Concepts of Genetics (12th Edition)
Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134604718
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 3, Problem 20PDQ
Summary Introduction

To determine: The stringency of p-value equal to 0.10 in rejecting null hypotheses.

Introduction: The chi-square test was developed by Karl Pearson to determine if the observed distribution of the values or individuals in phenotypic categories occurs as predicted or it occurs by chance. It is a very common test employed in statistics to measure the distribution of phenotypic characters in genetic research.

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In a series of three experiments, M. G. Addo sought to use chi-square test to determine the goodness of fit at 5% for each of his results below. Carry out the calculations and determine whether the results obtained in each case are consistent with the 3:1 or 1:1:1:1 ratio he predicted in his hypothesis. Comment on your results. CROSS Tall x short Purple x white Round yellow (F1) x Wrinkled green (F1) RESULTS HΥΡΟΤHESIS 712:352 3:1 705 : 224 3:1 31:26:27:26 1:1:1:1
Through PCR, we have determined the PER3 genotypes for a class of students as follows: H4/H4 = 125 individuals; H4/H5 = 90 individuals and H5/H5=85 individuals. Considering the Hardy Weinberg equilibrium and calculating the Chi-square statistic, do you reject or fail to reject the null-hypothesis?  1. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I reject the null hypothesis. 2. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P>0.05. Hence, I reject the null hypothesis.  3. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the appropriate degrees of freedom I conclude that P<0.05. Hence, I fail to reject the null hypothesis. 4. Comparing the value of Chi-square that I calculated with the critical value of Chi-square for the…
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Chapter 3 Solutions

Concepts of Genetics (12th Edition)

Ch. 3 - Albinism in humans is inherited as a simple...Ch. 3 - Which of Mendels postulates are illustrated by the...Ch. 3 - Discuss how Mendels monohybrid results served as...Ch. 3 - What advantages were provided by Mendels choice of...Ch. 3 - Mendel crossed peas having round seeds and yellow...Ch. 3 - Based on the preceding cross, what is the...Ch. 3 - Which of Mendels postulates can only be...Ch. 3 - In a cross between a black and a white guinea pig,...Ch. 3 - What is the basis for homology among chromosomes?Ch. 3 - In Drosophila, gray body color is dominant to...Ch. 3 - How many different types of gametes can be formed...Ch. 3 - Mendel crossed peas having green seeds with peas...Ch. 3 - In a study of black guinea pigs and white guinea...Ch. 3 - Mendel crossed peas having round green seeds with...Ch. 3 - Prob. 17PDQCh. 3 - The following are F2 results of two of Mendels...Ch. 3 - In assessing data that fell into two phenotypic...Ch. 3 - Prob. 20PDQCh. 3 - Consider the following pedigree. Predict the mode...Ch. 3 - Draw all possible conclusions concerning the mode...Ch. 3 - For decades scientists have been perplexed by...Ch. 3 - A wrongful birth case was recently brought before...Ch. 3 - TaySachs disease (TSD) is an inborn error of...Ch. 3 - Datura stramonium (the Jimsonweed) expresses...Ch. 3 - The wild-type (normal) fruit fly, Drosophila...Ch. 3 - To assess Mendels law of segregation using...Ch. 3 - Albinism, caused by a mutational disruption in...Ch. 3 - (a) Assuming that Migaloos albinism is caused by a...
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