Chapter 2.2, Problem 22PSB

To determine

To calculate: Supplement of the angle.

Answer to Problem 22PSB

  ${163}^{\circ }20\text{'}$

Explanation of Solution

Given information: five times complement of an angle less twice the supplement is ${40}^{\circ }$ .

Formula Used: sum of two supplementary angle is ${180}^{\circ }$ and sum of two complementary angle is ${90}^{\circ }$ .

Calculation: let measure of the angle be $x^{\circ }$ then its supplement is ${(180-x)}^{\circ }$ and its complement is ${(90-x)}^{\circ }$ then according to the given condition.

  $={163}^{\circ }20\text{'}$

  $\therefore$ Its compliment is ${(180-\frac{50}{3})}^{\circ }$

  $={163}^{\circ }20\text{'}$