Chapter 2.4, Problem 14PSB

a)

To determine

To calculate: Coordinates of R

Answer to Problem 14PSB

(-10, 0)

Explanation of Solution

Given information:

  

Formula Used : Area of triangle $=\frac{1}{2}\times base\times height.$

Calculation: R lies on negative X axis and ER is parallel to Y axis $\therefore R(-10,0)$ .

b)

To determine

To calculate: Information about $\angle RTE$ and $\angle CTE$

Answer to Problem 14PSB

Complementary angles

Explanation of Solution

Given information:

  

Formula Used : Area of triangle $=\frac{1}{2}\times base\times height.$

Calculation:

  $\because$ X and Y axis are perpendicular to each other.

  $\begin{array}{l}\therefore \angle CTR={90}^{\circ }\\ \therefore \angle RTE+\angle CTE={90}^{\circ }\end{array}$

Hence these angles are complementary

c)

To determine

To calculate: Area of $\Delta ERT$

Answer to Problem 14PSB

35 square units

Explanation of Solution

Given information:

  

Formula Used : Area of triangle $=\frac{1}{2}\times base\times height.$

Calculation:

Area of $\Delta ERT=\frac{1}{2}\times RT\times ER$

  $=\frac{1}{2}\times 10\times 7$

= 35 square inch 3rd