Chapter 29, Problem 4P

To determine

The conversion factor and binding energy of $KCl$ in kcal per mole.

Answer to Problem 4P

Binding energy of $KCl$ in kcal per mole is $102kcal/mol$ .

Explanation of Solution

Given info:

Binding energy of $KCl$ is $\text{4}\text{.43}\text{eV}$

Formula used:

Charges in one electron, $\text{e}\text{=1}\text{.60}\times {\text{10}}^{-19}C$

Calculation:

First convert the units:

  $1kcal/mol=\frac{\left(1kcal/mol\right)\left(4186J/kcal\right)}{\left(6.02\times {10}^{23}molecules/mol\right)\left(1.60\times {10}^{-19}J/eV\right)}=0.0435eV/mol$

Now calculation for $KCl$

  $\left(0.0435eV/mol\right)\left[\frac{\left(1kcal/mol\right)}{0.0434eV/mol}\right]=102kcal/mol$

Conclusion: The required value is $102kcal/mol$ .