Chapter 1.5, Problem 3PSA

Solution

a.

To Find: The angle bisector .

  $\overline{JG}$ is the angle bisector of angle FJH.

Given:

  

Concept Used:

Bisector of angle divides the angle into two equal parts.

Calculation:

Here, we have

  $\begin{array}{l}m\angle FJG=m\angle HJG\\ \Rightarrow \overline{JG}\text{ is the angle bisector of }\angle FJH\end{array}$

Conclusion:

  $\overline{JG}\text{ is the angle bisector of }\angle FJH$

b.

To Find: The angle bisector .

  $\overline{OK}\text{ is the angle bisector of }\angle POM$

Given:

  

  $m\angle POK=m\angle MOK$

Concept Used:

Bisector of angle divides the angle into two equal parts.

Calculation:

Here, we have

  $\begin{array}{l}m\angle POK=m\angle MOK\\ \Rightarrow \overline{OK}\text{ is the angle bisector of }\angle POM\end{array}$

Conclusion:

  $\overline{OK}\text{ is the angle bisector of }\angle POM$