Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 3, Problem 26QP
Summary Introduction
To predict: The pedigree chart for the family with the youngest son affected by albinism.
Introduction: Albinism is an autosomal recessive condition where the pigment melanin is lost from the skin that provides color to the skin. The skin becomes whitish and pale and is prone to damage under sunlight.
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Mendel's Law of Independent Assortment states that:
the members of a pair of homologous chromosemes assort independently of each other during gamete formation
none of these
the members of a pair of homologous chromosomes separate from each other during gamete formati
different pairs of homologous chromosomes assort independently of each other during gamete formation
different pairs of homologous chromosomes separate from each other during gamete formation
Mendel’s observation that two different traits could be inherited independently of each other can be explained by understanding that:
During meiosis, the process of chromosome assortment into daughter cells is random
Alleles of the genes reside on homologous chromosomes
All of the listed choices are correct
During meiosis, maternal and paternal members of homologous chromosomes are distributed separately into daughter cells
When Gregor Mendel was working in the mid 1800s, scientists had not yet discovered chromosomes or meiosis. However, we now understand how Mendel's principles are rooted in the events of meiosis. As an example of this, state Mendel's principle of independent assortment and explain how it relates to independent assortment in meiosis.
Chapter 3 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 3.4 - Why do scientists design experiments to disprove...Ch. 3.4 - Should Ockhams razor be considered an irrefutable...Ch. 3.7 - Prob. 1EGCh. 3.7 - For most cases, a p value of 0.05 is used to...Ch. 3 - Prob. 1CSCh. 3 - Prob. 2CSCh. 3 - Prob. 3CSCh. 3 - Prob. 1QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...
Ch. 3 - Prob. 4QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Prob. 6QPCh. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - Crossing Pea Plants: Mendels Study of Single...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Prob. 14QPCh. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Prob. 17QPCh. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - More Crosses with Pea Plants: The Principle of...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Meiosis Explains Mendels Results: Genes Are on...Ch. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Variations on a Theme by Mendel A characteristic...Ch. 3 - Prob. 29QPCh. 3 - Variations on a Theme by Mendel Pea plants usually...Ch. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QP
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- Assume that color blindness is a recessive character on the X chromosome. A man and woman with normal vision have the following offspring: a daughter with normal vision who has one color-blind son and one normal son; a daughter with normal vision who has six normal sons; and a color-blind son who has a daughter with normal vision. What are the probable genotypes of all individuals?arrow_forwardCystic fibrosis is a recessive human condition. A male with Cystic fibrosis and a woman with a dominant phenotype have sevral children, in which one displays Cystic fibrosis. What can you conclude about the genotype of the maternal parent and what is the probability that a child who does not display Cystic fibrosis is heterozygous?arrow_forwardA karyotype shows that a child has Klinefelter syndrome (47,XXY). If the child is also colorblind (due to a recessive X-linked allele), despite his parents having normal color vision, in which parent and stage of meiosis did nondisjunction occur? And explain why .arrow_forward
- The gene for nose shape is found on the X chromosome. Round nose is dominant to pointed nose. Human individuals with XXY (an additional X chromosome) are male. Individuals with XO (only one X chromosome) are female. For the following family, identify the possible nondisjunction events (rare mistakes during meiosis) that could explain the phenotype of the child. A man with a pointed nose and a woman with a round nose have a daughter with a round nose. This daughter has Turner Syndrome (genotype XO: one X chromosome). Nondisjunction must have occurred in melosis 2 of the mother More than one of the answers is correct Nondisjunction must have occurred in meiosis 1 of the father Nondisjunction must have occurred in meiosis 1 of the mother Nondisjunction must have occurred in meiosis 2 of the fatherarrow_forwardA WOMAN IS HETEROZYGOUS FOR TWO HARMFUL RECESSIVE ALLELES IN DIFFERENT CHROMOSOMES, ONE FOR PHENYLKETONURIA (PKU) AND THE OTHER FOR CYSTIC FIBROSIS (CF). SHE MARRIES AN UNAFFECTED MAN WHO IS A CARRIER FOR NEITHER DISEASE. IF SHE HAS A DAUGHTER, WHAT IS THE PROBABILITY THAT THE CHILD WILL CARRY NEITHER OF THE RECESSIVE ALLELES? EXACTLY ONE? BOTH?arrow_forwardIn humans, brown eyes (B) are dominant over blue. A brown eyed man marries a blue-eyed (b) woman and they have three children two of whom are brown-eyed and one of whom is blue-eyed. if the male has brown eyes but has a blue-eyed child, what must his genotype be?arrow_forward
- In the cross between a female AaBbccDdee and male AabbCcDdee, what proportion of the progeny are expected to be phenotypically identical to the female parent?arrow_forwardWhat aspect of chromosome behavior most clearly accounts for Mendel's law of segregation? Movement of sister chromatids to opposite poles at anaphase Il of meiosis. Movement of homologous chromosomes to opposite poles at anaphase I of meiosis. Crossing over between homologous chromosomes during prophase I of meiosis. Replication of chromosomes prior to meiosis. Independent alignment of different homologous pairs on the metaphase I spindle.arrow_forwardDiscuss the postulates of Mendel in relation to meiosis.arrow_forward
- Which phase of meiosis explains Mendel's Law of Segregation? Anaphase I Anaphase II Metaphase II O Prophase Iarrow_forwardExplain the relationship between meiosis and Mendel’s lawsof inheritance.arrow_forwardHow can Mendel's postulates of segregation and independent assortment be explained by meiosis?arrow_forward
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