Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 3.1, Problem 7SP

a)

Interpretation Introduction

Interpretation : The answers in scientific notation are to be written.

Concept Introduction : A given number is stated as the product of two numbers in scientific notation: a coefficient and 10 raised to a power. Round the number to one significant figure in the measurement.

a)

Expert Solution
Check Mark

Answer to Problem 7SP

The answer in scientific notation is 9×101meters .

Explanation of Solution

The known digits plus the last, estimated digit make up the significant figures in a measurement.

There is a set of rules to detect the digits in a significant measured value.

Round the number to one significant figure in the measurement.

If the 2nd digit number is greater than or equal to 5, then the 1st digit is added up by number 1 while leaving the remaining digit after the 2nd digit. If the 2nd digit number is lesser than 5, then the values till the 1st digit are alone taken up.

The answer obtained is 8.7×101 meters .

The scientific notation is given as

  8.7×101 meters=9×101meters

b)

Interpretation Introduction

Interpretation : The answers in scientific notation are to be written.

Concept Introduction : A given number is stated as the product of two numbers in scientific notation: a coefficient and 10 raised to a power. Round the number to one significant figure in the measurement.

b)

Expert Solution
Check Mark

Answer to Problem 7SP

The answer in scientific notation is 4×108 meters .

Explanation of Solution

The known digits plus the last, estimated digit make up the significant figures in a measurement.

There is a set of rules to detect the digits in a significant measured value.

Round the number to one significant figure in the measurement.

The known digits plus the last, estimated digit make up the significant figures in a measurement.

There is a set of rules to detect the digits in a significant measured value.

Round the number to three significant figures in the measurement.

If the 2nd digit number is greater than or equal to 5, then the 1st digit is added up by number 1 while leaving the remaining digit after the 2nd digit. If the 2nd digit number is lesser than 5, then the values till the 1st digit are alone taken up.

The answer obtained is 4.36×108 meters .

The scientific notation is given as

  4.36×108 meters=4×108 meters

c)

Interpretation Introduction

Interpretation : The answers in scientific notation are to be written.

Concept Introduction : A given number is stated as the product of two numbers in scientific notation: a coefficient and 10 raised to a power. Round the number to one significant figure in the measurement.

c)

Expert Solution
Check Mark

Answer to Problem 7SP

The answer in scientific notation is 2×102 meters .

Explanation of Solution

The known digits plus the last, estimated digit make up the significant figures in a measurement.

There is a set of rules to detect the digits in a significant measured value.

Round the number to one significant figure in the measurement.

If the 2nd digit number is greater than or equal to 5, then the 1st digit is added up by number 1 while leaving the remaining digit after the 2nd digit. If the 2nd digit number is lesser than 5, then the values till the 1st digit are alone taken up.

The answer obtained is 1.6×102 meters .

The scientific notation is given as

  1.6×102 meters=2×102 meters

d)

Interpretation Introduction

Interpretation : The answers in scientific notation are to be written.

Concept Introduction : A given number is stated as the product of two numbers in scientific notation: a coefficient and 10 raised to a power. Round the number to one significant figure in the measurement.

d)

Expert Solution
Check Mark

Answer to Problem 7SP

The answer in scientific notation is 9×103 meters .

Explanation of Solution

The known digits plus the last, estimated digit make up the significant figures in a measurement.

There is a set of rules to detect the digits in a significant measured value.

Round the number to one significant figure in the measurement.

If the 2nd digit number is greater than or equal to 5, then the 1st digit is added up by number 1 while leaving the remaining digit after the 2nd digit. If the 2nd digit number is lesser than 5, then the values till the 1st digit are alone taken up.

The answer obtained is 9.01×103 meters .

The scientific notation is given as

  9.01×103 meters=9×103 meters

e)

Interpretation Introduction

Interpretation : The answers in scientific notation are to be written.

Concept Introduction : A given number is stated as the product of two numbers in scientific notation: a coefficient and 10 raised to a power. Round the number to one significant figure in the measurement.

e)

Expert Solution
Check Mark

Answer to Problem 7SP

The answer in scientific notation is 2×103 meters .

Explanation of Solution

The known digits plus the last, estimated digit make up the significant figures in a measurement.

There is a set of rules to detect the digits in a significant measured value.

Round the number to one significant figure in the measurement.

If the 2nd digit number is greater than or equal to 5, then the 1st digit is added up by number 1 while leaving the remaining digit after the 2nd digit. If the 2nd digit number is lesser than 5, then the values till the 1st digit are alone taken up.

The answer obtained is 1.78×103 meters .

The scientific notation is given as

  1.78×103 meters=2×103 meters

f)

Interpretation Introduction

Interpretation : The answers in scientific notation are to be written.

Concept Introduction : A given number is stated as the product of two numbers in scientific notation: a coefficient and 10 raised to a power. Round the number to one significant figure in the measurement.

f)

Expert Solution
Check Mark

Answer to Problem 7SP

The answer in scientific notation is 6×102 meters .

