Chapter 2, Problem 23CRP

a.

Explanation of Solution

Determine the program to move the value at memory location $\text{0×D8}$ to memory location $\text{0×B3}$:

• The program counter instruction registers to move the value at memory location $\text{0×D8}$ to location $\text{0×B3}$ is as follows.

$\begin{array}{l}\text{12}\text{D8}\\ \text{31}\text{B3}\end{array}$

• The bit pattern memory of the cell address $\text{D8}$ is stored in the register $1$ after the execution of first instruction

b.

Explanation of Solution

Determine the program to interchange the value at memory location $\text{0×D8}$ to memory location $\text{0×B3}$:

• The program counter instruction registers to interchange the value at memory location $\text{0×D8}$ to memory location $\text{0×B3}$ is as follows.

$\begin{array}{l}\text{11}\text{D8}\\ \text{12}\text{B3}\\ \text{32}\text{D8}\\ \text{31}\text{B3}\end{array}$

• The contents of the memory cell $\text{D8}$ with contents are present in load register $1$
• The contents of the memory cell $\text{B3}$ with contents are present in load register $2$
• The bit pattern stored in register $2$ is copied in the memory cell $\text{D8}$ and the bit pattern stored in register $1$ is copied in the memory cell $\text{B3}$

c.

Explanation of Solution

Determine the program if the value stored in the memory location $0\times 44$ is $0\times 00$, then place the value $0\times 01$ in memory location $0\times 46$, otherwise put the value $0\times \text{FF}$ in memory location $0\times 46$:

• The address content of the program is shown as follows.

$\begin{array}{l}\text{00}\text{20}\\ \text{01}\text{00}\\ \text{02}\text{11}\\ \text{03}\text{44}\end{array}$

$\begin{array}{l}\text{04}\text{B1}\\ \text{05}\text{0C}\\ \text{06}\text{24}\\ \text{07}\text{FF}\end{array}$

$\begin{array}{l}\text{08}\text{34}\\ \text{09}\text{46}\\ \text{0A}\text{0B}\\ \text{0B}\text{10}\end{array}$

$\begin{array}{l}\text{0C}\text{25}\\ \text{0D}\text{01}\\ \text{0E}\text{35}\\ \text{0F}\text{46}\end{array}$

$\begin{array}{l}\text{10}\text{C0}\\ \text{11}\text{00}\end{array}$

• The sequence of instruction to be followed is as follows.

$\begin{array}{l}\text{2000}\\ \text{1144}\\ \text{B10C}\\ \text{24FF}\end{array}$

$\begin{array}{l}\text{3446}\\ \text{B010}\\ \text{2501}\\ \text{3546}\end{array}$

$\text{C000}$

• The bit pattern $00$ is stored in register $0$ after the execution of instruction $2000$