Physics (5th Edition)
5th Edition
ISBN: 9780321976444
Author: James S. Walker
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 30, Problem 25PCE
(a)
To determine
The frequency and wavelength of photon.
(b)
To determine
The region of photon in the electromagnetic spectrum that found in part (a).
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Determine the Debye temperature, Debye wavelength and Debye frequency for diamond given:
a=3.56 Angstroms
ρ=3.52 g/cm3
v0=12000 m/s
a) A monochromator is used as shown in the setup below to obtain a single wavelength λ = 1.5 Å X-ray from X-rays emanating from an X-ray source. The monochromator is made of Germanium single crystal. This is the Miller index (111) of the planes in the Germanium single crystal and the distance between the planes is d111 = 1.2 Å. What is the value of the monochromator angle θ ?
b) Calculate the energy of the X-ray with wavelength λ = 1.5 Å in eV.
Nanotechnology. Calculate the X - ray angle for Si ( 111 ) and ( 200 ) peak , giving the lattice parameter of Si is 5.43A and X - ray wavelength is 1.54A ( Cu Ka ) C )
Chapter 30 Solutions
Physics (5th Edition)
Ch. 30.1 - Prob. 1EYUCh. 30.2 - Prob. 2EYUCh. 30.3 - Prob. 3EYUCh. 30.4 - Prob. 4EYUCh. 30.5 - Prob. 5EYUCh. 30.6 - Prob. 6EYUCh. 30.7 - Prob. 7EYUCh. 30 - Prob. 1CQCh. 30 - Prob. 2CQCh. 30 - Prob. 3CQ
Ch. 30 - Prob. 4CQCh. 30 - Prob. 5CQCh. 30 - Prob. 6CQCh. 30 - Prob. 7CQCh. 30 - Prob. 8CQCh. 30 - Prob. 9CQCh. 30 - Prob. 10CQCh. 30 - Prob. 1PCECh. 30 - Prob. 2PCECh. 30 - Prob. 3PCECh. 30 - The Sun has a surface temperature of about 5800 K....Ch. 30 - Prob. 5PCECh. 30 - Prob. 6PCECh. 30 - (a) By what factor does the peak frequency change...Ch. 30 - Prob. 8PCECh. 30 - Prob. 9PCECh. 30 - Prob. 10PCECh. 30 - Prob. 11PCECh. 30 - Prob. 12PCECh. 30 - Prob. 13PCECh. 30 - Prob. 14PCECh. 30 - Prob. 15PCECh. 30 - Prob. 16PCECh. 30 - Prob. 17PCECh. 30 - Prob. 18PCECh. 30 - Prob. 19PCECh. 30 - Prob. 20PCECh. 30 - Prob. 21PCECh. 30 - Prob. 22PCECh. 30 - Prob. 23PCECh. 30 - Prob. 24PCECh. 30 - Prob. 25PCECh. 30 - Prob. 26PCECh. 30 - Prob. 27PCECh. 30 - Prob. 28PCECh. 30 - Prob. 29PCECh. 30 - Prob. 30PCECh. 30 - Prob. 31PCECh. 30 - Prob. 32PCECh. 30 - Prob. 33PCECh. 30 - Prob. 34PCECh. 30 - Prob. 35PCECh. 30 - BIO Owl Vision Owls have large, sensitive eyes for...Ch. 30 - Prob. 37PCECh. 30 - Prob. 38PCECh. 30 - Prob. 39PCECh. 30 - Prob. 40PCECh. 30 - Prob. 41PCECh. 30 - Prob. 42PCECh. 30 - Prob. 43PCECh. 30 - Prob. 44PCECh. 30 - Prob. 45PCECh. 30 - Prob. 46PCECh. 30 - Prob. 47PCECh. 30 - Prob. 48PCECh. 30 - Prob. 49PCECh. 30 - Prob. 50PCECh. 30 - Prob. 51PCECh. 30 - Prob. 52PCECh. 30 - Prob. 53PCECh. 30 - Prob. 54PCECh. 30 - Prob. 55PCECh. 30 - Prob. 56PCECh. 30 - Prob. 57PCECh. 30 - Prob. 58PCECh. 30 - Prob. 59PCECh. 30 - Prob. 60PCECh. 30 - Prob. 61PCECh. 30 - Prob. 62PCECh. 30 - Prob. 63PCECh. 30 - Prob. 64PCECh. 30 - Prob. 65PCECh. 30 - Prob. 66PCECh. 30 - Prob. 67PCECh. 30 - Prob. 68PCECh. 30 - Prob. 69PCECh. 30 - Prob. 70PCECh. 30 - Prob. 71PCECh. 30 - Prob. 72PCECh. 30 - Prob. 73PCECh. 30 - Prob. 74PCECh. 30 - Prob. 75PCECh. 30 - Prob. 76PCECh. 30 - Prob. 77PCECh. 30 - Prob. 78PCECh. 30 - Prob. 79PCECh. 30 - Prob. 80GPCh. 30 - Prob. 81GPCh. 30 - Prob. 82GPCh. 30 - Prob. 83GPCh. 30 - Prob. 84GPCh. 30 - Prob. 85GPCh. 30 - Prob. 86GPCh. 30 - Prob. 87GPCh. 30 - Prob. 88GPCh. 30 - Prob. 89GPCh. 30 - Prob. 90GPCh. 30 - Prob. 91GPCh. 30 - Prob. 92GPCh. 30 - Prob. 93GPCh. 30 - Prob. 94GPCh. 30 - Prob. 95GPCh. 30 - Prob. 96GPCh. 30 - Prob. 97PPCh. 30 - Prob. 98PPCh. 30 - Prob. 99PPCh. 30 - Prob. 100PPCh. 30 - Prob. 101PPCh. 30 - Prob. 102PP
Knowledge Booster
Similar questions
