Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 2.2, Problem 15PP
Interpretation Introduction

(a)

Interpretation:

The given equation needs to be expressed in scientific notation.

(4×102)×(1×108)

Concept introduction:

The form of expressing too big or too small numbers into a convenient decimal form is known as Scientific notation.

Expert Solution
Check Mark

Answer to Problem 15PP

(4×102)×(1×108)=(4×1)×102+8=4×1010

Explanation of Solution

Any number can be expressed as number between 1 and 10 that is coefficient and this coefficient is multiplied by 10 raised to the power of the exponent. This whole notation is known as Scientific notation.

Scientific notation for the multiplication is: (4×102)×(1×108)=(4×1)×102+8=4×1010

(b)

Interpretation Introduction

Interpretation:

The given equation needs to be expressed in scientific notation.

(2×104)×(3×102)

Concept introduction:

The form of expressing too big or too small numbers into a convenient decimal form is known as Scientific notation.

(b)

Expert Solution
Check Mark

Answer to Problem 15PP

(2×104)×(3×102)=(2×3)×104+2=6×102

Explanation of Solution

Any number can be expressed as number between 1 and 10 that is coefficient and this coefficient is multiplied by 10 raised to the power of the exponent. This whole notation is known as Scientific notation.

Scientific notation for the multiplication is: (2×104)×(3×102)=(2×3)×104+2=6×102

(c)

Interpretation Introduction

Interpretation:

The given equation needs to be expressed in scientific notation.

(6×102)÷(2×101)

Concept introduction:

The form of expressing too big or too small numbers into a convenient decimal form is known as Scientific notation.

(c)

Expert Solution
Check Mark

Answer to Problem 15PP

(6×102)÷(2×101)=(6÷2)×1021=3×101

Explanation of Solution

Any number can be expressed as number between 1 and 10 that is coefficient and this coefficient is multiplied by 10 raised to the power of the exponent. This whole notation is known as Scientific notation.

Scientific notation for the division is: (6×102)÷(2×101)=(6÷2)×1021=3×101

(d)

Interpretation Introduction

Interpretation:

The given equation needs to be expressed in scientific notation.

(8×104)÷(4×101)

Concept introduction:

The form of expressing too big or too small numbers into a convenient decimal form is known as Scientific notation.

(d)

Expert Solution
Check Mark

Answer to Problem 15PP

(8×104)÷(4×101)=(8÷4)×1041=2×103

Explanation of Solution

Any number can be expressed as number between 1 and 10 that is coefficient and this coefficient is multiplied by 10 raised to the power of the exponent. This whole notation is known as Scientific notation.

