Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 4, Problem 12PDQ
In goals, development of the beard is due to a recessive gene. The following cross involving true-breeding goats was made and carried to the F2 generation:
Offer an explanation for the inheritance and expression of this trait, diagramming the cross. Propose one or more crosses to test your hypothesis.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Using the following information perform following crosses using the forked line and predict all possible phenotypes types of the offspring. List the number and description of the phenotypes of the offspring. 1. aa BB Cc Dd Ee X aa bb Cc Dd EE 2. Ff Rr Gg dd Bb X Ff RR Gg Dd Bb 3. Dd gg JJ bb Hh Ee X DD GG Jj Bb Hh Ee
Some mice are born with a yellow coat controlled by the gene Y. Examine the
setup and outcome of the following crosses, which produce two generations:
Po: yellow mouse X gray mouse F1 :5 yellow mice, 4 gray mice
P: yellow mouse from F1 X yellow mouse from F1 F2 : 7 gray mice, 15 yellow
mice with 9 dead
Analyze the information provided to answer these questions:
• What type of cross is the first cross?
• Which trait is dominant?
• What is the genotype of the yellow mouse in the first cross?
• What is the genotype of the gray mouse in the second cross?
Why are 9 mice dead in F2?
Consider two blood polymorphisms that humans have in addition to the ABO system. Two alleles LM and LN determine the M, N, and MN blood groups. The dominant allele R of a different gene causes a person to have the Rh+ (rhesus positive) phenotype, whereas the homozygote for r is Rh− (rhesus negative). Two men took a paternity dispute to court, each claiming three children to be his own. The blood groups of the men, the children, and their mother were as follows:From this evidence, can the paternity of the children be established?
Chapter 4 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 4 - CASE STUDY | But he isn't deaf Researching their...Ch. 4 -
CASE STUDY | But he isn’t deaf
Researching...Ch. 4 - CASE STUDY | But he isn't deaf Researching their...Ch. 4 - HOW DO WE KNOW? In this chapter, we focused on...Ch. 4 - Review the Chapter Concepts list on page 53. These...Ch. 4 - In Shorthorn cattle, coat color may be red, white,...Ch. 4 -
4. With regard to the ABO blood types in humans,...Ch. 4 - In foxes, two alleles of a single gene, P and p,...Ch. 4 - Three gene pairs located on separate autosomes...Ch. 4 - As in the plants of Problem 6, color may be red,...
Ch. 4 -
8. The following genotypes of two independently...Ch. 4 - Given the inheritance pattern of coat color in...Ch. 4 - A husband and wife have normal vision, although...Ch. 4 - In humans, the ABO blood type is under the control...Ch. 4 - In goals, development of the beard is due to a...Ch. 4 -
13. In cats, orange coal color is determined by...Ch. 4 - In Drosophila, an X-linked recessive mutation,...Ch. 4 - Another recessive mutation in Drosophila, ebony...Ch. 4 - While vermilion is X-linked in Drosophila and...Ch. 4 - In pigs, coat color may be sandy, red, or white. A...Ch. 4 - A geneticist from an alien planet that prohibits...Ch. 4 - In another cross, the frog geneticist from Problem...Ch. 4 - In cattle, coats may be solid white, solid black,...Ch. 4 - Consider the following three pedigrees, all...Ch. 4 - Labrador retrievers may be black, brown, or golden...Ch. 4 - Three autosomal recessive mutations in Drosophila,...Ch. 4 -
24. Horses can be cremello (a light cream...Ch. 4 - Pigment in the mouse is produced only when the C...Ch. 4 - Five human matings numbered 1–5 are shown in the...Ch. 4 - Two mothers give birth to sons at the same time at...Ch. 4 - In Dexter and Kerry cattle, animals may be polled...Ch. 4 - What genetic criteria distinguish a case of...Ch. 4 -
30. The specification of the anterior-posterior...Ch. 4 - The maternal-effect mutation bicoid(bcd)is...Ch. 4 -
32. Students taking a genetics exam were...Ch. 4 - In four o'clock plants, many flower colors are...Ch. 4 - Prob. 34PDQ
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?arrow_forwardThe color of Andalusian chickens results from the inheritance of alleles that exhibit incomplete dominance. Black chickens result when 2 alleles for melanin production are inherited (MM). White splashed chickens result from the inheritance of 2 copies of a different allele (mm). The heterozygous condition (Mm) results in their famous bluish color. Predict the genotypes and phenotypes from the following crosses: MM x mm x Mm x Mm.arrow_forwardFinish these crosses below:(assume all parents are homozygous for alleles) Cross 1:These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be?arrow_forward
