Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Textbook Question
Chapter 4, Problem 22PDQ
Five human matings (1–5), identified by both maternal and paternal
Each mating resulted in one of the five offspring shown in the right-hand column (a–e). Match each offspring with one correct set of parents, using each parental set only once. Is there more than one set of correct answers?
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Students have asked these similar questions
What would the offspring's blood type be if the mother is type O+ (she is homozygous for Rh factor) and the father is A- (he is homozygous for type A)? Hint: You have to do two Punnett squares. The two Punnett squares must be shown to get the full points. After doing the Punnett squares, write down the possibilities of the offspring’s blood type.
The following scenario can be seen on Ch 29 Clinical case study on Heredity (27-year-old with normal pregnancy):
Mrs. Rodriguez’ blood type is type O, and her husband’s is type A. She is currently pregnant and she would like to know what type of blood her baby will have.
For discussion 7 please answer the following questions:
What are the genotype and phenotype of Mrs. Rodriguez?
What are the genotype and phenotype of Mr. Rodriguez, given that Mr. Rodriguez’s mother has O blood type and his father has A blood type? (use Punnett Square on your worksheet to find out the genotype of Mr. Rodriquez)
What is the probability that Mrs. Rodriguez’s baby will have O blood type? A? B? AB? (use Punnett Square as your worksheet)
Type O =______%
Type A = _____ %
Type B =______%
Type AB =______%
Several genes in humans in addition to the ABO gene () give rise to recognizable antigens on the surface of the red blood cells. The
Rh marker is determined by positive (R) and negative alleles () of gene R, where R is completely dominant to r. The presence of M and
N surface proteins are controlled by two codominant alleles of gene L (LM and LM. For each mother-child pair, choose the father of
the child from among the males in the right column. (Assume that all mothers and fathers are HH; there is no involvement of the
Bombay phenotype.)
Paternal genotypes maybe used once, more than once, or not at all. Each mother-child pair matches with one or more than one
paternal genotype.
Maternal phenotype:
Child phenotype:
Paternal genotype:
Reset
A, M, Rh(neg)
O, M, Rh(pos)
B, N, Rh(neg)
O, N, Rh(pos)
O, M, Rh(neg)
A, MN, Rh(pos)
A, N, Rh(pos)
AB, MN, Rh(pos)
B, N, Rh(pos)
A, MN, Rh(neg)
Genotypes of
possible fathers
AiLMLN rr
BiLMLN RR
ii LNLN rr
ii LMLM rr
AALMLN RR
Chapter 4 Solutions
Concepts of Genetics (12th Edition)
Ch. 4 - In the guinea pig, one locus involved in the...Ch. 4 - In some plants a red flower pigment, cyanidin, is...Ch. 4 - Below are three pedigrees. For each trait,...Ch. 4 - Researching their family histories, a deaf couple...Ch. 4 - Researching their family histories, a deaf couple...Ch. 4 - HOW DO WE KNOW? In this chapter, we focused on...Ch. 4 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 4 - In shorthorn cattle, coat color may be red, white,...Ch. 4 - In foxes, two alleles of a single gene, P and p,...Ch. 4 - In mice, a short-tailed mutant was discovered....
Ch. 4 - List all possible genotypes for the A, B, AB, and...Ch. 4 - With regard to the ABO blood types in humans,...Ch. 4 - In a disputed parentage case, the child is blood...Ch. 4 - The A and B antigens in humans may be found in...Ch. 4 - In chickens, a condition referred to as creeper...Ch. 4 - In rabbits, a series of multiple alleles controls...Ch. 4 - Three gene pairs located on separate autosomes...Ch. 4 - As in Problem 12, flower color may be red, white,...Ch. 4 - Horses can be cremello (a light cream color),...Ch. 4 - With reference to the eye color phenotypes...Ch. 4 - Pigment in mouse fur is only produced when the C...Ch. 4 - In rats, the following genotypes of two...Ch. 4 - Given the inheritance pattern of coat color in...Ch. 4 - In a species of the cat family, eye color can be...Ch. 4 - In a plant, a tall variety was crossed with a...Ch. 4 - In a unique species of plants, flowers may be...Ch. 4 - Five human matings (15), identified by both...Ch. 4 - A husband and wife have normal vision, although...Ch. 4 - In humans, the ABO blood type is under the control...Ch. 4 - In Drosophila, an X-linked recessive mutation,...Ch. 4 - Another recessive mutation in Drosophila, ebony...Ch. 4 - In Drosophila, the X-linked recessive mutation...Ch. 4 - While vermilion is X-linked in Drosophila and...Ch. 4 - In a cross in Drosophila involving the X-linked...Ch. 4 - Consider the three pedigrees below, all involving...Ch. 4 - In goats, the development of the beard is due to a...Ch. 4 - Predict the F1 and F2 results of crossing a male...Ch. 4 - Two mothers give birth to sons at the same time at...Ch. 4 - Discuss the topic of phenotypic expression and the...Ch. 4 - Prob. 35PDQCh. 4 - Labrador retrievers may be black, brown...Ch. 4 - A true-breeding purple-leafed plant isolated from...Ch. 4 - In Dexter and Kerry cattle, animals may be polled...Ch. 4 - A geneticist from an alien planet that prohibits...Ch. 4 - The following pedigree is characteristic of an...Ch. 4 - Students taking a genetics exam were expected to...Ch. 4 - In four oclock plants, many flower colors are...Ch. 4 - Below is a partial pedigree of hemophilia in the...
