Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 4, Problem 18PDQ
Given the inheritance pattern of coat color in rats described in Problem 17, predict the genotype and
- (a) 9/16 gray: 3/16 yellow: 3/16 black: 1/16 cream
- (b) 9/16 gray: 3/16 yellow: 4/16 albino
- (c) 27/64 gray: 16/64 albino: 9/64 yellow: 9/64 black: 3/64 cream
- (d) 3/8 black: 3/8 cream: 2/8 albino
- (e) 3/8 black: 4/8 albino: 1/8 cream
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Students have asked these similar questions
3. 4 genes contribute to cobra length. The base (minimum) length is 6 feet for aabbccdd and the maximum
length is 14 feet for AABBCCDD. Note: no Pascal's triangle is needed for this problem.
a)
Assuming all genes act equally to each other, how much does each capital letter allele add to the
length?
b)
If you cross an AaBbCcdD cobra X an AaBBCcdd cobra, what are the minimum and maximum lengths of
the offspring (once they grow up)? Show the genotypes for the min and max.
Given the following testcross data for corn in which the genes for fine stripe (f), bronze aleurone (bz) and knotted leaf (Kn) are involved:
PhenotypeNumber
Kn + +451
Kn f +134
+ + + 97
+ f bz436
Kn + bz18
+ + bz119
+ f +24
Kn f bz86
Total:1,365
Maize geneticists tend to be like Drosophila geneticists utilizing a + to indicate the wild type allele (which also is dominant) and a lower case letter for the mutant allele (which is recessive). The first thing I suggest in attacking this problem is to use the typical convention of upper case letters for dominant alleles and lower case letters for recessive alleles as follows:
F = wild type, f = fine stripe;
B = wild type, b = bronze aleurone
K = wild type, k = knotted leaf
Then we can rewrite the phenotypes in a “language” that is more easily understood:
PhenotypeNumber
k F B451
k f B134
K F B97
K f b436
k F b18
K F b119
K f B24
k f b86
Total:1,365
a) Determine the sequence (order) of the…
A standard three-point mapping is conducted for recessive mutations in autosomal genes purple eye (pr), curved wing ( c) and black body (b). Their wild type alleles are also used for genetic mapping. An F1 Drosophila female heterozygous for purple eye (pr), curved wing (c) and black (b) is crossed to a triply homozygous mutant male. The observed numbers and phenotypes of the offspring are as follows:
360 pr c b
380 pr+ c+ b+
104 pr c+ b
96 pr+ c b+
30 pr c b+
20 pr+ c+ b
6 pr c+ b+
4 pr+ c b
PROVIDE THE FOLLOWING:
A) State the order of genes on this chromosome.
B) Calculate map distances between the gene pairs: pr-c, pr-b, c-b. Show calculations, state the number of map units and which gene pairs they refer to.
Chapter 4 Solutions
Concepts of Genetics (12th Edition)
Ch. 4 - In the guinea pig, one locus involved in the...Ch. 4 - In some plants a red flower pigment, cyanidin, is...Ch. 4 - Below are three pedigrees. For each trait,...Ch. 4 - Researching their family histories, a deaf couple...Ch. 4 - Researching their family histories, a deaf couple...Ch. 4 - HOW DO WE KNOW? In this chapter, we focused on...Ch. 4 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 4 - In shorthorn cattle, coat color may be red, white,...Ch. 4 - In foxes, two alleles of a single gene, P and p,...Ch. 4 - In mice, a short-tailed mutant was discovered....
