QACh. 4 - Prob. 4.94QACh. 4 - Prob. 4.95QACh. 4 - Prob. 4.96QACh. 4 - Prob. 4.97QACh. 4 - Prob. 4.98QACh. 4 - Prob. 4.99QACh. 4 - Prob. 4.100QACh. 4 - Prob. 4.101QACh. 4 - Prob. 4.102QACh. 4 - Prob. 4.103QACh. 4 - Prob. 4.104QACh. 4 - Prob. 4.105QACh. 4 - Prob. 4.106QACh. 4 - Prob. 4.107QACh. 4 - Prob. 4.108QACh. 4 - Prob. 4.109QACh. 4 - Prob. 4.110QACh. 4 - Prob. 4.111QACh. 4 - Prob. 4.112QACh. 4 - Prob. 4.113QACh. 4 - Prob. 4.114QACh. 4 - Prob. 4.115QACh. 4 - Prob. 4.116QACh. 4 - Prob. 4.117QACh. 4 - Prob. 4.118QACh. 4 - Prob. 4.119QACh. 4 - Prob. 4.120QACh. 4 - Prob. 4.121QACh. 4 - Prob. 4.122QACh. 4 - Prob. 4.123QACh. 4 - Prob. 4.124QACh. 4 - Prob. 4.125QACh. 4 - Prob. 4.126QACh. 4 - Prob. 4.127QACh. 4 - Prob. 4.128QACh. 4 - Prob. 4.129QACh. 4 - Prob. 4.130QACh. 4 - Prob. 4.131QACh. 4 - Prob. 4.132QACh. 4 - Prob. 4.133QACh. 4 - Prob. 4.134QACh. 4 - Prob. 4.135QACh. 4 - Prob. 4.136QACh. 4 - Prob. 4.137QACh. 4 - Prob. 4.138QACh. 4 - Prob. 4.139QACh. 4 - Prob. 4.140QACh. 4 - Prob. 4.141QACh. 4 - Prob. 4.142QACh. 4 - Prob. 4.143QACh. 4 - Prob. 4.144QACh. 4 - Prob. 4.145QACh. 4 - Prob. 4.146QACh. 4 - Prob. 4.147QACh. 4 - Prob. 4.148QACh. 4 - Prob. 4.149QACh. 4 - Prob. 4.150QACh. 4 - Prob. 4.151QACh. 4 - Prob. 4.152QACh. 4 - Prob. 4.153QACh. 4 - Prob. 4.154QACh. 4 - Prob. 4.155QACh. 4 - Prob. 4.156QACh. 4 - Prob. 4.157QACh. 4 - Prob. 4.158QACh. 4 - Prob. 4.159QACh. 4 - Prob. 4.160QACh. 4 - Prob. 4.161QACh. 4 - Prob. 4.162QACh. 4 - Prob. 4.163QACh. 4 - Prob. 4.164QACh. 4 - Prob. 4.165QACh. 4 - Prob. 4.166QACh. 4 - Prob. 4.167QACh. 4 - Prob. 4.168QACh. 4 - Prob. 4.169QACh. 4 - Prob. 4.170QACh. 4 - Prob. 4.171QACh. 4 - Prob. 4.172QACh. 4 - Prob. 4.173QACh. 4 - Prob. 4.174QACh. 4 - Prob. 4.175QACh. 4 - Prob. 4.176QACh. 4 - Prob. 4.177QACh. 4 - Prob. 4.178QACh. 4 - Prob. 4.179QACh. 4 - Prob. 4.180QA
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- How do Group VIA elements form ions? A) They lose protons B) They gain two protons C) They lose two electrons D) They gain two electrons Which substance consists of anions and cations? A) CaF2, Calcium Fluoride B) Br2, Bromine C) Ag, Silver D) SiO2, Silicon Dioxide A newly discovered element is assigned to Group VIIA (Group 7A) in the periodic table. What charge will ions of this new element have? A) 1- B) 2- C) 1+ D) 2+ Reactions occur when atoms, ions or molecules collide. In a reaction between magnesium and bromine atoms, how many atoms of bromine will react per atom of magnesium? A) 1 B) 2 C) 3 D) 4 Which compound exists as a solid crystal lattice of cations and anions at room temperature? A) BrCl B) CaCl2 C) SCl2 D) SiCl4arrow_forwardome OWLV2 | Online teaching and learning resource from Cengage Learning [References] Use the References to access important values if needed for this question. The following Lewis diagram represents the valence electron configuration of a main-group element. The element in period 3 that has this valence electron congfiguration is 1A 8A H 2A 3A 4A 5A 6A 7A He Li Be B CNO F Ne Na Mg 3B 4B 5B 6B 7B 1B 2B Al Si P S CI Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg TI Pb Bi Po At Rn Fr Ra Ac Rf Ha Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa UNp Pu Am Cm Bk Cf Es Fm Md No Lrarrow_forwardHow many valence electrons does a neutral tellurium atom have?arrow_forward
- How many valence electrons are in I? 1 X Sarrow_forwardThe following Lewis diagram represents the valence electron configuration of a main-group element. If this element is in period 3, its valence electron configuration is X•arrow_forwardGive the periodic group number and number of valence electrons for each of the following atoms. (a) O (b) B (c) Na (d) Mg (e) F (f) Sarrow_forward
- 7.17 Coulombic forces are often used to explain ionic bonding. Are coulombic forces involved in covalent bonding as well? Explain.arrow_forward7.63 What physical concept forms the premise of VSEPR theory?arrow_forwardrrange the atoms and/or ions in the following groups in order of decreasing size. msp;a.O,O,O2b.Fe2+,Ni2+,Zn2+c.Ca+,K+,Clarrow_forward
- The bond length in HI(1.62) is close to the sum of the atomic radii of H (0.37 Å) and I (1.33 Å). What does this fact indicate about the polarity of the bond?arrow_forwarda The molecule HNNH exists as a transient species in certain reactions. Give the valence bond description of this species. b Hydrogen cyanide, HCN, is a very poisonous gas or liquid with the odor of bitter almonds. Give the valence bond description of HCN. (Carbon is the central atom.)arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Living By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
The Bohr Model of the atom and Atomic Emission Spectra: Atomic Structure tutorial | Crash Chemistry; Author: Crash Chemistry Academy;https://www.youtube.com/watch?v=apuWi_Fbtys;License: Standard YouTube License, CC-BY