Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 3.3, Problem 42SP
Interpretation Introduction

Interpretation : The expression of 15cm3 to litres is to be converted.

Concept Introduction : A conversion factor is a ratio of equivalent measurements. Dimensional analysis is a useful method for resolving conversion problems where measurements in one unit are changed to equal measurements in another.

Expert Solution
Check Mark

Answer to Problem 42SP

The expression of 15cm3 is 1.5×102L .

Explanation of Solution

Given information :

The given expression is 15cm3 .

It is known that 1L=103cm3 .

An equivalent measurement ratio is referred to as a conversion factor. An effective approach for resolving conversion problems where measurement in one unit is changed to an equivalent measurement in another is dimensional analysis.

The desired conversion is cm3L .

The conversion of the expression is given as

  15cm3=15cm3×103L1cm31L=103cm3=1.5×102L

Interpretation Introduction

Interpretation : The expression of 7.38g to kilograms is to be converted.

Concept Introduction : A conversion factor is a ratio of equivalent measurements. Dimensional analysis is a useful method for resolving conversion problems where measurements in one unit are changed to equal measurements in another.

Expert Solution
Check Mark

Answer to Problem 42SP

The expression of 7.38g is 7.38×103kg .

Explanation of Solution

Given information :

The given expression is 7.38g .

It is known that 1kg=103g .

An equivalent measurement ratio is referred to as a conversion factor. An effective approach for resolving conversion problems where measurement in one unit is changed to an equivalent measurement in another is dimensional analysis.

The desired conversion is gkg .

The conversion of the expression is given as

  7.38g=7.38g×103kg1g1kg=103g=7.38×103kg

Interpretation Introduction

Interpretation : The expression of 6.7s to millisecond is to be converted.

Concept Introduction : A conversion factor is a ratio of equivalent measurements. Dimensional analysis is a useful method for resolving conversion problems where measurements in one unit are changed to equal measurements in another.

Expert Solution
Check Mark

Answer to Problem 42SP

The expression of 6.7s is 6.7×103ms .

Explanation of Solution

Given information :

The given expression is 6.7s .

It is known that 1s=103ms .

An equivalent measurement ratio is referred to as a conversion factor. An effective approach for resolving conversion problems where measurement in one unit is changed to an equivalent measurement in another is dimensional analysis.

The desired conversion is sms .

The conversion of the expression is given as

  6.7s=6.7s×103ms1s1s=103ms=6.7×103ms

Interpretation Introduction

Interpretation : The expression of 94.5g to micrograms is to be converted.

Concept Introduction : A conversion factor is a ratio of equivalent measurements. Dimensional analysis is a useful method for resolving conversion problems where measurements in one unit are changed to equal measurements in another.

Expert Solution
Check Mark

Answer to Problem 42SP

The expression of 94.5g is 9.45×107μg .

Explanation of Solution

Given information :

The given expression is 94.5g .

It is known that 1g=106μg .

A conversion factor is a ratio of equivalent measurements. Dimensional analysis is a useful method for resolving conversion problems where measurements in one unit are changed to equal measurements in another.

The desired conversion is gμg .

The conversion of the expression is given as

  94.5g=94.5g×106μg1g1g=106μg=9.45×107μg

Chapter 3 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 3.1 - Prob. 11SPCh. 3.1 - Prob. 12LCCh. 3.1 - Prob. 13LCCh. 3.1 - Prob. 14LCCh. 3.1 - Prob. 15LCCh. 3.1 - Prob. 16LCCh. 3.1 - Prob. 17LCCh. 3.1 - Prob. 18LCCh. 3.2 - Prob. 19SPCh. 3.2 - Prob. 20SPCh. 3.2 - Prob. 21SPCh. 3.2 - Prob. 22SPCh. 3.2 - Prob. 23LCCh. 3.2 - Prob. 24LCCh. 3.2 - Prob. 25LCCh. 3.2 - Prob. 26LCCh. 3.2 - Prob. 27LCCh. 3.2 - Prob. 28LCCh. 3.2 - Prob. 29LCCh. 3.2 - Prob. 30LCCh. 3.2 - Prob. 31LCCh. 3.2 - Prob. 32LCCh. 3.2 - Prob. 33LCCh. 3.2 - Prob. 34LCCh. 3.2 - Prob. 35LCCh. 3.3 - Prob. 36SPCh. 3.3 - Prob. 37SPCh. 3.3 - Prob. 38SPCh. 3.3 - Prob. 39SPCh. 3.3 - Prob. 40SPCh. 3.3 - Prob. 41SPCh. 3.3 - Prob. 42SPCh. 3.3 - Prob. 43SPCh. 3.3 - Prob. 44SPCh. 3.3 - Prob. 45SPCh. 3.3 - Prob. 46SPCh. 3.3 - Prob. 47SPCh. 3.3 - Prob. 48SPCh. 3.3 - Prob. 49SPCh. 3.3 - Prob. 50LCCh. 3.3 - Prob. 51LCCh. 3.3 - Prob. 52LCCh. 3.3 - Prob. 53LCCh. 3.3 - Prob. 54LCCh. 3.3 - Prob. 55LCCh. 3 - Prob. 56ACh. 3 - Prob. 57ACh. 3 - Prob. 58ACh. 3 - Prob. 59ACh. 3 - Prob. 60ACh. 3 - Prob. 61ACh. 3 - Prob. 62ACh. 3 - Prob. 63ACh. 3 - Prob. 65ACh. 3 - Prob. 66ACh. 3 - Prob. 67ACh. 3 - Prob. 68ACh. 3 - Prob. 69ACh. 3 - Prob. 70ACh. 3 - Prob. 71ACh. 3 - Prob. 72ACh. 3 - Prob. 73ACh. 3 - Prob. 74ACh. 3 - Prob. 75ACh. 3 - Prob. 76ACh. 3 - Prob. 77ACh. 3 - Prob. 78ACh. 3 - Prob. 79ACh. 3 - Prob. 80ACh. 3 - Prob. 81ACh. 3 - Prob. 82ACh. 3 - Prob. 83ACh. 3 - Prob. 84ACh. 3 - Prob. 85ACh. 3 - Prob. 86ACh. 3 - Prob. 87ACh. 3 - Prob. 88ACh. 3 - Prob. 89ACh. 3 - Prob. 90ACh. 3 - Prob. 91ACh. 3 - Prob. 92ACh. 3 - Prob. 93ACh. 3 - Prob. 94ACh. 3 - Prob. 95ACh. 3 - Prob. 96ACh. 3 - Prob. 97ACh. 3 - Prob. 98ACh. 3 - Prob. 99ACh. 3 - Prob. 100ACh. 3 - Prob. 101ACh. 3 - Prob. 102ACh. 3 - Prob. 103ACh. 3 - Prob. 104ACh. 3 - Prob. 105ACh. 3 - Prob. 106ACh. 3 - Prob. 107ACh. 3 - Prob. 108ACh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STPCh. 3 - Prob. 11STPCh. 3 - Prob. 12STP
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