Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
7th Edition
ISBN: 9780199339136
Author: Adel S. Sedra, Kenneth C. Smith
Publisher: Oxford University Press
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Chapter 2, Problem 2.21P
To determine
The value of maximum voltage by which the “virtual ground concept” departs from its ideal value.
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11)This multiple choice question from MEASUREMENTS INSTRUMENTATIONS course.
Figure Q2(a) shows an amplifier system with the given input voltagewaveform Vin and the corresponding output voltage waveform Vout.
Predict what will happen to the output voltage waveform if the op-ampis given a voltage supply of VCC = +14 V and VEE = -14 V.
For the op-amp shown in the following figure, the unity-gain bandwidth has the value of 20.5 KHz. The amplifier bandwidth is
equal to
Chapter 2 Solutions
Microelectronic Circuits (The Oxford Series in Electrical and Computer Engineering) 7th edition
Ch. 2.1 - Prob. 2.1ECh. 2.1 - Prob. 2.2ECh. 2.1 - Prob. 2.3ECh. 2.2 - Prob. D2.4ECh. 2.2 - Prob. 2.5ECh. 2.2 - Prob. 2.6ECh. 2.2 - Prob. D2.7ECh. 2.2 - Prob. D2.8ECh. 2.3 - Prob. 2.9ECh. 2.3 - Prob. 2.10E
Ch. 2.3 - Prob. D2.11ECh. 2.3 - Prob. 2.12ECh. 2.3 - Prob. 2.13ECh. 2.3 - Prob. 2.14ECh. 2.4 - Prob. 2.15ECh. 2.4 - Prob. D2.16ECh. 2.4 - Prob. 2.17ECh. 2.5 - Prob. 2.18ECh. 2.5 - Prob. D2.19ECh. 2.5 - Prob. D2.20ECh. 2.6 - Prob. 2.21ECh. 2.6 - Prob. 2.22ECh. 2.6 - Prob. 2.23ECh. 2.6 - Prob. 2.24ECh. 2.6 - Prob. 2.25ECh. 2.7 - Prob. 2.26ECh. 2.7 - Prob. 2.27ECh. 2.7 - Prob. 2.28ECh. 2.8 - Prob. 2.29ECh. 2.8 - Prob. 2.30ECh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. D2.12PCh. 2 - Prob. D2.13PCh. 2 - Prob. D2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. D2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. D2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. D2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. D2.33PCh. 2 - Prob. D2.34PCh. 2 - Prob. D2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. D2.37PCh. 2 - Prob. D2.38PCh. 2 - Prob. D2.39PCh. 2 - Prob. D2.40PCh. 2 - Prob. D2.41PCh. 2 - Prob. D2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. D2.44PCh. 2 - Prob. D2.45PCh. 2 - Prob. D2.46PCh. 2 - Prob. D2.47PCh. 2 - Prob. D2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. D2.51PCh. 2 - Prob. D2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. D2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. D2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. D2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. D2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. D2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. D2.76PCh. 2 - Prob. 2.77PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. D2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. D2.82PCh. 2 - Prob. D2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. D2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. D2.92PCh. 2 - Prob. D2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. D2.99PCh. 2 - Prob. D2.100PCh. 2 - Prob. 2.101PCh. 2 - Prob. 2.102PCh. 2 - Prob. 2.103PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.105PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.107PCh. 2 - Prob. 2.108PCh. 2 - Prob. 2.109PCh. 2 - Prob. 2.110PCh. 2 - Prob. 2.111PCh. 2 - Prob. 2.112PCh. 2 - Prob. 2.113PCh. 2 - Prob. 2.114PCh. 2 - Prob. 2.115PCh. 2 - Prob. D2.116PCh. 2 - Prob. D2.117PCh. 2 - Prob. D2.118PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.120PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.122PCh. 2 - Prob. 2.123PCh. 2 - Prob. 2.124PCh. 2 - Prob. 2.125PCh. 2 - Prob. 2.126PCh. 2 - Prob. D2.127P
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- By using only two op-amps, design a circuit that can perform the following operation: Vo == Also, evaluate the given circuit equation. Show all the assumptions, calculation and the circuit illustration. Marking Scheme: Circuit Design Assumptions Calculationarrow_forward1) Op-amp limiting factors - Current Saturation U2 Vin R1 OUT OPAMP R2 RLoad The saturation output current for the above op-amp is +/- 15mA. For the following input signals, determine if the output appears as would be expected in an ideal circuit. Include sketches of the output voltage. a) R1 = 100, R2 = 900, an open circuit load, and Vin is 2Vpp triangle wave with zero offset voltage (Vmax 1V, Vmin = -1V) and a period of 2ms. b) R1 = 100, R2 = 900, a 1k load, and Vin is 2Vpp triangle wave with a 1V offset voltage (Vmax=2V, Vmin = 0V) and a period of 2ms. c) R1 = 100, R2 = 900, an open circuit load, and Vin is 4Vpp triangle wave with zero offset voltage (Vmax=2V, Vmin = -2V) and a period of 2ms.arrow_forwardDesign an op-amp circuit that can perform this operation: Vo = 2V1V2 – 3V3. Marking Scheme: 1. Circuit Diagram 2. Calculation with Assumptionsarrow_forward
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- +Vcc Vin VI Vo Vref VN -Vcc Ry RxL Figure Q.A2(e). Inverting Schmitt-trigger circuit. (ii) The operational-amplifier (op-amp) of the inverting Schmitt-trigger in Figure Q.A2(e) has saturation voltages of +Vsat = +11 V and -Vsat = -11 V. The voltage divider circuit has the relationship of Rx = 2RY with the value of RY being 100 kn. Using the relationships derived above: (a) Calculate the values of the upper threshold point (UTP or Vi*), lower threshold point (LTP or Vr). (b) Now, sketch the input-output characteristic of the inverting Schmitt- trigger. Clearly label axes, the threshold voltages and the saturation voltages in your sketch.arrow_forwardAnswer the following questions a) What assumption do we make for an ideal op - amp? b) Explain what slew rate is why it is important characteristic for an op amp.arrow_forwardExplain in your wordsarrow_forward
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