Concept explainers
In the text, JUMP instructions were expressed by identifying the destination explicitly by stating the name (or step number) of the destination within the JUMP instruction (for example, “Jump to Step 6”). A drawback of this technique is that if an instruction name (number) is later changed, we must be sure to find all jumps to that instruction and change that name also. Describe another way of expressing a JUMP instruction so that the name of the destination is not explicitly stated.
Want to see the full answer?
Check out a sample textbook solutionChapter 2 Solutions
Computer Science: An Overview (12th Edition)
Additional Engineering Textbook Solutions
Concepts Of Programming Languages
Concepts of Programming Languages (11th Edition)
Starting Out with Java: From Control Structures through Objects (6th Edition)
C How to Program (8th Edition)
Starting Out with Python (3rd Edition)
Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
- Implement a new unary instruction in place of N0P0 called ASL2 that does two left shifts on the accumulator. V should remain unchanged, but N and Z should correlate with the new value in the accumulator, and C should be the carry from the second shift. Write a program that tests all the features of the new instruction.arrow_forwardCreate a stack-based program which computes: 7 & (9 | 8). Your answer should include an illustration which shows the state of the stack after each instruction and show the workings of all the calculations that are required.arrow_forwardWrite an instruction that uses a segment override.arrow_forward
- Assignment for Computer Architecture The assignment is to create a MIPS program that demonstrates that the associative law fails in addition for floating point numbers (single or double precision). You only need to demonstrate it for single precision. Remember the associative law is a + (b + c) = (a + b) + c. The program’s output should look something like the following where the xxx’s are the numbers you chose. The resulting numbers may be different than mine depending on your choice of a, b, and c. Using a = xxx, b = xxx, and c = xxx a + (b + c) = 0 (a + b) + c = 1 The key is to have two of the number large (one positively and one negatively but equal in magnitude) floating point numbers and the third floating point number very small in comparison. As a side note, the associative law will also fail for multiplication for floating point numbers, but you do not need to demonstrate that. Please don't forget to include comments in this codearrow_forwardE In the following code block(Reference:Q11), you will a set of assembly instructions with corresponding line numbers (line numbers are for informational purpose only and they are not part of the source code). 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 mov edx, 5 dec ecx jmp LABEL1 mov eax, 1 LABEL1: mul edx jmp ecx mov edx, 0678h sub edx, eax jmp DWORD PTR [edx] neg ebx add ecx, ebx mov eax, 0 For each of the conditions/scenario listed below, indicate the corresponding line number (that cause or is associated with the condition/scenario). Enter 0 (Zero) if the condition is not caused by the block of code. 1) Memory indirect jump: type your answer... type your answer... type your answer... type your answer... 2) Register indirect jump: 3) Relative short jump: type your answer... 5) Two's complement type your answer... 4) Relative near jump: 6) Unreachable codearrow_forwardThis problem is adapted from an earlier edition of P&H, and should be submitted.Consider the following code used to implement a new instruction: foo $t3,$t1,$t2:mask : . word 0xFFFFF83Fs t a r t : l a $t0 , masklw $t0 , 0 ( $ t 0 )l a $t3 , s h f t rlw $t3 , 0 ( $ t 3 )and $t3 , $t3 , $ t 0a ndi $t2 , $t2 , 0 x 0 0 1 fs l l $t2 , $t2 , 6o r $t3 , $t3 , $ t 2l a $t5 , s h f t rsw $t3 , 0 ( $ t 5 )s h f t r : s l l $t3 , $t1 , 0Add meaningful comments to the code and write a brief (2 sentence max) description of what foo does. Thisis not the same as saying how it does it - e.g., when asked to describe what a pedestrian is doing, you wouldsay they are walking, not that they are ilfting their left leg, angling it forward, putting it down, . . ..State at least one reason why writing “self-modifying code” such as this is a bad idea (and often times notactually allowed by the operating system)?arrow_forward
- 8.fast please in assembly You are giving the before condition and an instruction. Give the after condition:Before:Esp:00 63 FB 54instruction: ret After: Group of answer choices esp: 00 63 FB 50 esp: 00 63 FB 55 esp: 00 63 FB 54 esp: 00 63 FB 58arrow_forwardA problem-solving procedure that requires executing one or more comparison and branch instructions is called a(n) __________.arrow_forward_____ is a CPU design technique in which instruction execution is divided into multiple stages and different instructions can execute in different stages simultaneously.arrow_forward
- Each instruction in this situation is given its own data, separate from the data used by any other instructions. To do this, we use a: A Multiple Input/Output B Data or Instruction Repeatedly C Distinct Information Difficulty Level: Single Inst, Single Inst, Multiplearrow_forwardThe codes below are disassembled from a program. Write an invalid target for the “jmp” instruction such that the code can be considered as anti-disassembly. Jmp ??? loc_2: call 15FF2A1h OR [ecx], d1 inc eax jmp short loc_3 db 0E8h Please just give me a simple answerarrow_forwardAmdahl’s Law My speedup factor is 6. My new execution time after speedup is 5 seconds. What was my old or original execution time in seconds?arrow_forward
- Systems ArchitectureComputer ScienceISBN:9781305080195Author:Stephen D. BurdPublisher:Cengage LearningEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT