Human Biology (MindTap Course List)
11th Edition
ISBN: 9781305112100
Author: Cecie Starr, Beverly McMillan
Publisher: Cengage Learning
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Chapter 19, Problem 4CT
The young woman shown at right has albinism—very pale skin, white hair, and pale blue eyes. This phenotype is due to the absence of melanin, which imparts color to the skin, hair, and eyes. It typically is caused by a recessive allele. In the following situations, what are the probable genotypes of the father, the mother, and their children?
- a. Both parents have normal
phenotypes ; some of their children are albino and others are not. - b. Both parents and all their children are albino.
- c. The mother is not albino, the father is albino, and one of their four children is albino.
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A homozygous recessive allele, aa, is responsible for albinism. Humans can exhibit this phenotype. In each
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The allele for albinism is recessive to the allele for normal skin pigmentation. All individuals who are homozygous for this recessive allele (m) are unable to produce the enzyme needed for melanin production and are referred to as albinos. In the following statements, determine the correct genotypes: An albino male (genotype A) whose parents both have normal skin pigmentation (genotype B) marries a woman who does not have albinism (genotype C). This woman’s father is an albino (genotype D). The married couple has three children, two with normal skin pigmentation (genotype E) and one exhibiting albinism (genotype F)
Albinism causes the skin, hair, or eyes to have little or no color. It is also associated with vision problems. Albinism results from an allele a that is recessive to the allele for normal melanin production. Maya has normal skin color, but her sister has albinism. Maya’s mother has albinism, and her father has normal skin color.
a)What are the genotypes of Maya, her sister, her mother, and her father.
b)If Maya’s parents have another child, what is the probability that this child will have albinism? Show the Punnett square you use to help in solving.
c)If Maya marries a man with albinism, what is the probability that their first child will have albinism? Show the Punnett square you use to help in solving.
Chapter 19 Solutions
Human Biology (MindTap Course List)
Ch. 19 - Define the difference between (a) gene and allele,...Ch. 19 - Prob. 2RQCh. 19 - What is probability, and how is it applied in...Ch. 19 - What is independent assortment? Does independent...Ch. 19 - Alleles are ___________. a. alternate forms of a...Ch. 19 - A heterozygote has _____. a. only one of the...Ch. 19 - Prob. 3SQCh. 19 - Offspring of a cross AA aa are ______. a. all AA...Ch. 19 - Prob. 5SQCh. 19 - Prob. 6SQ
Ch. 19 - Which statement best fits the principle of...Ch. 19 - Prob. 8SQCh. 19 - Prob. 9SQCh. 19 - Prob. 10SQCh. 19 - One gene has alleles A and a. Another has alleles...Ch. 19 - Still referring to Problem 1, what will be the...Ch. 19 - Go back to Problem 1, and assume you now study a...Ch. 19 - The young woman shown at right has albinismvery...Ch. 19 - When you decide to breed your Labrador retriever...Ch. 19 - The ABO blood system has been used to settle cases...Ch. 19 - Prob. 7CTCh. 19 - A man is homozygous dominant for ten different...Ch. 19 - Prob. 9CTCh. 19 - Bill and Marie each have flat feet, long...Ch. 19 - You decide to breed a pair of guinea pigs, one...
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- X‑linked, recessive diseases, such as hemophilia, are extremely rare in the population. However, many women are carriers and show no sign of the disease. The pedigree illustrates the inheritance of an X‑linked, recessive disease. Determine whether the unknown individuals are affected by the disease, unaffected by the disease, or carriers of the X‑linked recessive allele. Unaffected individuals are not carriers of the X‑linked recessive allele.arrow_forwardThe allele for albinism ( c ) is recessive to the allele for normal pigmentation ( C ). A normally pigmented woman whose father is an albino marries an albino man whose parents are normal. They have three children, two normal and one albino. Give the genotypes for EACH person listed.arrow_forwardEpilepsy is a central nervous system (neurological) disorder in which brain activity becomes abnormal, causing seizures or periods of unusual behavior, sensations and sometimes loss of awareness. For epilepsy, the concordance values are 72% for monozygotic twins and 15% for dizygotic twins. 1) Is this a single gene inheritance or multifactorial disease? 2) Is there a strong genetic or environmental cause to the development of this disease? If both genetic and environmental causes are implicated, you have to indicate each of them separately.arrow_forward
- In humans, the allele for normal blood clotting (H) is dominant to the allele for hemophilia. This is a sex-linked trait found on the X chromosome. A woman with normal blood clotting has four children: a normal son, a hemophiliac son, and two normal daughters. The father has normal blood clotting. What is the probable genotype for each member of the family?arrow_forwardFor a recessive condition, two normal heterozygous individuals have children. What is the likelihood of their children being affected by this condition? What is the likelihood of their children being carriers without the condition? What is the likelihood of their asymptomatic children being carriers? Suppose that an individual with the condition has children with a heterozygous individual, what is the likelihood of their children being carriers?arrow_forwardThe gene for polydactyly (P) is autosomal and dominant to normal fingers (p). Hemophilia is sex-linked and recessive (X h ). A man and his wife both of whom are polydactylous and have normal red blood cells have a child who is non-polydactylous and with hemophilia. What are their genotypes?arrow_forward
- 1. A) Apply the concept of sex linkage to explain why color blindness is more prevalent in men than in women. B) Mary is concerned that she may be a carrier for hemophilia, a sex-linked condition located on the X chromosome. Mary is married to John, who doesn't have hemophilia. Assuming Mary is a carrier, what are the genotype ratios expected for Mary and John's kids (specify for boys and for girls)? C) Mary and John have 2 boys, none of them has hemophilia. Can we use this fact as proof that Mary does not carry the allele for hemophilia? Explain your argument.arrow_forwardA gene that controls the ability to see red and green is located on the X chromosome but not on the Y chromosome. There is a recessive nonfunctional allele for this gene that can cause red-green color blindness if the person possessing it does not also have the dominant normal gene. Consider the case of a carrier mother who is heterozygous for the red-green vision gene and a father who has normal vision. Use XB = normal vision, Xb = color-blind vision. What is the chance the parents would have a color-blind boy? A color-blind girl? What about a girl or boy with normal vision? Redo the Punnett square for a carrier mother (XBXb) and a color-blind father (XbY). Do the chances of having color-blind children change? How?arrow_forwardCystic fibrosis in humans is caused by a recessive allele. A man is known to be a carrier of the cystic fibrosis allele. He marries a phenotypically normal woman. In the general population, the incidence of cystic fibrosis at birth is approximately 1 in 1,700. Assume Hardy-Weinberg proportions. What is the probability that the wife is also a carrier? Answer in decimal number only (three decimal places; example: 0.123). What is the probability that their first child will be affected? Answer in decimal number only (three decimal places; example: 0.123).arrow_forward
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