Chapter 2.3, Problem 2PSA

To determine

To Draw: conclusions from given information.

Answer to Problem 2PSA

  ${90}^{\circ }$

Explanation of Solution

Given information: $\angle DEF$ .is complementary to $\angle FEH$

  

$\angle DEF$ .is complementary to $\angle FEH$

Hence by definition of complementary function ,

  $\begin{array}{l}\angle DEF+\angle FEH={90}^{\circ }\\ \therefore \angle DEH={90}^{\circ }\end{array}$

  $\therefore DE\perp EH$ (If angle between two lines is ${90}^{\circ }$ , then the lines are perpendicular to each other ).