(a) The observed frequency of the allele a and A. (b) The observed genotype of Aa , AA , and aa. (c) The expected frequency of the alleles Aa , AA , and aa after one generation of the random mating. Introduction: The Hardy–Weinberg equation can be used to calculate genotypic and allele frequency in a population. These equations are based on the Hardy–Weinberg equilibrium. The equation can be mathematically represented as follows: p + q = 1 p 2 + 2 p q + q 2 = 1 Where, p denotes the dominant allele frequency, q is the recessive allele frequency, p 2 denotes the homozygous dominant individual’s frequency, q 2 denotes the homozygous recessive individual’s frequency, and 2 pq denotes the frequency of the heterozygous individuals. Given: Total number of individuals = 10. Number of individuals having genotype AA = 2. Number of individuals having genotype Aa = 4. Number of individuals having genotype aa = 4.

Question

Want to see the full answer?

Answer 1

Question

Chapter 20.3, Problem 1R

Summary Introduction

To analyze:

(a) The observed frequency of the allele a and A.

(b) The observed genotype of Aa, AA, and aa.

(c) The expected frequency of the alleles Aa, AA, and aa after one generation of the random mating.

Introduction:

The Hardy–Weinberg equation can be used to calculate genotypic and allele frequency in a population. These equations are based on the Hardy–Weinberg equilibrium. The equation can be mathematically represented as follows:

p+q= 1

p2+2pq+q2=1

Where, p denotes the dominant allele frequency, q is the recessive allele frequency, p² denotes the homozygous dominant individual’s frequency, q² denotes the homozygous recessive individual’s frequency, and 2pq denotes the frequency of the heterozygous individuals.
Given:

Total number of individuals = 10.

Number of individuals having genotype AA = 2.

Number of individuals having genotype Aa = 4.

Number of individuals having genotype aa = 4.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

A sample of 100 individuals from a population that is dimorphic at the A locus has genotype counts as follows. AA: 30 Aa: 60 aa: 10 a) What are the allele frequencies in the population? b) What are the expected genotype frequencies, if the population were at HardyWeinberg equilibrium? c) Is the proportion of heterozygotes lower or higher than expected at Hardy-Weinberg equilibrium? What deviations from the assumptions of the model would best explain the observed difference?

In a human population at equilibrium, three genotypes are present in the following proportions: A/A = 0.81, A/a = 0.18, a/a = 0.01. Answer the following questions: What are the frequencies of gene A and gene a? What will their frequencies be in the next generation? What proportion of all marriages in this population is between heterozygotic parents?

A diploid population has 456 individuals of genotype AA, 814 individuals with genotype Aa, and 208 individuals of genotype aa at gene 123 on chromosome six. What are the allele frequencies of this population? Is this population in Hardy-Weinberg equilibrium? If yes, explain how you came to this conclusion. If no, suggest some processes that may have caused a deviation from Hardy-Weinberg processes.