- a. State a hypothesis explaining the inheritance of flower color in painted tongues. b. Assign genotypes to the parents, F₁ progeny, and F2 progeny for all five crosses. c. In a cross between true-breeding yellow and true-breeding lavender plants, all of the F1 progeny are bronze. If you used F₁ plants to produce and F2 generation, what phenotypes in what ratios would you expect? Are there any genotypes that might produce a phenotype that you cannot predict from earlier experiments, and if so, how might this alter the phenotypic ratios among the F2 progeny?arrow_forwardFinish these crosses below:(assume all parents are homozygous for alleles) Cross 1: These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be? Cross 2: These are the parents: Vestigial Wings, Wild Type Body Male; Wild Type Wings and Ebony Body Female What are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be? Cross 3: These are the parents: Wild Type Male; White Eye Female What are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios.…arrow_forwardA geneticist crosses two yellow mice with straight hair and obtains the following progeny: 1/2 yellow, straight 1/6 yellow, fuzzy 1/4 gray, straight 1/12 gray, fuzzy Provide a genetic explanation for the results and assign genotypes to the parents and progeny of this cross. What additional crosses might be carried out to determine if your explanation is correct? Hint: consider lethality of a homozygous recessive traitarrow_forward
- An ebony strain of flies was discovered to be sensitive to carbon dioxide. Crossing a female sensitive strain with male resistant strain gave all sensitive offspring. The offspring of an F1 female crossed with a resistant male were all sensitive. Using the following key to your illustrations using shapes, make a reciprocal cross up to the F2 generation. Put your illustrations in the space provided below. Label the phenotypes of all individuals in the reciprocal cross. Adjust spacing, if necessary. Make sure that the complete cross(es) can fit the same page. Big blue circle - male cytoplasm Big pink circle - female cytoplasm Small half-blue-half-pink circle - F1 nucleus Small blue circle - male nucleus Small pink circle - female nucleus give a diagram pleasearrow_forwardAn ebony strain of flies was discovered to be sensitive to carbon dioxide. Crossing a female sensitive strain with male resistant strain gave all sensitive offspring. The offspring of an F1 female crossed with a resistant male were all sensitive. Using the following key to your illustrations using shapes, make a reciprocal cross up to the F2 generation. Put your illustrations in the space provided below. Label the phenotypes of all individuals in the reciprocal cross. Adjust spacing, if necessary. Make sure that the complete cross(es) can fit the same page. Big blue circle - male cytoplasm Big pink circle - female cytoplasm Small half-blue-half-pink circle - F1 nucleus Small blue circle - male nucleus Small pink circle - female nucleusarrow_forwardWhen crossing a true breeding white mouse with a true breeding brown mouse your friend tells you she recovered all black mice. But then when she crosses the F1 mice to each other she recovered 28 black mice, 8 brown mice, and 13 white mice. Can you help her explain these results? (Type out the cross and include genotypes of as many mice as possible. What phrase best describes this phenomenon? How many genes are involved are they linked or unlinked? Etc.)arrow_forward
- Scenario A In goats, black fur is dominant to red fur. The gene for this trait can be described as Bb (if you forgot why this is so, go back and reread the background information at the beginning of this exercise). A homozygous black female goat (nanny) is crossed with a heterozygous male (billy). What is the genotype of the billy? What is the phenotype of the billy?arrow_forwardIn goats, black fur is dominant to red fur. The gene for this trait can be described as Bb (if you forgot why this is so, go back and reread the background information at the beginning of this exercise). A homozygous black female goat (nanny) is crossed with a heterozygous male (billy). What is the probability of this cross producing a black kid (baby goat) that is homozygous for this trait? Record your answer as a percentage. _____arrow_forwardTallness (T) in a certain plant is dominant to short (t), while red (R) flower color is dominant to yellow (r). The heterozygous condition results in orange (Rr) flower color. A short plant with red flowers, is crossed with a plant homozygous for tallness and yellow flowers. What would be the genotype and phenotype of the F1 individuals? ttRr—short and orange ttrr—short and yellow TtRr—tall and red Ttrr—tall and yellow TtRr—tall and orangearrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY