Chapter 22, Problem 45R

To determine

To Calculate: The volume of concentrate needed to make $3\text{ L}$ of the indicator.

Answer to Problem 45R

  $\underset{\_}{90\text{ mL}}$ of concentrated solution is needed to make $3\text{ L}$ of the indicator solution.

Explanation of Solution

Given:

Volume of concentrated solution required to make $100\text{ mL}$ of indicator solution. = $3.0\text{ mL}$

Calculation:

As per the problem,

Volume of concentrate required to make $100\text{ mL}$ of indicator solution. = $3.0\text{ mL}$

Therefore, volume of concentrate required to make $1\text{ mL}$ of indicator solution

  $=\frac{3.0\text{ mL}}{100}=0.03\text{ mL}$

Hence, volume of concentrate required to make $3\text{ L}$ of indicator solution

  $\begin{array}{l}=(0.03\text{ mL}\times 3000\text{) [1 L=1000 mL; 3 L=3000 mL]}\\ \text{=90 mL}\end{array}$

Conclusion: $90\text{ mL}$ of concentrated solution is needed to make $3\text{ L}$ of indicator solution.