Chapter 2.2, Problem 47E

To determine

To Draw: the normal density curve

Explanation of Solution

Given:

Mean $\mu$ =9.12 ounce

Standard deviation $\sigma$ =0.05 ounce

Calculation:

For 68%

Within 1 standard deviation of the mean

  $\begin{array}{c}\mu -\sigma =9.12-0.05=9.07\\ \mu +\sigma =9.12+0.05=9.17\end{array}$

For 95%

Within 2 standard deviation of the mean

  $\begin{array}{c}\mu -2\sigma =9.12-2(0.05)=9.02\\ \mu +2\sigma =9.12+2(0.05)=9.22\end{array}$

For 99.7%

Within 3 standard deviation of the mean

  $\begin{array}{c}\mu -3\sigma =9.12-3(0.05)=8.97\\ \mu +3\sigma =9.12+3(0.05)=9.27\end{array}$

Graph: