Principles of Highway Engineering and Traffic Analysi (NEW!!)
6th Edition
ISBN: 9781119305026
Author: Fred L. Mannering, Scott S. Washburn
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 19P
To determine
The change in design life of the rigid pavement when the modulus of rupture is changed.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Discuss the following terms briefly:
I. Emulsion breaking and Cutback curing,
III. Flexible pavement and Rigid pavements,
VII. Breast wall and retaining wall.
4- Describe the characteristics and functions of the top layer in a pavement system.
Discuss various tests used for the quality of aggregate used in flexible pavements.
Chapter 4 Solutions
Principles of Highway Engineering and Traffic Analysi (NEW!!)
Ch. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10P
Ch. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- An agency uses the following formula to determine pavement condition rating, PCR = 99.3 − 5.51 (5.0-ROUGH) − 1.59 LNALL − 0.221 AVGOUT − 0.0306 LONG − 0.531 TRAN, where we have the following. ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile And, present serviceability rating is determined as the following. PSR = 5e−0.0051118 · IRI − 0.0016027 A pavement section has the following distress data. IRI = 108 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi Determine the current PCR for this section. PCR = Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI…arrow_forwardComparing Rigid and Flexible Airport Pavement .arrow_forwardProblem 31: Compute the pavement thickness by expansion pressure method if the expansion pressure is 0.160 kg/cm? and the average pavement density is 0.0030 kg/cm?.arrow_forward
- Give me right solution... Urgent please A 5 tonne wheel load is applied on a pavement and generates a surface deflection of 0.15 mm. A. If the pavement is 125 mm thick, what is the vertical stress at the top of the subgrade? B. If the equivalent radius of tyre contact is 100 mm and Poisson’s ratio is 0.3, what is the pavement’s modulus of elasticityarrow_forward. Say what is the main purpose of the pavement or pavement layers, and then draw the flexible pavement layers respectively.arrow_forwardWhat is the purpose of pavement structure? Discuss various layers in structure of flexible pavement in detail.arrow_forward
- Q#3. Discuss root causes and remedial measures of the following distresses occurring in flexible pavements: Slippage failure, Potholes, Rutting and its types, Bitumen bleedingarrow_forwardBriefly explain the process of constructing a pavement using roller-compacted concrete (RCC). What are the advantages and disadvantages of this method of construction?arrow_forwardAn agency uses the following formula to determine pavement condition rating, PCR = 99.3 5.51 (5.0-ROUGH) 1.59 LNALL 0.221 AVGOUT 0.0306 LONG where we have the following. ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile And, present serviceability rating is determined as the following. PSR = 5e-0.0051118 IRI-0.0016027 A pavement section has the following distress data. IRI = 106 in./mi Alligator cracking 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi Determine the current PCR for this section. PCR = 0.531 TRAN, Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi)…arrow_forward
- In 1996, a rigid pavement on a northbound section of interstate highway was designed with a 12-inch PCC slab, an Ec of 6x10^6 lb/in^2, a concrete modulus of rupture of 800 lb/in^2, a load transfer coefficient of 3.0, an initial PSI of 4.5, and a terminal serviceability index of 2.5. The overall standard deviation was 0.45, the modulus of subgrade reaction was 190 lb/in^3, and a reliability of 95% was used along with a drainage coefficient of 1.0. The pavement was designed for a 10-year life, and traffic was assumed to be composed entirely of tractor semi-trailer trucks with one 16-kip single axle, one 20-kip single axle, and one 35-kip tandem axle (the effect of all other vehicles was ignored). The interstate has four northbound lanes and was conservatively designed. How many tractor semi-trailer trucks, per day, were assumed to be traveling in the northbound direction?arrow_forwardA rigid pavement is being designed with the same parameters as used in Problem 4.5. The modulus of subgrade reaction is 300 lb/in? and the slab thickness is determined to be 8.5 inches. The load transfer coefficient is 3.0, the drainage coefficient is 1.0, and the modulus of elasticity is 4 million 1b/in?. What is the design modulus of rupture? (Assume that any parameters not given in this problem are the same as those given in Problem 4.5.) 4.5 for reference: A flexible pavement was designed for the following daily traffic with a 12-year design life: 1300 single axles at 8000 Ib each, 900 tandem axles at 15,000 1b each, 20 single axles at 40,000 Ib each, and200 tandem axles at 40,000 lb each. The highway was designed with 4 inches of HMA wearing surface,arrow_forwardProblem 1: Make a diagram showing the comparison between Flexible and Rigid Pavement. Categorize the comparison based on the type and number of layers, materials used, design input data, suitability, durability etc. Note: For reference use AASHTOarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Traffic and Highway EngineeringCivil EngineeringISBN:9781305156241Author:Garber, Nicholas J.Publisher:Cengage Learning
Traffic and Highway Engineering
Civil Engineering
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Cengage Learning