(a)
Interpretation: The 250 g of 0.90 % of NaCl solution mass by mass is given. The number of grams of NaCl required to make the solution needs to be determined.
Concept Introduction: In m/m solution, the number of grams of solute in 100 g of the solution is given. Thus, for 0.90 % NaCl m/m solution, there is 0.90 g of NaCl in 100 g of solution.
(a)
Explanation of Solution
The mass of the solution is given 250 g; thus, the mass of the solute can be calculated as follows:
For 100 g, 0.90 g of NaCl is used.
For 1 g, the number of grams of NaCl used will be:
Thus, for 250 g, the mass of NaCl required will be:
Thus, the mass of NaCl (solute) required will be 2.25 g.
(b)
Interpretation: The mass of
Concept Introduction: The molarity of a solution is defined as the number of moles of solute in 1 L of the solution.
(b)
Explanation of Solution
In the problem, 500 mL of 2.0 M
Putting the values,
Thus, the number of moles of
Or,
Therefore, 101.1 g of
Chapter 21 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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