- (a) A simplified parabolic E-K diagram for an electron in the conduction band is given in Figure 3. Determine the relative effective mass, m'/m.. given the E – E. = C,k², value of a of 1 nm, Planck constant h = 6.625 × 10-34 J. s, free electron mass m, = 9.11 x 10-31 kg, electric charge q = 1.6 x 10-19 C and 1 eV = 1.6 x 10-19 J. E E = E,+0.32 eV Figure 3arrow_forwardHe-Ne laser produces light of wavelength 6328Angstrom at room temperature a) The energy difference between two energy levels emitting this radiation in eV is? b) Why the discharge tube is taken narrow? option 1- for effective collision option-2 for resonance option 3 for pumping option 4 for population inversion c) which type of laser is He-Ne laser option 1- two level option-2 three level option 3 four level option 4 involve bands d) The energy difference between two energy levels emitting this radiation in Joule is? e) The frequency of emitted radiation is?arrow_forwardAn extremely crude picture of a valence electron in an atom or a molecule treats it as a particle in a one-dimensional box whose length is on the order of the size of atoms and molecules. For an electron in a one-dimensional box of length 1.0 A; calculate the separation between the two lowest energy levels. Calculate the wavelength of a photon corresponding to a transition between these two levels. In what portion of the electromagnetic spectrum is this wavelength?arrow_forward
- 1) The temperature of the absorber plate of a flat plate collector is 102 degrees * C and an be accepted as a black body. What percent of the radiant energy comes from this ate in the long wavelength band gap of 8 um to 11 um?arrow_forwardPlease provide a structure consistent with the following IR, 13 C NMR, and 1 H NMR spectra. Assign at least 2 bands in the IR and assign ALL protons in the 1 H/ 13 C NMR spectrumarrow_forwardFor inorganic LED emitting shorter wavelength (say blue) light, it typically also comes with narrower spectral width, and vice versa. Why is that? Gives your understanding.arrow_forward
- Diatomic line. Consider a line of atoms ABAB... AB, with an A-B bond lengtlh of sa. The form factors are fa» fp for atoms A, B, respectively. The incident beam of X-rays is perpendicular to the line of atoms. (a) Show that the interference condition is nd = a cos 0, where 0 is the angle between the diffracted beam and the line of atoms. (b) Show that the intensity of the diffracted beam is proportional to |f, - fB° for n odd, and to |f, + frl° for n even. (c) Explain what happens if fa = fB-arrow_forwardIn X-ray fluorescence (XRF), the energy of the characteristic Ka line of iron (Fe) is 6.405 keV. Calculate the wavelength (in Å) corresponding to this line and state what electronic transition this represents. (DATA: h = 6.626 x 10-34 J s; c = 2.998 x 108 m s-1; e = 1.602 x 10-19 C)arrow_forwarda) The bandwidth of silicon is 1.12 eV. Photon that can create a hole-electron pair in silicon Calculate the maximum value the wavelength can take. Photon energy-wave for silicon by drawing the graph showing the relationship between the length of the energy can be benefited and Indicate the parts that cannot be used with the reasons. b) The physical mechanism of generating electrical energy from a photovoltaic structure is the electric field and Explain in the context of electrons.arrow_forward
- You measure the structure of a crystalline sample of lead using the Ka peak of Cu X-rays at 8.06 keV. Carefully explain whether or not you would expect to see a reflection at an angle of 20.4°.arrow_forwardDetermine the element with the lowest atomic number that can be detected by wavelength dispersive x-ray spectroscopy that uses the LiF (200) crystal with the d spacing of 0.4028 nm.arrow_forwardIn the graph below the excitation (dashed line) and emission (solid line) spectra of a certain fluorescent dye is shown. To the nearest 5 nm, what is the peak emission wavelength of this dye? 3.80 430 480 Type your answer... 530 wavelength (nm) 580 -Excitation Emission 630arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College