Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 3, Problem 28ESP
To assess Mendel’s law of segregation using tomatoes, a true-breeding tall variety (SS) is crossed with a true-breeding short variety (ss). The heterozygous F1 tall plants (Ss) were crossed to produce two sets of F2 data, as follows.
- (a) Using the χ2 test, analyze the results for both datasets. Calculate χ2 values and estimate the p values in both cases.
- (b) From the above analysis, what can you conclude about the importance of generating large datasets in experimental conditions?
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Shown are F₂ results of a monohybrid cross performed by Mendel.
a) Calculate the expected numbers of each type of pods.
Full pods
Constricted pods
Total
882
298
1180
0.84
b) What do these p-values mean with regards to your null hypothesis? (Please
choose either reject or fail to reject.)
In one of Mendel’s dihybrid crosses, he observed315 round, yellow; 108 round, green; 101 wrinkled,yellow; and 32 wrinkled, green F2 plants. Analyze thesedata using the x2 test to see if(a) they fit a 9:3:3:1 ratio.(b) the round:wrinkled data fit a 3:1 ratio.(c) the yellow:green data fit a 3:1 ratio.
Mendel crossed two Pea plants for plant height and flower color Tall plant (T) is dominant to Short Plant (t). Purple Flower (P) is dominant to white flower (p). Using the following information perform the dihybrid cross using punnett squares that will predict all possible genotypes of the offspring and list the number and description of the phenotypes of the offspring. A. One plant homozygous dominant for plant height and flower color crossed with another plant homozygous recessive for plant height and heterozygous for flower color.
Chapter 3 Solutions
Concepts of Genetics (12th Edition)
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- Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forwardWhat are the expected phenotypic ratios from the following cross:Tt Rr yy Aa × Tt rr YY Aa, where T = tall, t = dwarf, R = round,r = wrinkled, Y = yellow, y = green, A = axial, a = terminal; T, R,Y, and A are dominant alleles. Note: Consider using the multiplication method in answering this problemarrow_forwardOn the basis of Mendel’s observations (i.e. Mendelian patterns), predict the results from the following crosses with peas. Show the results in terms of genotypes, phenotypes, and their proportions in the offspring. The progeny of a tall (dominant and homozygous) variety crossed with a dwarf variety. The progeny of (a) self-fertilized. The progeny from (a) crossed with the original tall parent. The progeny of (a) crossed with the original dwarf parent.arrow_forward
- shown are the F2 results of two Mendel's monohybrid crosses. Mendel crossed 2 heterozygote parents. If he were to expect segregation to happen normally, do the results match his expectations? state a null hypothesis that you will test using chi-square analysis. Calculate the chi-square value and determine the p value for both crosses a. Full pods: 882; constricted pods: 299 (full pods are dominant over constricted) b. violet flowers: 705; white flowers: 500 (violet dominant over white)arrow_forwardA test cross between a plant of genotype PpSs and the tester white plant with wrinkled seed coat (ppss) gives the following numbers of progeny in four phenotypic types. 14:87:83:16 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat). a. What is the expected ratio of progeny phenotypes assuming independent assortment of alleles? b. Explain how ratios of progeny show that the two genes are linked. c. How many map units separate the purple and smooth genes? Show your calculations. d. What is the “parental” genotype of the heterozygous parent? (i.e. Which alleles of the P and S loci are present on each of the two chromosomes of the doubly heterozygous parent of this test cross?)arrow_forwardSuppose that the wild type phenotype for tomatoes is red, round fruit with three-parted leaves and that a strain of mutant tomatoes has yellow, pear-shaped fruit with entire leaves. A and a represent the alleles for fruit color, B and b represent the alleles for fruit shape, and C and c the leaf shape. Two tomatoes with the genotypes Aa Bb cc and Aa Bb CC are crossed. The resulting Punnett square is shown. One cell has been completed with the correct tomato phenotype. Fill in the rest of the Punnett square by placing a fruit and leaf phenotype in each cell. ABC AbC aBC abC ABC Abc aBc abc Answer Bankarrow_forward
- PBIKE GU IKE GU Assume that a cross is made between a heterozygous tall pea plant and a s short pea plant. Fifty ofte GOR ano 582 produced in the following frequency: 30 = tall, 20 = s a) What frequency of tall and short plants is expected? b) To test the goodness of fit between the observed and expected values, provide the needed statement of the null c) Compute a Chi-square value (Table value is equal to 3.84) associated with the appropriate test of significance. d) How many degrees of freedom are associated with this test of significance? 29056 290582arrow_forwardTwo true-breeding varieties of maize, one 11 cm high and the other 47 cm high were crossed and the resultant F1 hybrids were then crossed to generate the F2 . In the F2 there were a total of 13,923 plants with a continuous variation in heights between the two extremes and with only 3 plants as large as 47 cm high and 5 plants of 11 cm high. The F1 from (b) is then crossed to give an F2. What proportion would you expect in the F2 of each extreme phenotype?arrow_forwardIn classical Mendelian genetics, how can one check the genotype of a parent (A) expressing the characters of a dominant allele? Select one: a. By performing a back cross with a recessive homozygote parent (B). If the A parent is homozygote for the dominant allele, then all the individuals from the F1 will display the dominant character. If the parent A was, instead, a heterozygote, then 50% of the F1 progeny will express the recessive character (homozygote recessive) and 50% the dominant one (heterozygotes). b. It is impossible to check such genotype without using specific molecular assays. c. By performing a back cross with a dominant homozygote parent (B). If the A parent is homozygote for the dominant allele, then all the individuals from the F1 will display the dominant character.arrow_forward
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