The gene for polydactyly (P) is autosomal and dominant to normal fingers (p). Hemophilia is sex-linked and recessive (X h ). A man and his wife both of whom are polydactylous and have normal red blood cells have a child who is non-polydactylous and with hemophilia. What are their genotypes?

Hemophilia, disease in which the blood lacks a clotting factor, is caused by an X linked recessive gene. Joe doe not have hemophilia and Lucille is heterozygous for the condition.  What is the chance that their MALE child will have hemophilia? (Note: you are calculating the probability for their MALE children only, in other words if they have 1 male child, what is the probability that he will be born with the disease?)     0%     1/4 or 25%     2/4 or 50%     3/4 or 75%     4/4 or 100%

Achondroplasia,is characterized by difficulty converting cartilage to bone and thus results in shortened limbs. This trait is autosomal dominant. (A = achondroplasia allele; a = average height allele.) A husband and wife both have achondroplasia. The couple have a total 12 living children: 6 boys and 6 girls.  The husband is colorblind, which is an X-linked recessive trait, and the wife believes there is a chance she is a carrier of colorblindness, since that trait runs in her family. One of the couple’s daughters and three of their sons are colorblind.  (Xc = colorblindness allele; XC = normal color vision allele.) a) Please list all of the different gametes that the husband can produce. b) Please list all of the different gametes that the wife can produce.

Albinism, lack of pigmentation in humans, results from an autosomal recessive gene designated a. Two parents with normal pigmentation have an albino child. What is the probability that their next child will be albino? What is the probability that the next child will be an albino girl? If the child is normal, what is the probability that it will be a carrier (heterozygous) for the albino gene?

Cystic fibrosis in humans is caused by mutations in a single gene and is inherited as an autosomal (non-sex chromosome) recessive trait. An unaffected couple has two children. The first child has cystic fibrosis, and the second child is unaffected. What is the probability that the second child is a carrier (heterozygous) for the mutation that causes the disease? 2/3 1 1/2 3/4

Label all individuals with the correct genotype. If you are not certain of the gentotype, list all possible geneotypes with their associated probabilities (based on the genotypes of their parents)

A woman with normal blood clotting mates with a man who has hemophilia. Their first child is a boy who has hemophilia. Tests show that the father and son both have the same form of hemophilia, that it is X-linked recessive, and that the boy has normal genetic inheritance. You can predict that if the couple produces more children together, then the odds are that: Select one: O a. All of the children will have hemophilia. b. Half of the boys and half of the girls will have hemophilia. O C. None of the rest of the children should have hemophilia. O d. Half of the boys and none of the girls will have hemophilia.

Hypophosphatemia (vitamin D-resistant rickets) is inherited as a sex-linked dominant trait (H). A) A normal woman and a man with hypophosphatemia marry. What is the chance of having daughters with rickets? Sons? B) A heterozygous woman and a normal man marry. Does the mother have rickets? What is the chance of having daughters with rickets? Sons?

In humans, blue eyes are inherited as a recessive autosomal trait and color blindness is an X-linked recessive trait.  A woman with blue eyes and normal color vision (her father was colorblind) marries a man who has normal color vision.  The man has brown eyes, but his mother had blue eyes.  What is the probability that this couple will have a child with normal vision and blue eyes?

A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?