Explanation of Solution

The known digits plus the last, estimated digit make up the significant figures in a measurement.

There is a set of rules to detect the digits in a significant measured value.

Round the number to one significant figure in the measurement.

If the 2nd digit number is greater than or equal to 5, then the 1st digit is added up by number 1 while leaving the remaining digit after the 2nd digit. If the 2nd digit number is lesser than 5, then the values till the 1st digit are alone taken up.

The answer obtained is 6.30×102 meters .

The scientific notation is given as

  6.30×102 meters= 6×102meters

Chapter 3 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 3.1 - Prob. 11SPCh. 3.1 - Prob. 12LCCh. 3.1 - Prob. 13LCCh. 3.1 - Prob. 14LCCh. 3.1 - Prob. 15LCCh. 3.1 - Prob. 16LCCh. 3.1 - Prob. 17LCCh. 3.1 - Prob. 18LCCh. 3.2 - Prob. 19SPCh. 3.2 - Prob. 20SPCh. 3.2 - Prob. 21SPCh. 3.2 - Prob. 22SPCh. 3.2 - Prob. 23LCCh. 3.2 - Prob. 24LCCh. 3.2 - Prob. 25LCCh. 3.2 - Prob. 26LCCh. 3.2 - Prob. 27LCCh. 3.2 - Prob. 28LCCh. 3.2 - Prob. 29LCCh. 3.2 - Prob. 30LCCh. 3.2 - Prob. 31LCCh. 3.2 - Prob. 32LCCh. 3.2 - Prob. 33LCCh. 3.2 - Prob. 34LCCh. 3.2 - Prob. 35LCCh. 3.3 - Prob. 36SPCh. 3.3 - Prob. 37SPCh. 3.3 - Prob. 38SPCh. 3.3 - Prob. 39SPCh. 3.3 - Prob. 40SPCh. 3.3 - Prob. 41SPCh. 3.3 - Prob. 42SPCh. 3.3 - Prob. 43SPCh. 3.3 - Prob. 44SPCh. 3.3 - Prob. 45SPCh. 3.3 - Prob. 46SPCh. 3.3 - Prob. 47SPCh. 3.3 - Prob. 48SPCh. 3.3 - Prob. 49SPCh. 3.3 - Prob. 50LCCh. 3.3 - Prob. 51LCCh. 3.3 - Prob. 52LCCh. 3.3 - Prob. 53LCCh. 3.3 - Prob. 54LCCh. 3.3 - Prob. 55LCCh. 3 - Prob. 56ACh. 3 - Prob. 57ACh. 3 - Prob. 58ACh. 3 - Prob. 59ACh. 3 - Prob. 60ACh. 3 - Prob. 61ACh. 3 - Prob. 62ACh. 3 - Prob. 63ACh. 3 - Prob. 65ACh. 3 - Prob. 66ACh. 3 - Prob. 67ACh. 3 - Prob. 68ACh. 3 - Prob. 69ACh. 3 - Prob. 70ACh. 3 - Prob. 71ACh. 3 - Prob. 72ACh. 3 - Prob. 73ACh. 3 - Prob. 74ACh. 3 - Prob. 75ACh. 3 - Prob. 76ACh. 3 - Prob. 77ACh. 3 - Prob. 78ACh. 3 - Prob. 79ACh. 3 - Prob. 80ACh. 3 - Prob. 81ACh. 3 - Prob. 82ACh. 3 - Prob. 83ACh. 3 - Prob. 84ACh. 3 - Prob. 85ACh. 3 - Prob. 86ACh. 3 - Prob. 87ACh. 3 - Prob. 88ACh. 3 - Prob. 89ACh. 3 - Prob. 90ACh. 3 - Prob. 91ACh. 3 - Prob. 92ACh. 3 - Prob. 93ACh. 3 - Prob. 94ACh. 3 - Prob. 95ACh. 3 - Prob. 96ACh. 3 - Prob. 97ACh. 3 - Prob. 98ACh. 3 - Prob. 99ACh. 3 - Prob. 100ACh. 3 - Prob. 101ACh. 3 - Prob. 102ACh. 3 - Prob. 103ACh. 3 - Prob. 104ACh. 3 - Prob. 105ACh. 3 - Prob. 106ACh. 3 - Prob. 107ACh. 3 - Prob. 108ACh. 3 - Prob. 1STPCh. 3 - Prob. 2STPCh. 3 - Prob. 3STPCh. 3 - Prob. 4STPCh. 3 - Prob. 5STPCh. 3 - Prob. 6STPCh. 3 - Prob. 7STPCh. 3 - Prob. 8STPCh. 3 - Prob. 9STPCh. 3 - Prob. 10STPCh. 3 - Prob. 11STPCh. 3 - Prob. 12STP
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