Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 20, Problem 2COQ
Is it possible for a phenotypically normal female fly to be homozygous for a loss-of-function allele in the bicoid gene? What would be the
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In C. elegans, lon-2 and unc-2 are recessive mutations that are 8 map units apart on the X chromosome. An hermaphrodite who is Lon and Unc is mated to a wild-type male. An F1 hermaphrodite is mated to a wild-type male. What are the expected percentages of the different phenotypes among the male progeny?
Termites have a haplo-diploid sex determination system where females develop from a fertilized egg (they are diploid, having one allele from the
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Assuming that the female parent (queen) is heterozygous for a particular gene, what is the probability that a female offspring will inherit the
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O A. The probability that a daughter will inherit a recessive allele from her mother is 50%; the probability that a son will inherit a recessive allele
from his mather is 50%.
OB. Ihe probobility that a daughter will inherit a recessive allele from her mother is 0%; the probability that a son will inherit a recessive allele
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O C. The probability that a daughter will inherit a recessive allele from her mother is…
One reason that worker bees forgo their own reproduction to help their sister (the queen) reproduce is that female bees are more closely related to their sisters than they are to their own offspring. This quirk of genetics results from the fact that bees have haplodiploid sex determination, in which females are diploid, with a mother and a father, but males are haploid, developing from unfertilized eggs. Because males are haploid, they produce sperm by mitosis. Explainwhy haplodiploid sex determination causes females to be more closely related to their sisters than to their offspring.
Chapter 20 Solutions
Biology
Ch. 20.1 - 20.1 General Themes in Development Concept Check:...Ch. 20.1 - Prob. 2CCCh. 20.1 - Prob. 1CSCh. 20.2 - Development in Animals I: Pattern Formation...Ch. 20.2 - Development in Animals I: Pattern Formation...Ch. 20.2 - Prob. 3CCCh. 20.2 - Core Skill: Modeling The goal of this modeling...Ch. 20.2 - Development in Animals I: Pattern Formation Core...Ch. 20.3 - Development in Animals II: Cell Differentiation...Ch. 20.3 - Development in Animals II: Cell Differentiation...
Ch. 20.3 - Development in Animals II: Cell Differentiation...Ch. 20.3 - Development in Animals II: Cell Differentiation...Ch. 20.3 - Development in Animals II: Cell Differentiation...Ch. 20.4 - Development in Plants Concept Check: Where are...Ch. 20.4 - Prob. 2CCCh. 20 - The process whereby a cells morphology and...Ch. 20 - Prob. 2TYCh. 20 - Positional information is important in determining...Ch. 20 - Morphogens are a. molecules that disrupt normal...Ch. 20 - Prob. 5TYCh. 20 - Arrange the following phases of pattern formation...Ch. 20 - Prob. 7TYCh. 20 - Which of the following genes do not play a role in...Ch. 20 - An embryonic stem cell that can give rise to any...Ch. 20 - Prob. 10TYCh. 20 - Prob. 1CQCh. 20 - The MyoD gene in mammals plays a role in muscle...Ch. 20 - Prob. 3CQCh. 20 - Prob. 1COQCh. 20 - Is it possible for a phenotypically normal female...
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- Human sex chromosomes are XX for females and XY for males. a. With respect to an X-linked gene, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele? c. If a female is heterozygous for an X-linked allele, how many different types of gametes can she produce with respect to this allele?arrow_forwardFemale flies with white eyes and miniature wings (both X-linkedrecessive traits) were crossed to male flies with red eyes and longwings. On rare occasions, female offspring were produced withwhite eyes. If we assume these females are due to errors in meiosis, what would be the most likely chromosomal composition ofsuch flies? What would be their wing length?arrow_forwardSex determination in birds is different from that in humans. The sex chromosomes in birds are called Z and W, because males have two of the same chromosome (ZZ), whereas females have two different chromosomes (ZW). There is a Z-linked allele in some birds that causes the death of the embryo when the normal dominant allele is not present. What would be the sex ratio in the living offspring of a cross between a male heterozygous for the lethal allele and a normal female? A) What are the genotypes of the parents? Male____ Female____ B) Which gametes would each form? Male____ Female____ C) Draw your Punnett square below and determine the sex ratios of living offspring.arrow_forward
- In Drosophila, vermilion eye color is due to a recessive allele (v) located on the X chromosome. Curved wings are due to a recessive allele (cu) located on one autosome, and ebony body is due to a recessive allele (e) located on another autosome. A vermilion male is mated to a curved, ebony female, and the F1 males are phenotypically wild-type. If these males were backcrossed to curved, ebony females, what proportion of the F2 offspring will be wild-type males?arrow_forwardIn fruit flies red (A) eyes are dominant to apricot (a) eyes, and normal (P) wings and dominant to pointed (p) wings. Based on the information above, what are the possible gametes that could be produced by a fly that is homozygous for red eyes and heterozygous for normal wings? Group of answer choices: A) AA, Pp B) AP, Ap, aP, ap C) AP, Ap D) AAPparrow_forwardIn fruit flies, L= long wings and l = short wings. When a long-winged fly is crossed with a short winged fly, the offspring exhibit a 1:1 ratio. What is the genotype of the parental flies?arrow_forward
- PURPLE VESTIGIAL DIHYBRID CROSS In the parental generation, you mate a pure-breeding wild-type female (put/pu+;vg+/vg+) with a pure-breeding purple, vestigial (pu/pu;vg/vg) to produce an F1 generation that is all wild-type (pu*/pu;vg+/vg). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (pu*/pu;vg+/vg) with tester males, which are purple, vestigial (pu/pu;vg/vg). The offspring of this dihybrid testcross are: Phenotype Genotype Tester Gamete Dihybrid Gamete Number Wild-type 437 417 77 59 Purple, vestigial Vestigial Purple Copy the table into your notes and derive the dihybrid gametes following the example in the first section. The columns in blue (phenotypes and numbers of offspring) are what you can see and count. The genotypes of the testcross offspring (orange) must be deduced from the phenotypes and knowing that the tester contributed pu vg gametes. Finally, you can deduce the dihybrid gametes (green) by subtracting the tester gamete contribution…arrow_forwardIn humans, the mic2 gene (involved in antibody production) is found on sex chromosomes and has pseudoautosomal inheritance. If a female that is a mic2a is mated to a phenotypically mic2b male then what would be resulting ratios of the offspring? (note; the mic2a and 2b alleles are codominant) O 50% mic2a and 50% mic2b for both sexes O 100% mic2a/2b for both males and females O all females are mic2a/2b whereas males are all mic2a all females are mic2b whereas males are all mic2aarrow_forwardIn Drosophila, a fully heterozygous female with the X-linked recessive genes a, b, and c (not necessarily in that order on the chromosome) was mated to a male that was genetically a, b, c (not necessarily in that order on the chromosome). The offspring occurred in the following phenotypic ratios: Phenotypes: Numbers: What is the cis/trans arrangement in the heterozygous parent? Wild 426 а, с, b 428 Which gene is in the middle? a 23 c, b 22 If you added 23, 22, 3, and 2, it would give you the map distance between genes C 49 b, a 46 What calculation would you make to determine if interference was occurring? (you don't have to complete the calculation) b. C, a Total 1000 3.arrow_forward
- Let’s suppose that a gene affecting pigmentation is found on the Xchromosome (in mammals or insects) or the Z chromosome (in birds)but not on the Y or W chromosome. It is found on an autosome inbees. This gene exists in two alleles: D (dark) is dominant to d (light).What would be the phenotypic results of crosses between true-breedingdark females and true-breeding light males, and the reciprocal crossesinvolving true-breeding light females and true-breeding dark males,in the following species? Refer back to Figures 4.1 and 4.2 for themechanism of sex determination in these species.A. BirdsB. Fruit fliesC. BeesD. Humansarrow_forwardIn Drosophila, singed bristles (sn) and cut wings (ct) are both caused by recessive, X-linked alleles. The wild type alleles (sn+ and ct+) are responsible for straight bristles and intact wings, respectively. A female homozygous for sn+ and ct+ is crossed to a sn ct male. The F1 flies are interbred. The F2 males are distributed as follows sn ct 36 sn ct+ 13 sn+ ct 12 sn+ ct+ 39 What is the map distance between sn and ct?arrow_forwardDrosophila have XX/XY sex determination systems just like mammals. In Drosophila, loci for both eye color and body color are on the X chromosome. Red eye color (R) is dominant to white eye color (r), and tan body color (T) is dominant to yellow body color (t). Which of the following is the genotype for a female with a yellow body and red eyes, who is homozygous for eye color? Group of answer choices XRT XrT XRt XRT XRt XRt XRt XRTarrow_forward
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