Ch. 4 - List all possible genotypes for the A, B, AB, and...Ch. 4 - With regard to the ABO blood types in humans,...Ch. 4 - In a disputed parentage case, the child is blood...Ch. 4 - The A and B antigens in humans may be found in...Ch. 4 - In chickens, a condition referred to as creeper...Ch. 4 - In rabbits, a series of multiple alleles controls...Ch. 4 - Three gene pairs located on separate autosomes...Ch. 4 - As in Problem 12, flower color may be red, white,...Ch. 4 - Horses can be cremello (a light cream color),...Ch. 4 - With reference to the eye color phenotypes...Ch. 4 - Pigment in mouse fur is only produced when the C...Ch. 4 - In rats, the following genotypes of two...Ch. 4 - Given the inheritance pattern of coat color in...Ch. 4 - In a species of the cat family, eye color can be...Ch. 4 - In a plant, a tall variety was crossed with a...Ch. 4 - In a unique species of plants, flowers may be...Ch. 4 - Five human matings (15), identified by both...Ch. 4 - A husband and wife have normal vision, although...Ch. 4 - In humans, the ABO blood type is under the control...Ch. 4 - In Drosophila, an X-linked recessive mutation,...Ch. 4 - Another recessive mutation in Drosophila, ebony...Ch. 4 - In Drosophila, the X-linked recessive mutation...Ch. 4 - While vermilion is X-linked in Drosophila and...Ch. 4 - In a cross in Drosophila involving the X-linked...Ch. 4 - Consider the three pedigrees below, all involving...Ch. 4 - In goats, the development of the beard is due to a...Ch. 4 - Predict the F1 and F2 results of crossing a male...Ch. 4 - Two mothers give birth to sons at the same time at...Ch. 4 - Discuss the topic of phenotypic expression and the...Ch. 4 - Prob. 35PDQCh. 4 - Labrador retrievers may be black, brown...Ch. 4 - A true-breeding purple-leafed plant isolated from...Ch. 4 - In Dexter and Kerry cattle, animals may be polled...Ch. 4 - A geneticist from an alien planet that prohibits...Ch. 4 - The following pedigree is characteristic of an...Ch. 4 - Students taking a genetics exam were expected to...Ch. 4 - In four oclock plants, many flower colors are...Ch. 4 - Below is a partial pedigree of hemophilia in the...
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- The wild-type (normal) fruit fly, Drosophila melanogaster, has straight wings and long bristles. Mutant strains have been isolated that have either curled wings or short bristles. The genes representing these two mutant traits are located on separate chromosomes. Carefully examine the data from the following five crosses shown below (running across both columns). (a) Identify each mutation as either dominant or recessive. In each case, indicate which crosses support your answer. (b) Assign gene symbols and, for each cross, determine the genotypes of the parents.arrow_forwardIn a cross in Drosophila, a female heterozygous for the autosomallylinked genes a, b, c, d, and e (abcde/ + + + + +) was testcrossedwith a male homozygous for all recessive alleles (abcde/abcde).Even though the distance between each of the loci was at least3 map units, only four phenotypes were recovered, yielding thefollowing data: Phenotype No. of Flies+ + + + + 440a b c d e 460+ + + + e 48a b c d + 52 Total = 1000 Why are many expected crossover phenotypes missing? Can anyof these loci be mapped from the data given here? If so, determinemap distances.arrow_forwardYou are mapping three linked loci in Drosophila melanogaster (the common laboratory fruit fly). You cross flies that are triply mutant for apricot (pale eyes), bristle (extra bristles) and clipped (notched wings) to wild-type flies. The F+ flies are wild-type in appearance. You then backcross the F+ females to pure-breeding (apricot, bristle, clipped) males and score the phenotypes of 1000 F progeny for all three loci. Here are the results: 359 wild-type 361 apricot, bristle, clipped 89 bristle, clipped 91 apricot 42 apricot, bristle 38 clipped 9 apricot, clipped 11 bristle Using these data, first determine what gametes from the F; trihybrid produced each of the eight F2 categories. Note that apricot = aa (recessive to wild-type A); bristle = bb (recessive to wild-type B); and clipped = cc (recessive to wild-type C). Then determine if each gamete is recombinant (R) or nonrecombinant (R) for each pair of alleles (that is, for each genetic interval). Complete the table by dragging the…arrow_forward
