Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Textbook Question
Chapter 27, Problem 18RQ
What two methods can be utilized to reduce the force and power requirements for a particular broaching cut?
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Chapter 27 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 27 - Why is sawing one of the most efficient of the...Ch. 27 - Explain why tooth spacing (pitch) is important in...Ch. 27 - What is the tooth gullet used for on a saw blade?Ch. 27 - Explain what is meant by the set of the teeth on a...Ch. 27 - How is tooth set related to saw kerf?Ch. 27 - Why can a bandsaw blade not be hardened throughout...Ch. 27 - What are the advantages of using circular saws?Ch. 27 - Why have bandsawing machines largely replaced...Ch. 27 - Explain how the hole in Figure 27.7 is made on a...Ch. 27 - How would you calculate or estimate Tm for a...
Ch. 27 - What is the disadvantage of using gravity to feed...Ch. 27 - What is unique about the broaching process...Ch. 27 - Can a thick saw blade be used as a broach? Why or...Ch. 27 - Broaching machines are simpler in a basic design...Ch. 27 - Why is broaching particularly well-suited for mass...Ch. 27 - In designing a broach, what would be the first...Ch. 27 - Why is it necessary to relate the design of a...Ch. 27 - What two methods can be utilized to reduce the...Ch. 27 - For a given job, how would a broach having...Ch. 27 - Why are the pitch and radius of the gullet between...Ch. 27 - Why are broaching speeds usually relatively low,...Ch. 27 - What are the advantages of shell-type broach...Ch. 27 - Why are most broaches made from alloy or...Ch. 27 - What are the advantages of TiN-coated broaching...Ch. 27 - For mass-production operations, which process is...Ch. 27 - What is the difference between the roughing teeth...Ch. 27 - The sides of a square, blind hole must be machined...Ch. 27 - The interior, flat surfaces of socket wrenches,...Ch. 27 - Prob. 29RQCh. 27 - What are some ways to improve the efficiency of a...Ch. 27 - To what extent is filing different from sawing?Ch. 27 - Prob. 32RQCh. 27 - Prob. 33RQCh. 27 - Prob. 34RQCh. 27 - A surface 12 in. long is to be machined with a...Ch. 27 - The pitch of the teeth on a simple surface broach...Ch. 27 - Estimate the (approximate maximum) horsepower...Ch. 27 - Estimate the approximate force acting in the...Ch. 27 - In cutting a 6-in.-long slot in a piece of AISI...Ch. 27 - The strength of a pull broach is determined by its...Ch. 27 - Suppose you want to shape a block of metal 7 in....Ch. 27 - Could you have saved any time in Problem 7 by...Ch. 27 - Derive the equation for shaping cutting speed.Ch. 27 - How many strokes per minute would be required to...Ch. 27 - How much time would be required to shape a flat...Ch. 27 - What is the metal removal rate in Problem 11 if...Ch. 27 - Suppose you decide to mill the flat surface...Ch. 27 - A planer has a 10-hp motor, and 75% of the motor...
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- 34 - The outside diameter of a cylinder made of titanium alloy is to be turned. The starting diameter is 400 mm and the length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.24 and C-450. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time for this part. vT" = C . AD,L Tm %3D fv a) 325.8 m /min b) 275.8 m/min 226.6 m/min d) O 187.9 m/minarrow_forwardIn the manufacture of twist drills, the shank is joined to the body of the drill using (a) spot welding (b) TIG welding (c) projection welding (d) friction weldingarrow_forwardPuanlar) 16 The outside diameter of a cylinder made of titanium alloy is to be turned. The starting diameter is 400 mm and the length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.24 and C=450. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time for this part. V vT" = C. %3D Ce Tm 1. %3D 19 fv 25 31 37 43 49 187.9 m/min b) 325.8 m /min 275.8 m/min d) 226.6 m/minarrow_forward
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