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- The mother of a family with 10 children has blood typeRh+. She also has a very rare condition (elliptocytosis,phenotype E) that causes red blood cells to be oval rather than round in shape but that produces no adverseclinical effects. The father is Rh− (lacks the Rh+ antigen)and has normal red blood cells (phenotype e). The children are 1 Rh+ e, 4 Rh+ E, and 5 Rh− e. Information isavailable on the mother’s parents, who are Rh+ E andRh− e. One of the 10 children (who is Rh+ E) marriessomeone who is Rh+ e, and they have an Rh+ E child.a. Draw the pedigree of this whole family.b. Is the pedigree in agreement with the hypothesisthat the Rh+ allele is dominant and Rh− is recessive?c. What is the mechanism of transmission ofelliptocytosis?d. Could the genes governing the E and Rh phenotypesbe on the same chromosome? If so, estimate the mapdistance between them, and comment on your resultarrow_forwardO. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S Farrow_forwardSeveral genes in humans in addition to the ABO gene(I) give rise to recognizable antigens on the surface ofred blood cells. The MN and Rh genes are two examples. The Rh locus can contain either a positive or anegative allele, with positive being dominant to negative. M and N are codominant alleles of the MN gene.The following chart shows several mothers and theirchildren. For each mother-child pair, choose the fatherof the child from among the males in the right column, assuming one child per male.Mother Child Malesa. O M Rh(pos) B MN Rh(neg) O M Rh(neg)b. B MN Rh(neg) O N Rh(neg) A M Rh(pos)c. O M Rh(pos) A M Rh(neg) O MN Rh(pos)d. AB N Rh(neg) B MN Rh(neg) B MN Rh(pos)arrow_forward
- Five human matings numbered 1–5 are shown in the followingtable. Included are both maternal and paternal phenotypes forABO and MN blood-group antigen status. Parental Phenotypes Offspring(1) A, M * A, N (a) A, N(2) B, M * B, M (b) O, N(3) O, N * B, N (c) O, MN(4) AB, M * O, N (d) B, M(5) AB, MN * AB, MN (e) B, MN Each mating resulted in one of the five offspring shown to theright (a–e). Match each offspring with one correct set of parents,using each parental set only once. Is there more than one set ofcorrect answers?arrow_forwardIn humans, four different blood types (A, B, AB, and O) are encoded by three alleles 1, 1, and i Individuals with both I and I alleles have blood type AB (red blood cells with both A and B antigens). Two copies of the i allele are required for an individual to have blood type O (red blood cells with no antigens). Which of the following correctly indicates the relationship between the I and / alleles for the blood type gene? Select one: OA. I is dominant to / OB. I is recessive to i OC. I and I are co-dominant OD. I and/exemplify incomplete dominancearrow_forwardHemophilia is determined by genes on the X chromosome in humans. Assume that a phenotypically normal woman whose father had hemophilia is married to a normal man. 1) What is the probability that their first son will have hemophilia? 2) What is the probability that their first daughter will have hemophilia?arrow_forward
- While sitting at home during Movement Control Order (MCO) because of pandemic covid19, observe two different traits of a couple in your family (eg. your mom & dad or your sister & her husband or your brother & his wife, etc). Draw a genetic cross that involves cross of the parents with the chosen 2 pairs of their contracting traits. Imagine that the cross obeys the Mendelian Laws, show the cross and gametes production for each generation (P, F1 and F2). By Using a Punnet square as symbolic representation of the results for the cross, determine the phenotypes, genotypes, phenotypic ratio and genotypic ratio of F2 generation in the family.arrow_forwardA man of blood group A is being sued by a woman of blood group B for paternity. The women’s child is blood group O. A) Is this man the father of this child? Explain. B) If this man actually is the father of this child, specify the genotypes of both parents. C.) If it was impossible for this group A man to be the father of a type O child, regardless of the mother’s genotype, specify his genotype. D.) If a man was blood group AB, could he be the father of a group O child? Why/why not?arrow_forwardA mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?arrow_forward
- A woman who has blood type A positive has a daughter who is type O positive and a son who is type B negative. Rh positive is a trait that shows simple dominance over Rh negative and is designated by the alleles R and r, respectively. A third gene for the MN blood group has codominant alleles M and N. If both children are of blood type M in addition to their ABO blood type, list all of the possible parental phenotypes for the ABO, MN and Rh traits.arrow_forwardy 301 Amelogenesis imperfecta is X-linked dominant. Affected XY individuals have extremely thin enamel on the teeth while XX carriers have grooved teeth from uneven deposition of enamel. If an unaffected XY individual were to produce children with a XX carrier partner, a. what would be the expected chance of a XY child being affected with the disease? b. what would be the expected chance of a XY child being affected with the disease?arrow_forwardIn humans, the allele for normal blood clotting, H, is dominant to the allele for hemophilia, h. The trait is X-linked. A female hemophiliac has a child with a man who is not a hemophiliac. What is the probability that this couple's child is a hemophiliac and what is the child's gender? Your response must include a Punnett square with correct nomenclature.arrow_forward
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