Chapter 1.9, Problem 11PSB

To determine

The probability that second hand of the clock is between

  $7\text{ and 12}$ .

Answer to Problem 11PSB

  $Probabilitythatsecondhandisbetween7and12= \frac{1}{3}$

Explanation of Solution

Given second hand of the clock sweeps continuously around the face of the clock.

Formula used:

  $\begin{array}{l}Probabilityofaevent=\frac{possiblenumberofoutcomes}{totalnumberofoutcomes}\\ \end{array}$

Calculation:

A clock shows 12 hours

So, total number of outcomes is 12

Possible number of outcomes between 7 and 12 is 4

  $\begin{array}{l}Probabilityofaevent=\frac{possiblenumberofoutcomes}{totalnumberofoutcomes}\\ \end{array}$

P (Second hand is between 7 and 12) = $\frac{4}{\begin{array}{l}12\\ \end{array}}$ = $\frac{1}{3}$