Human Biology (MindTap Course List)
11th Edition
ISBN: 9781305112100
Author: Cecie Starr, Beverly McMillan
Publisher: Cengage Learning
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Chapter 19, Problem 5CT
When you decide to breed your Labrador retriever Molly and sell the puppies, you discover that two of Molly’s four siblings have developed a hip disorder that is traceable to the action of a single recessive allele. Molly herself shows no sign of the disorder. If you breed Molly to a male Labrador that does not carry the recessive allele, can you assure a purchaser that the puppies will also be free of the condition? Explain your answer.
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YOUR SISTER DIED FROM TAY-SACHS DISEASE, INHERITED AS A RECESSIVE ALLELE (t). you're married and planning to start your family. you're worried about the disease and decide to have genetic testing to see if you or your spouse is a carrier of the tay-sachs allele. the test results show that you're a carrier of the allele, but your spouse isn't. what is the probability that you and your spouse will have a child with tay-sachs disease? show your work.
You are studying three traits in a goldfish variety; body colour (A or a), tail length (B or b) and shape (C or c).
Note: Use the uppercase letters for the alleles associated with the dominant phenotypes and the lowercase letters for the alleles associated with the recessive phenotypes. Assume that each of these traits is regulated by one gene.
Photo credit https://www.petmd.com
Part A. You mate a gold fish (P1) with a white fish (P2) and obtain 100 fish in F1, of which 50 are gold and 50 are white. Write two sets of the possible genotypes of the parental and the resulting F1 fish by filling in the table below.
Sets
P1
P2
F1 gold fish
F1 white fish
1
2
Part B. You cross a true breeding gold fish having long curly tail (P3) with a true breeding gold fish having short and straight tail (P4). All of the resulting F1 fish have long straight tails.
Write the genotype of the parental fish (P3 and P4) using the outlined nomenclature.…
As seen in the photo, Labradors come in three colors-- black, brown and yellow. What is the genetic basis for these different coat colors? One gene produces melanin, a pigment which is deposited in the dog's fur and makes the color dark. With this gene, allele B (black) is dominant to allele b. Only in the case of a recessive homozygote (bb) will the dog's phenotype be brown. The regulatory gene is separate from the melanin gene but it acts as a switch, either turning the melanin gene on or turning it off. Allele E is dominant and allows for the melanin to be deposited in the dog's fur ("on" switch), but if the switch gene is a recessive homozygote, the melanin is blocked ("off" switch) and a yellow dog is the result!
1. Two other Labradors mate and produce puppies. Their genotypes are Bbee and BbEe. What color are each parent and what are the phenotypic rations of their offspring in the F1 Generation? Show your work with a Punnett square.
Chapter 19 Solutions
Human Biology (MindTap Course List)
Ch. 19 - Define the difference between (a) gene and allele,...Ch. 19 - Prob. 2RQCh. 19 - What is probability, and how is it applied in...Ch. 19 - What is independent assortment? Does independent...Ch. 19 - Alleles are ___________. a. alternate forms of a...Ch. 19 - A heterozygote has _____. a. only one of the...Ch. 19 - Prob. 3SQCh. 19 - Offspring of a cross AA aa are ______. a. all AA...Ch. 19 - Prob. 5SQCh. 19 - Prob. 6SQ
Ch. 19 - Which statement best fits the principle of...Ch. 19 - Prob. 8SQCh. 19 - Prob. 9SQCh. 19 - Prob. 10SQCh. 19 - One gene has alleles A and a. Another has alleles...Ch. 19 - Still referring to Problem 1, what will be the...Ch. 19 - Go back to Problem 1, and assume you now study a...Ch. 19 - The young woman shown at right has albinismvery...Ch. 19 - When you decide to breed your Labrador retriever...Ch. 19 - The ABO blood system has been used to settle cases...Ch. 19 - Prob. 7CTCh. 19 - A man is homozygous dominant for ten different...Ch. 19 - Prob. 9CTCh. 19 - Bill and Marie each have flat feet, long...Ch. 19 - You decide to breed a pair of guinea pigs, one...
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