- Albinism in humans is inherited as a simple recessive trait.Determine the genotypes of the parents and offspring for the following families. When two alternative genotypes are possible,list both.(a) Two parents without albinism have five children, four withoutalbinism and one with albinism.(b) A male without albinism and a female with albinism havesix children, all without albinism.arrow_forwardHemophilia A is caused by a sex-linked recessive gene in human and in dogs. a. What proportions (and sexes), among their offspring will be hemophiliacs if a hemophilic male is mated to a homozygous nonhemophilic female?b. If a daughter produced by the mating in (a) is mated to a normal male, what proportions and (sexes) will be hemophilic among their offspring?arrow_forwardCoat color in an elusive (and not necessarily real) mutated mongoose in Puerto Rico is governed by multiple alleles. The order of decreasing dominance for these alleles is as follows: black (B), buff, (B", brown (B') and albino (b). What phenotypic ratios are observed from a BB' X B'b cross? all brown O 2 black: 2 Brown O 1 black: 1 buff 2 black: 1 buff: 1 brown 2 brown :1 buff : 1 albino O 2 buff: 1 black: 1 albinoarrow_forward
- stion 6 of 18 Suppose that a geneticist discovers a new mutation in Drosophila melanogaster that causes the flies to shake and quiver. She calls this mutation quiver, qu, and determines that it is due to an autosomal recessive gene. She wants to determine whether the gene encoding quiver is linked to the recessive gene for vestigial wings, vg. She crosses a fly homozygous for quiver and vestigial traits with a fly homozygous for the wild-type traits, and then uses the resulting F, females in a testcross. She obtains the flies from this testcross. Phenotype Number of flies vg* qu+ 230 vg qu 224 vg qut vg* qu 97 99 Test the hypothesis that the genes quiver and vestigial assort independently by calculating the chi-squared, X², for this hypothesis. Provide the X2 to one decimal place. X2 = Does the X value support the hypothesis that the quiver and vestigial genes assort independently? Why or why not? the partial table of critical values for X2 calculations to test this hypothesis.arrow_forward3.13 In Drosophila, the mutant allele bwdts causing brown eyes (normal eyes are red) is temperature sensitive. In flies reared at 29°C the mutant allele is dominant, but in flies reared at 22°C the mutant allele is recessive. In a cross of bwdts/+ X bwdts/+, where the + sign denotes the wild-type allele of bwdts, what is the expected ratio of brown-eyed flies to red-eyed flies if the progeny are reared at 29°C? At 22°C?arrow_forwardThe following genotypes of two independently assorting autosomal genes determine coat color in rats:A-B- (gray); A-bb (yellow); aaB-(black); aabb (cream)A third gene pair on a separate autosome determines whetherany color will be produced. The CC and Cc genotypes allow coloraccording to the expression of the A and B alleles. However,the cc genotype results in albino rats regardless of the A and Balleles present. Determine the F1 phenotypic ratio of the followingcrosses: (a)AAbbCC * aaBBcc; (b) AaBBcc * AABbcc;(c) AaBbCc * AaBbcc.arrow_forward
- Three recessive mutations in Drosophila melanogaster, roughoid (ru, small rough eyes), javelin (jv, cylindrical bristles), and sepia eyes (se, dark brown eyes) are linked. A three-point cross was carried out and the following progeny obtained: jv+ ru+ se+ 37 jv+ ru+ se 2 jv+ ru se 14 jv+ ru se+ 146 jv ru se+ 2 jv ru se 35 jv ru+ se 154 jv ru+ se+ 10 a. Determine the order of the genes on the chromosome. b. Determine which progeny contain single crossovers and which contain double crossovers and indicate where among the genes the crossovers occurred. c. Calculate the map distances among the genes. d. Calculate the coefficient of coincidence and interference among the genesarrow_forwardGene mapping using the Three-point Testcross a) Given the following alleles that control seed traits:W = wrinkled G = green R = roundw = smooth g = yellow r = oval b) Results of a cross with a triple heterozygote revealed the following phenotypes:30 smooth yellow round4 smooth green round958 wrinkled green round2 wrinkled yellow oval18 wrinkled yellow round946 smooth yellow oval16 smooth green oval26 wrinkled green oval c) Determine the order of the genes and the distance between them in centiMorgan (cM).Construct a gene map to show your results. TIP: Based on the phenotypes, determine the alleles in the gametesarrow_forwardWing shape (A/a) and body color (B/b) in Drosophila are controlled by two independently assorting gene pairs. Flies with curved wings and gray body were crossed with each other and produced the following offspring: 36 curved wings, gray body 12 curved wings, black body 18 straight wings, gray body 6 straight wings, black body Questions: 1. Describe the interactions that will explain the observed phenotypic ratio. Indicate the phenotype specified by each allele, and the interaction(s) between the alleles.arrow_forward
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