Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Question
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Chapter 2.8, Problem 2PSA

a

To determine

To calculate : The value of 2 is to be calculated

a

Expert Solution
Check Mark

Answer to Problem 2PSA

The value of 2 is 119028'

Explanation of Solution

Given information : The following information can be predicted from the diagram

  1=60032'

  1 and 3 are vertically opposite angles

  2 and 4 are vertically opposite angles

Formula used : We will use the following formulas

Vertically opposite angles have same measurements

Supplementary angles add up to 1800

Calculation : We can see that 2 is the supplementary angle for 1=60032'

Hence, we can say that

  2=180060032'=119028'

Hence, the desired value is calculated

b

To determine

To calculate : The value of 3 is to be calculated

b

Expert Solution
Check Mark

Answer to Problem 2PSA

The value of 3 is 60032'

Explanation of Solution

Given information : The following information can be predicted from the diagram

  1=60032'

  1 and 3 are vertically opposite angles

  2 and 4 are vertically opposite angles

Formula used : We will use the following formulas

Vertically opposite angles have same measurements

Supplementary angles add up to 1800

Calculation : We can see that 3 is the vertically opposite angle for 1=60032'

Hence, we can say that

  3=60032'

Hence, the desired value is calculated

c

To determine

To calculate : The value of 4 is to be calculated

c

Expert Solution
Check Mark

Answer to Problem 2PSA

The value of 4 is 119028'

Explanation of Solution

Given information : The following information can be predicted from the diagram

  1=60032'

  1 and 3 are vertically opposite angles

  2 and 4 are vertically opposite angles

Formula used : We will use the following formulas

Vertically opposite angles have same measurements

Supplementary angles add up to 1800

Calculation : We can see that 4 is the supplementary angle for 1=60032'

Hence, we can say that

  4=180060032'=119028'

