Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN: 9780078746376
Author: Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher: Glencoe/McGraw-Hill School Pub Co
Question
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Chapter 2, Problem 79A

(a)

Interpretation Introduction

Interpretation:

The given multiplication problem needs to be represented in scientific notation.

(4.8×105km)×(2.0×103km)

Concept introduction:

Scientific notation is a term used to express any number as a number between 1 and 10 (termed as coefficient) multiplied by 10 raised to a power (termed as exponent). Scientists express numbers in a scientific notation form.

(a)

Expert Solution
Check Mark

Answer to Problem 79A

The complete multiplication of the given problem is 9.6×108km2.

Explanation of Solution

When multiplying the numbers in scientific notation, add the exponent values. Simply, multiply both numbers and add the exponent values.

(4.8×105km)×(2.0×103km)=(4.8×2.0)×105+3km2=9.6×108km2

(b)

Interpretation Introduction

Interpretation:

The given multiplication problem needs to be completed in scientific notation.

(3.33×104m)×(3.00×105m)

Concept introduction:

Scientific notation is a term used to express any number as a number between 1 and 10 (termed as coefficient) multiplied by 10 raised to a power (termed as exponent). Scientists express numbers in a scientific notation form.

(b)

Expert Solution
Check Mark

Answer to Problem 79A

The complete multiplication of the given problem is 9.99×109m2.

Explanation of Solution

When multiplying the numbers in scientific notation, add the exponent values. Simply, multiply both numbers and add the exponent values.

(3.33×104m)×(3.00×105m)=(3.33×3.00)×1045m2=9.99×109m2

(c)

Interpretation Introduction

Interpretation:

The given multiplication problem needs to be completed in scientific notation.

(1.2×106m)×(1.5×107m)

Concept introduction:

Scientific notation is a term used to express any number as a number between 1 and 10 (termed as coefficient) multiplied by 10 raised to a power (termed as exponent). Scientists express numbers in a scientific notation form.

(c)

Expert Solution
Check Mark

Answer to Problem 79A

The complete multiplication of the given problem is 1.8×101m2.

Explanation of Solution

When multiplying the numbers in scientific notation, add the exponent values. Simply, multiply both numbers and add the exponent values.

(1.2×106m)×(1.5×107m)=(1.2×1.5)×1067m2=1.8×101m2

(d)

Interpretation Introduction

Interpretation:

The given division problem needs to be completed in scientific notation.

(8.42×108kL)÷(4.21×103kL)

Concept introduction:

Scientific notation is a term used to express any number as a number between 1 and 10 (termed as coefficient) multiplied by 10 raised to a power (termed as exponent). Scientists express numbers in a scientific notation form.

(d)

Expert Solution
Check Mark

Answer to Problem 79A

The complete division of the given problem is 2.0×105.

Explanation of Solution

When dividing the numbers in scientific notation, subtract the exponent values. Simply, divide both numbers and subtract the exponent values.

(8.42×108kL)÷(4.21×103kL)=(8.42÷4.21)×1083=2.0×105

(e)

Interpretation Introduction

Interpretation:

The given division problem needs to be completed in scientific notation.

(8.4×106L)÷(2.4×103L)

Concept introduction:

Scientific notation is a term used to express any number as a number between 1 and 10 (termed as coefficient) multiplied by 10 raised to a power (termed as exponent). Scientists express numbers in a scientific notation form.

(e)

Expert Solution
Check Mark

Answer to Problem 79A

The complete division of the given problem is 3.5×109.

Explanation of Solution

When dividing the numbers in scientific notation, subtract the exponent values. Simply, divide both numbers and subtract the exponent values.

(8.4×106L)÷(2.4×103L)=(8.4÷2.4)×106(3)=(8.4÷2.4)×106+3=3.5×109

(f)

Interpretation Introduction

Interpretation:

The given division problem needs to be converted in scientific notation.

(3.3×104mL)÷(1.1×106mL)

Concept introduction:

Scientific notation is a term used to express any number as a number between 1 and 10 (termed as coefficient) multiplied by 10 raised to a power (termed as exponent). Scientists express numbers in a scientific notation form.

(f)

Expert Solution
Check Mark

Answer to Problem 79A

The complete division of the given problem is 3.0×102.

Explanation of Solution

When dividing the numbers in scientific notation, subtract the exponent values. Simply, divide both numbers and subtract the exponent values.

