Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 21, Problem 101A

(a)

Interpretation Introduction

Interpretation: The hydroxide ion concentration of a solution with pH value 7.0 needs to be determined.

Concept Introduction: The pH of the solution is negative log of hydronium ion in the solution. It is related to pOH of the solution as follows:

  pH+pOH=14

Now, pOH is negative log of hydroxide ions in the solution thus, it is represented as follows:

  pOH=logOH

Here, OH is concentration of hydroxide ions in the solution.

(a)

Expert Solution
Check Mark

Explanation of Solution

The given solution has pH value 7.0. The pOH can be calculated as follows:

  pOH=14pH

Or,

  pOH=147=7

Now, from pOH the concentration of hydroxide ions can be calculated as follows:

  OH=10pOH

Substitute the values,

  OH=107

Therefore, the concentration of hydroxide ions will be 1×107 M .

(b)

Interpretation Introduction

Interpretation: The hydroxide ion concentration of a solution with pH value 4.0 needs to be determined.

Concept Introduction: The pH of the solution is negative log of hydronium ion in the solution. It is related to pOH of the solution as follows:

  pH+pOH=14

Now, pOH is negative log of hydroxide ions in the solution thus, it is represented as follows:

  pOH=logOH

Here, OH is concentration of hydroxide ions in the solution.

(b)

Expert Solution
Check Mark

Explanation of Solution

The given solution has pH value 4.0. The pOH can be calculated as follows:

  pOH=14pH

Or,

  pOH=144=10

Now, from pOH the concentration of hydroxide ions can be calculated as follows:

  OH=10pOH

Substitute the values,

  OH=1010

Therefore, the concentration of hydroxide ions will be 1×1010 M .

(c)

Interpretation Introduction

Interpretation: The hydroxide ion concentration of a solution with pH value 9.0 needs to be determined.

Concept Introduction: The pH of the solution is negative log of hydronium ion in the solution. It is related to pOH of the solution as follows:

  pH+pOH=14

Now, pOH is negative log of hydroxide ions in the solution thus, it is represented as follows:

  pOH=logOH

Here, OH is concentration of hydroxide ions in the solution.

(c)

Expert Solution
Check Mark

Explanation of Solution

The given solution has pH value 9.0. The pOH can be calculated as follows:

  pOH=14pH

Or,

  pOH=149=5

Now, from pOH the concentration of hydroxide ions can be calculated as follows:

  OH=10pOH

Substitute the values,

  OH=105

Therefore, the concentration of hydroxide ions will be 1×105 M .

Chapter 21 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 21.2 - Prob. 11SPCh. 21.2 - Prob. 12SPCh. 21.2 - Prob. 13SPCh. 21.2 - Prob. 14LCCh. 21.2 - Prob. 15LCCh. 21.2 - Prob. 16LCCh. 21.2 - Prob. 17LCCh. 21.2 - Prob. 18LCCh. 21.2 - Prob. 19LCCh. 21.3 - Prob. 20LCCh. 21.3 - Prob. 21LCCh. 21.3 - Prob. 22LCCh. 21.3 - Prob. 23LCCh. 21.3 - Prob. 24LCCh. 21.3 - Prob. 25LCCh. 21 - Prob. 26ACh. 21 - Prob. 27ACh. 21 - Prob. 28ACh. 21 - Prob. 29ACh. 21 - Prob. 30ACh. 21 - Prob. 31ACh. 21 - Prob. 32ACh. 21 - Prob. 33ACh. 21 - Prob. 34ACh. 21 - Prob. 35ACh. 21 - Prob. 36ACh. 21 - Prob. 37ACh. 21 - Prob. 38ACh. 21 - Prob. 39ACh. 21 - Prob. 40ACh. 21 - Prob. 41ACh. 21 - Prob. 42ACh. 21 - Prob. 43ACh. 21 - Prob. 44ACh. 21 - Prob. 45ACh. 21 - Prob. 46ACh. 21 - Prob. 47ACh. 21 - Prob. 48ACh. 21 - Prob. 49ACh. 21 - Prob. 50ACh. 21 - Prob. 51ACh. 21 - Prob. 52ACh. 21 - Prob. 53ACh. 21 - Prob. 54ACh. 21 - Prob. 55ACh. 21 - Prob. 56ACh. 21 - Prob. 57ACh. 21 - Prob. 58ACh. 21 - Prob. 59ACh. 21 - Prob. 60ACh. 21 - Prob. 61ACh. 21 - Prob. 62ACh. 21 - Prob. 63ACh. 21 - Prob. 64ACh. 21 - Prob. 65ACh. 21 - Prob. 66ACh. 21 - Prob. 67ACh. 21 - Prob. 68ACh. 21 - Prob. 69ACh. 21 - Prob. 70ACh. 21 - Prob. 71ACh. 21 - Prob. 72ACh. 21 - Prob. 73ACh. 21 - Prob. 74ACh. 21 - Prob. 75ACh. 21 - Prob. 76ACh. 21 - Prob. 77ACh. 21 - Prob. 78ACh. 21 - Prob. 79ACh. 21 - Prob. 80ACh. 21 - Prob. 81ACh. 21 - Prob. 82ACh. 21 - Prob. 83ACh. 21 - Prob. 84ACh. 21 - Prob. 85ACh. 21 - Prob. 86ACh. 21 - Prob. 87ACh. 21 - Prob. 88ACh. 21 - Prob. 89ACh. 21 - Prob. 90ACh. 21 - Prob. 91ACh. 21 - Prob. 92ACh. 21 - Prob. 93ACh. 21 - Prob. 94ACh. 21 - Prob. 95ACh. 21 - Prob. 96ACh. 21 - Prob. 97ACh. 21 - Prob. 98ACh. 21 - Prob. 99ACh. 21 - Prob. 100ACh. 21 - Prob. 101ACh. 21 - Prob. 102ACh. 21 - Prob. 103ACh. 21 - Prob. 104ACh. 21 - Prob. 105ACh. 21 - Prob. 106ACh. 21 - Prob. 1STPCh. 21 - Prob. 2STPCh. 21 - Prob. 3STPCh. 21 - Prob. 4STPCh. 21 - Prob. 5STPCh. 21 - Prob. 6STPCh. 21 - Prob. 7STPCh. 21 - Prob. 8STPCh. 21 - Prob. 9STPCh. 21 - Prob. 10STPCh. 21 - Prob. 11STPCh. 21 - Prob. 12STPCh. 21 - Prob. 13STP
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