Scientific notation for the given division is: (8×104)÷(4×101)=(8÷4)×1041=2×103

Chapter 2 Solutions

Chemistry: Matter and Change

Ch. 2.2 - Prob. 11PPCh. 2.2 - Prob. 12PPCh. 2.2 - Prob. 13PPCh. 2.2 - Prob. 14PPCh. 2.2 - Prob. 15PPCh. 2.2 - Prob. 16PPCh. 2.2 - Prob. 17PPCh. 2.2 - Prob. 18PPCh. 2.2 - Prob. 19PPCh. 2.2 - Prob. 20PPCh. 2.2 - Prob. 21PPCh. 2.2 - Prob. 22PPCh. 2.2 - Prob. 23PPCh. 2.2 - Prob. 24SSCCh. 2.2 - Prob. 25SSCCh. 2.2 - Prob. 26SSCCh. 2.2 - Prob. 27SSCCh. 2.2 - Prob. 28SSCCh. 2.2 - Prob. 29SSCCh. 2.2 - Prob. 30SSCCh. 2.2 - Prob. 31SSCCh. 2.3 - Prob. 32PPCh. 2.3 - Prob. 33PPCh. 2.3 - Prob. 34PPCh. 2.3 - Prob. 35PPCh. 2.3 - Prob. 36PPCh. 2.3 - Prob. 37PPCh. 2.3 - Prob. 38PPCh. 2.3 - Prob. 39PPCh. 2.3 - Prob. 40PPCh. 2.3 - Prob. 41PPCh. 2.3 - Prob. 42PPCh. 2.3 - Prob. 43PPCh. 2.3 - Prob. 44PPCh. 2.3 - Prob. 45SSCCh. 2.3 - Prob. 46SSCCh. 2.3 - Prob. 47SSCCh. 2.3 - Prob. 48SSCCh. 2.3 - Prob. 49SSCCh. 2.3 - Prob. 50SSCCh. 2.3 - Prob. 51SSCCh. 2.4 - Prob. 52SSCCh. 2.4 - Prob. 53SSCCh. 2.4 - Prob. 54SSCCh. 2.4 - Prob. 55SSCCh. 2.4 - Prob. 56SSCCh. 2.4 - Prob. 57SSCCh. 2.4 - Prob. 58SSCCh. 2 - Prob. 59ACh. 2 - Prob. 60ACh. 2 - Prob. 61ACh. 2 - Prob. 62ACh. 2 - Prob. 63ACh. 2 - Prob. 64ACh. 2 - Prob. 65ACh. 2 - Prob. 66ACh. 2 - Prob. 67ACh. 2 - Prob. 68ACh. 2 - Prob. 69ACh. 2 - Prob. 70ACh. 2 - Prob. 71ACh. 2 - Prob. 72ACh. 2 - Prob. 73ACh. 2 - Prob. 74ACh. 2 - Prob. 75ACh. 2 - Prob. 76ACh. 2 - Prob. 77ACh. 2 - Prob. 78ACh. 2 - Prob. 79ACh. 2 - Prob. 80ACh. 2 - Prob. 81ACh. 2 - Prob. 82ACh. 2 - Prob. 83ACh. 2 - Prob. 84ACh. 2 - Prob. 85ACh. 2 - Prob. 86ACh. 2 - Prob. 87ACh. 2 - Prob. 88ACh. 2 - Prob. 89ACh. 2 - Prob. 90ACh. 2 - Prob. 91ACh. 2 - Prob. 92ACh. 2 - Prob. 93ACh. 2 - Prob. 94ACh. 2 - Prob. 95ACh. 2 - Prob. 96ACh. 2 - Prob. 97ACh. 2 - Prob. 98ACh. 2 - Prob. 99ACh. 2 - Prob. 100ACh. 2 - Prob. 101ACh. 2 - Prob. 102ACh. 2 - Prob. 103ACh. 2 - Prob. 104ACh. 2 - Prob. 105ACh. 2 - Prob. 106ACh. 2 - Prob. 107ACh. 2 - Prob. 108ACh. 2 - Prob. 109ACh. 2 - Prob. 110ACh. 2 - Prob. 111ACh. 2 - Prob. 112ACh. 2 - Prob. 113ACh. 2 - Prob. 114ACh. 2 - Prob. 115ACh. 2 - Prob. 116ACh. 2 - Prob. 117ACh. 2 - Prob. 118ACh. 2 - Prob. 119ACh. 2 - Prob. 120ACh. 2 - Prob. 121ACh. 2 - Prob. 122ACh. 2 - Prob. 123ACh. 2 - Prob. 124ACh. 2 - Prob. 125ACh. 2 - Prob. 126ACh. 2 - Prob. 127ACh. 2 - Prob. 128ACh. 2 - Prob. 129ACh. 2 - Prob. 130ACh. 2 - Prob. 1STPCh. 2 - Which value is NOT equivalent to the others? A....Ch. 2 - Prob. 3STPCh. 2 - Prob. 4STPCh. 2 - Prob. 5STPCh. 2 - Prob. 6STPCh. 2 - Prob. 7STPCh. 2 - Prob. 8STPCh. 2 - Prob. 9STPCh. 2 - Prob. 10STPCh. 2 - Prob. 11STPCh. 2 - Prob. 12STPCh. 2 - Prob. 13STPCh. 2 - Prob. 14STPCh. 2 - Prob. 15STPCh. 2 - Prob. 16STPCh. 2 - Prob. 17STPCh. 2 - Prob. 18STPCh. 2 - Prob. 19STPCh. 2 - Prob. 20STP

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