Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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For a recessive condition, two normal heterozygous individuals have children.
- What is the likelihood of their children being affected by this condition?
- What is the likelihood of their children being carriers without the condition?
- What is the likelihood of their asymptomatic children being carriers?
- Suppose that an individual with the condition has children with a heterozygous individual, what is the likelihood of their children being carriers?
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- Explain the following features of the Mendelian traits and fill the Punnet Squares. a)The disappearance of recessive phenotype in the F1 generation. b)The genotype of an individual expressing dominant phenotype can be differentiated by the test cross.arrow_forwardHemophilia, disease in which the blood lacks a clotting factor, is caused by an X linked recessive gene. Joe doe not have hemophilia and Lucille is heterozygous for the condition. What is the chance that their MALE child will have hemophilia? (Note: you are calculating the probability for their MALE children only, in other words if they have 1 male child, what is the probability that he will be born with the disease?) 0% 1/4 or 25% 2/4 or 50% 3/4 or 75% 4/4 or 100%arrow_forwardA certain type of deafness in humans is inherited as an X-linked recessive trait. A man with this type of deafness married a normal woman, and they are expecting a child. They find out that they are distantly related. Part of the family tree is shown here.How would you advise the parents about the probability of their child being a deaf boy, a deaf girl, a normal boy, or a normal girl? Be sure to state any assumptions that you make.arrow_forward
- Freckles is determined by a single gene and having freckles is dominant over not having freckles. If a man with freckles and a woman without freckles have a child that does not have freckles then a)the man is heterozygous for the freckles gene. b)the child is heterozygous for the freckles gene. c)the woman and man are both heterozygous for the freckles gene. d) the woman is heterozygous for the freckles genarrow_forwardIn humans, one type of red-green colorblindness (n) is sex-linked and recessive. A) A woman who is a carrier marries a man with normal vision. What is the chance of having color-blind daughters? Color-blind sons? B) A heterozygous woman and a color-blind man marry. What is the chance of having color-blind daughters? Color-blind sons?arrow_forwardIn humans, albinism (lack of skin pigment) is an autosomal recessive trait. The first child of two normally pigmented parents is an albino. Which of the following is true about this family? SELECT ALL THAT ARE CORRECT. A) Their first child (described above) has a homozygous recessive genotype B) The next child born to this couple has a 25% chance of being albino. C) If the next child born to this couple is male, he has a greater chance of being albino. D) The parents are both heterozygous for albinism. E) The probability of their second child being albino is 0% F) If the second and third child born to this couple are albino, the fourth child has 100% chance of also being albino.arrow_forward
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