Explanation Given info: The wavelength of the light for which Rhodopsin is sensitive is 500 nm . The frequency of the light for Rhosopsin is, ν = c λ Here, c is the speed of the light. λ is the wavelength of the light. The speed of the light is 3 × 10 8 m / s . Substitute 3 × 10 8 m / s for c and 500 nm for λ in the above equation. ν = 3 × 10 8 m / s 500 nm ( 10 − 9 Ȁ

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ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Chapter 30, Problem 99PP

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Whether the light of wavelength 500 nm have a higher, lower or same frequency as the peak frequency of the vent radiation.

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Chapter 30, Problem 98PP

Chapter 30, Problem 100PP

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Chapter 30 Solutions

Physics (5th Edition)

Ch. 30.1 - Prob. 1EYU Ch. 30.2 - Prob. 2EYU Ch. 30.3 - Prob. 3EYU Ch. 30.4 - Prob. 4EYU Ch. 30.5 - Prob. 5EYU Ch. 30.6 - Prob. 6EYU Ch. 30.7 - Prob. 7EYU Ch. 30 - Prob. 1CQ Ch. 30 - Prob. 2CQ Ch. 30 - Prob. 3CQ

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Whether the light of wavelength 500 nm have a higher, lower or same frequency as the peak frequency of the vent radiation .

Solution Summary: The author explains that the light of wavelength 500nm has a higher frequency than the peak frequency of the vent radiation.

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Whether the light of wavelength 500 nm have a higher, lower or same frequency as the peak frequency of the vent radiation.

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Chapter 30 Solutions