Hence, the desired value is calculated

Chapter 2 Solutions

Geometry For Enjoyment And Challenge

Ch. 2.1 - Prob. 11PSBCh. 2.1 - Prob. 12PSBCh. 2.1 - Prob. 13PSBCh. 2.1 - Prob. 14PSCCh. 2.1 - Prob. 15PSCCh. 2.2 - Prob. 1PSACh. 2.2 - Prob. 2PSACh. 2.2 - Prob. 3PSACh. 2.2 - Prob. 4PSACh. 2.2 - Prob. 5PSACh. 2.2 - Prob. 6PSACh. 2.2 - Prob. 7PSACh. 2.2 - Prob. 8PSACh. 2.2 - Prob. 9PSACh. 2.2 - Prob. 10PSACh. 2.2 - Prob. 11PSACh. 2.2 - Prob. 12PSBCh. 2.2 - Prob. 13PSBCh. 2.2 - Prob. 14PSBCh. 2.2 - Prob. 15PSBCh. 2.2 - Prob. 16PSBCh. 2.2 - Prob. 17PSBCh. 2.2 - Prob. 18PSBCh. 2.2 - Prob. 19PSBCh. 2.2 - Prob. 20PSBCh. 2.2 - Prob. 21PSBCh. 2.2 - Prob. 22PSBCh. 2.2 - Prob. 23PSBCh. 2.2 - Prob. 24PSBCh. 2.2 - Prob. 25PSCCh. 2.2 - Prob. 26PSCCh. 2.3 - Prob. 1PSACh. 2.3 - Prob. 2PSACh. 2.3 - Prob. 3PSACh. 2.3 - Prob. 4PSACh. 2.3 - Prob. 5PSACh. 2.3 - Prob. 6PSACh. 2.3 - Prob. 7PSACh. 2.3 - Prob. 8PSACh. 2.3 - Prob. 9PSBCh. 2.3 - Prob. 10PSBCh. 2.3 - Prob. 11PSBCh. 2.3 - Prob. 12PSBCh. 2.3 - Prob. 13PSCCh. 2.3 - Prob. 14PSCCh. 2.4 - Prob. 1PSACh. 2.4 - Prob. 2PSACh. 2.4 - Prob. 3PSACh. 2.4 - Prob. 4PSACh. 2.4 - Prob. 5PSACh. 2.4 - Prob. 6PSACh. 2.4 - Prob. 7PSACh. 2.4 - Prob. 8PSACh. 2.4 - Prob. 9PSACh. 2.4 - Prob. 10PSBCh. 2.4 - Prob. 11PSBCh. 2.4 - Prob. 12PSBCh. 2.4 - Prob. 13PSBCh. 2.4 - Prob. 14PSBCh. 2.4 - Prob. 15PSBCh. 2.4 - Prob. 16PSBCh. 2.4 - Prob. 17PSBCh. 2.4 - Prob. 18PSBCh. 2.4 - Prob. 19PSBCh. 2.4 - Prob. 20PSCCh. 2.4 - Prob. 21PSCCh. 2.5 - Prob. 1PSACh. 2.5 - Prob. 2PSACh. 2.5 - Prob. 3PSACh. 2.5 - Prob. 4PSACh. 2.5 - Prob. 5PSACh. 2.5 - Prob. 6PSACh. 2.5 - Prob. 7PSACh. 2.5 - Prob. 8PSACh. 2.5 - Prob. 9PSACh. 2.5 - Prob. 10PSACh. 2.5 - Prob. 11PSBCh. 2.5 - Prob. 12PSBCh. 2.5 - Prob. 13PSBCh. 2.5 - Prob. 14PSBCh. 2.5 - Prob. 15PSBCh. 2.5 - Prob. 16PSBCh. 2.5 - Prob. 17PSCCh. 2.5 - Prob. 18PSCCh. 2.5 - Prob. 19PSCCh. 2.6 - Prob. 1PSACh. 2.6 - Prob. 2PSACh. 2.6 - Prob. 3PSACh. 2.6 - Prob. 4PSACh. 2.6 - Prob. 5PSACh. 2.6 - Prob. 6PSACh. 2.6 - Prob. 7PSACh. 2.6 - Prob. 8PSACh. 2.6 - Prob. 9PSACh. 2.6 - Prob. 10PSACh. 2.6 - Prob. 11PSBCh. 2.6 - Prob. 12PSBCh. 2.6 - Prob. 13PSBCh. 2.6 - Prob. 14PSBCh. 2.6 - Prob. 15PSCCh. 2.6 - Prob. 16PSCCh. 2.7 - Prob. 1PSACh. 2.7 - Prob. 2PSACh. 2.7 - Prob. 3PSACh. 2.7 - Prob. 4PSACh. 2.7 - Prob. 5PSACh. 2.7 - Prob. 6PSACh. 2.7 - Prob. 7PSACh. 2.7 - Prob. 8PSACh. 2.7 - Prob. 9PSACh. 2.7 - Prob. 10PSBCh. 2.7 - Prob. 11PSBCh. 2.7 - Prob. 12PSBCh. 2.7 - Prob. 13PSBCh. 2.7 - Prob. 14PSBCh. 2.7 - Prob. 15PSBCh. 2.7 - Prob. 16PSCCh. 2.7 - Prob. 17PSCCh. 2.7 - Prob. 18PSDCh. 2.7 - Prob. 19PSDCh. 2.7 - Prob. 20PSDCh. 2.8 - Prob. 1PSACh. 2.8 - Prob. 2PSACh. 2.8 - Prob. 3PSACh. 2.8 - Prob. 4PSACh. 2.8 - Prob. 5PSACh. 2.8 - Prob. 6PSACh. 2.8 - Prob. 7PSACh. 2.8 - Prob. 8PSACh. 2.8 - Prob. 9PSBCh. 2.8 - Prob. 10PSBCh. 2.8 - Prob. 11PSBCh. 2.8 - Prob. 12PSBCh. 2.8 - Prob. 13PSBCh. 2.8 - Prob. 14PSBCh. 2.8 - Prob. 15PSCCh. 2 - Prob. 1RPCh. 2 - Prob. 2RPCh. 2 - Prob. 3RPCh. 2 - Prob. 4RPCh. 2 - Prob. 5RPCh. 2 - Prob. 6RPCh. 2 - Prob. 7RPCh. 2 - Prob. 8RPCh. 2 - Prob. 9RPCh. 2 - Prob. 10RPCh. 2 - Prob. 11RPCh. 2 - Prob. 12RPCh. 2 - Prob. 13RPCh. 2 - Prob. 14RPCh. 2 - Prob. 15RPCh. 2 - Prob. 16RPCh. 2 - Prob. 17RPCh. 2 - Prob. 18RPCh. 2 - Prob. 19RPCh. 2 - Prob. 20RPCh. 2 - Prob. 21RPCh. 2 - Prob. 22RPCh. 2 - Prob. 23RPCh. 2 - Prob. 24RPCh. 2 - Prob. 25RPCh. 2 - Prob. 26RPCh. 2 - Prob. 27RPCh. 2 - Prob. 28RPCh. 2 - Prob. 29RPCh. 2 - Prob. 30RPCh. 2 - Prob. 31RPCh. 2 - Prob. 32RPCh. 2 - Prob. 33RPCh. 2 - Prob. 34RPCh. 2 - Prob. 35RPCh. 2 - Prob. 36RPCh. 2 - Prob. 37RPCh. 2 - Prob. 38RP
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