PRACTICE OF STATISTICS F/AP EXAM
PRACTICE OF STATISTICS F/AP EXAM
6th Edition
ISBN: 9781319113339
Author: Starnes
Publisher: MAC HIGHER
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Chapter 2.1, Problem 15E

(a)

To determine

Interpretation of the z − score.

(a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

z − score,

  z=1.10

The z − score describes the number of standard deviations that a value is from the mean.

Negative z − score indicates that the value is below the mean.

Whereas,

Positive z − score indicates that the value is above the mean.

Thus,

According to the sample, 22 pairs of shoes that Jackson owns is 1.10 standard deviations above the mean number of the pairs of shoes owned by the other students.

(b)

To determine

Mean of the distribution using the information along with Jackson’s z − score.

(b)

Expert Solution
Check Mark

Answer to Problem 15E

Mean of the distribution,

  μ=11.638

Explanation of Solution

Given information:

Value, x=22

Standard deviation, σ=9.42

z − score, z=1.10

Calculations:

Calculate the z − score:

  z=xμσ

Substitute values,

  1.10=22μ9.42

Multiply both sides by 9.42:

  10.362=22μ

That becomes

  μ=2210.362=11.638

Since the units of the mean and the data values are same.

Thus,

The mean is 11.638 pairs of shoes.

Chapter 2 Solutions

PRACTICE OF STATISTICS F/AP EXAM

Ch. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.2 - Prob. 49ECh. 2.2 - Prob. 50ECh. 2.2 - Prob. 51ECh. 2.2 - Prob. 52ECh. 2.2 - Prob. 53ECh. 2.2 - Prob. 54ECh. 2.2 - Prob. 55ECh. 2.2 - Prob. 56ECh. 2.2 - Prob. 57ECh. 2.2 - Prob. 58ECh. 2.2 - Prob. 59ECh. 2.2 - Prob. 60ECh. 2.2 - Prob. 61ECh. 2.2 - Prob. 62ECh. 2.2 - Prob. 63ECh. 2.2 - Prob. 64ECh. 2.2 - Prob. 65ECh. 2.2 - Prob. 66ECh. 2.2 - Prob. 67ECh. 2.2 - Prob. 68ECh. 2.2 - Prob. 69ECh. 2.2 - Prob. 70ECh. 2.2 - Prob. 71ECh. 2.2 - Prob. 72ECh. 2.2 - Prob. 73ECh. 2.2 - Prob. 74ECh. 2.2 - Prob. 75ECh. 2.2 - Prob. 76ECh. 2.2 - Prob. 77ECh. 2.2 - Prob. 78ECh. 2.2 - Prob. 79ECh. 2.2 - Prob. 80ECh. 2.2 - Prob. 81ECh. 2.2 - Prob. 82ECh. 2.2 - Prob. 83ECh. 2.2 - Prob. 84ECh. 2.2 - Prob. 85ECh. 2.2 - Prob. 86ECh. 2.2 - Prob. 87ECh. 2.2 - Prob. 88ECh. 2.2 - Prob. 89ECh. 2.2 - Prob. 90ECh. 2.2 - Prob. 91ECh. 2.2 - Prob. 92ECh. 2 - Prob. R2.1RECh. 2 - Prob. R2.2RECh. 2 - Prob. R2.3RECh. 2 - Prob. R2.4RECh. 2 - Prob. R2.5RECh. 2 - Prob. R2.6RECh. 2 - Prob. R2.7RECh. 2 - Prob. R2.8RECh. 2 - Prob. R2.9RECh. 2 - Prob. T2.1SPTCh. 2 - Prob. T2.2SPTCh. 2 - Prob. T2.3SPTCh. 2 - Prob. T2.4SPTCh. 2 - Prob. T2.5SPTCh. 2 - Prob. T2.6SPTCh. 2 - Prob. T2.7SPTCh. 2 - Prob. T2.8SPTCh. 2 - Prob. T2.9SPTCh. 2 - Prob. T2.10SPTCh. 2 - Prob. T2.11SPTCh. 2 - Prob. T2.12SPTCh. 2 - Prob. T2.13SPT
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