(3.3×104mL)÷(1.1×106mL)=(3.3÷1.1)×104(6)=(3.3÷1.1)×104+6=3.0×102

Chapter 2 Solutions

Chemistry: Matter and Change

Ch. 2.2 - Prob. 11PPCh. 2.2 - Prob. 12PPCh. 2.2 - Prob. 13PPCh. 2.2 - Prob. 14PPCh. 2.2 - Prob. 15PPCh. 2.2 - Prob. 16PPCh. 2.2 - Prob. 17PPCh. 2.2 - Prob. 18PPCh. 2.2 - Prob. 19PPCh. 2.2 - Prob. 20PPCh. 2.2 - Prob. 21PPCh. 2.2 - Prob. 22PPCh. 2.2 - Prob. 23PPCh. 2.2 - Prob. 24SSCCh. 2.2 - Prob. 25SSCCh. 2.2 - Prob. 26SSCCh. 2.2 - Prob. 27SSCCh. 2.2 - Prob. 28SSCCh. 2.2 - Prob. 29SSCCh. 2.2 - Prob. 30SSCCh. 2.2 - Prob. 31SSCCh. 2.3 - Prob. 32PPCh. 2.3 - Prob. 33PPCh. 2.3 - Prob. 34PPCh. 2.3 - Prob. 35PPCh. 2.3 - Prob. 36PPCh. 2.3 - Prob. 37PPCh. 2.3 - Prob. 38PPCh. 2.3 - Prob. 39PPCh. 2.3 - Prob. 40PPCh. 2.3 - Prob. 41PPCh. 2.3 - Prob. 42PPCh. 2.3 - Prob. 43PPCh. 2.3 - Prob. 44PPCh. 2.3 - Prob. 45SSCCh. 2.3 - Prob. 46SSCCh. 2.3 - Prob. 47SSCCh. 2.3 - Prob. 48SSCCh. 2.3 - Prob. 49SSCCh. 2.3 - Prob. 50SSCCh. 2.3 - Prob. 51SSCCh. 2.4 - Prob. 52SSCCh. 2.4 - Prob. 53SSCCh. 2.4 - Prob. 54SSCCh. 2.4 - Prob. 55SSCCh. 2.4 - Prob. 56SSCCh. 2.4 - Prob. 57SSCCh. 2.4 - Prob. 58SSCCh. 2 - Prob. 59ACh. 2 - Prob. 60ACh. 2 - Prob. 61ACh. 2 - Prob. 62ACh. 2 - Prob. 63ACh. 2 - Prob. 64ACh. 2 - Prob. 65ACh. 2 - Prob. 66ACh. 2 - Prob. 67ACh. 2 - Prob. 68ACh. 2 - Prob. 69ACh. 2 - Prob. 70ACh. 2 - Prob. 71ACh. 2 - Prob. 72ACh. 2 - Prob. 73ACh. 2 - Prob. 74ACh. 2 - Prob. 75ACh. 2 - Prob. 76ACh. 2 - Prob. 77ACh. 2 - Prob. 78ACh. 2 - Prob. 79ACh. 2 - Prob. 80ACh. 2 - Prob. 81ACh. 2 - Prob. 82ACh. 2 - Prob. 83ACh. 2 - Prob. 84ACh. 2 - Prob. 85ACh. 2 - Prob. 86ACh. 2 - Prob. 87ACh. 2 - Prob. 88ACh. 2 - Prob. 89ACh. 2 - Prob. 90ACh. 2 - Prob. 91ACh. 2 - Prob. 92ACh. 2 - Prob. 93ACh. 2 - Prob. 94ACh. 2 - Prob. 95ACh. 2 - Prob. 96ACh. 2 - Prob. 97ACh. 2 - Prob. 98ACh. 2 - Prob. 99ACh. 2 - Prob. 100ACh. 2 - Prob. 101ACh. 2 - Prob. 102ACh. 2 - Prob. 103ACh. 2 - Prob. 104ACh. 2 - Prob. 105ACh. 2 - Prob. 106ACh. 2 - Prob. 107ACh. 2 - Prob. 108ACh. 2 - Prob. 109ACh. 2 - Prob. 110ACh. 2 - Prob. 111ACh. 2 - Prob. 112ACh. 2 - Prob. 113ACh. 2 - Prob. 114ACh. 2 - Prob. 115ACh. 2 - Prob. 116ACh. 2 - Prob. 117ACh. 2 - Prob. 118ACh. 2 - Prob. 119ACh. 2 - Prob. 120ACh. 2 - Prob. 121ACh. 2 - Prob. 122ACh. 2 - Prob. 123ACh. 2 - Prob. 124ACh. 2 - Prob. 125ACh. 2 - Prob. 126ACh. 2 - Prob. 127ACh. 2 - Prob. 128ACh. 2 - Prob. 129ACh. 2 - Prob. 130ACh. 2 - Prob. 1STPCh. 2 - Which value is NOT equivalent to the others? A....Ch. 2 - Prob. 3STPCh. 2 - Prob. 4STPCh. 2 - Prob. 5STPCh. 2 - Prob. 6STPCh. 2 - Prob. 7STPCh. 2 - Prob. 8STPCh. 2 - Prob. 9STPCh. 2 - Prob. 10STPCh. 2 - Prob. 11STPCh. 2 - Prob. 12STPCh. 2 - Prob. 13STPCh. 2 - Prob. 14STPCh. 2 - Prob. 15STPCh. 2 - Prob. 16STPCh. 2 - Prob. 17STPCh. 2 - Prob. 18STPCh. 2 - Prob. 19STPCh. 2 - Prob. 20STP
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