Chapter 2, Problem 80A

(a)

Interpretation Introduction

Interpretation:

The given mass $\text{5}\text{.70}\text{g}$ needs to be converted to milligrams.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 80A

$\text{5}\text{.70}\text{g}$ is equal to $5.70\times {10}^3\text{milligrams}$.

Explanation of Solution

To convert $\text{5}\text{.70}\text{g}$ to milligrams, multiply the given value by $1000$ thus,

$5.76\text{g}\times \frac{\text{1000}\text{mg}}{\text{1}\text{g}}=5.70\times {10}^3\text{mg}$

(b)

Interpretation Introduction

Interpretation:

The given value $\text{4}\text{.37}\text{cm}$ needs to be converted to meters.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 80A

$\text{4}\text{.37}\text{cm}$ is equal to $4.37\times {10}^{-2}\text{meters}$.

Explanation of Solution

To convert $\text{4}\text{.37}\text{cm}$ to meters, divide the given value by $100$ thus,

$4.37\text{cm}\times \frac{\text{1}\text{m}}{\text{100}\text{cm}}=4.37\times {10}^{-2}\text{m}$

(c)

Interpretation Introduction

Interpretation:

The given mass $\text{783}\text{kg}$ needs to be converted to grams.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 80A

$\text{783}\text{kg}$ is equal to $7.83\times {10}^5\text{grams}$.

Explanation of Solution

To convert $\text{783}\text{kg}$ to grams, multiply the given value by $1000$ thus,

$\text{783}\text{kg}\times \frac{\text{1000}\text{g}}{\text{1}\text{kg}}=7.83\times {10}^5\text{g}$

(d)

Interpretation Introduction

Interpretation:

The given value $\text{45}\text{.3}\text{mm}$ needs to be converted to meters.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 80A

$\text{45}\text{.3}\text{mm}$ is equal to $45.3\times {10}^{-3}\text{meters}$.

Explanation of Solution

To convert $\text{45}\text{.3}\text{mm}$ to meters, divide the given value by $1000$ thus,

$\text{45}\text{.3}\text{mm}\times \frac{\text{1}\text{m}}{\text{1000}\text{mm}}=45.3\times {10}^{-3}\text{m}$

(e)

Interpretation Introduction

Interpretation:

The given value $\text{10}\text{m}$ needs to be converted to centimeters.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 80A

$\text{10}\text{m}$ is equal to $1000\text{centimeters}$.

Explanation of Solution

To convert $\text{10}\text{m}$ to centimeters, multiply the given value by $100$ thus,

$\text{10}\text{m}\times \frac{\text{100}\text{cm}}{\text{1}\text{m}}=1000\text{cm}$

(f)

Interpretation Introduction

Interpretation:

The given value $\text{37}\text{.5}\text{g/mL}$ needs to be converted to kg/L.

Concept introduction:

Unit conversion is defined as a multi-step process involving division or multiplication by a numerical factor, rounding and selection of correct number of significant digits.

Answer to Problem 80A

$\text{37}\text{.5}\text{g/mL}$ is equal to $\text{37}\text{.5}\text{kg/L}$.

Explanation of Solution

To convert $\text{37}\text{.5}\text{g/mL}$ to kg/L, multiply the given value by 1000 and then divide the value by $1000$

$\frac{\text{37}\text{.5}\text{g}}{\text{mL}}\times \frac{\text{1}\text{kg}}{\text{1000}\text{g}}\times \frac{\text{1000}\text{mL}}{\text{1}\text{L}}=\text{37}\text{.5}\text{kg/L}$