Chapter 1.2, Problem 10PSA

a.

To determine

To find: The PQ.

Answer to Problem 10PSA

PQ $=5$ .

Explanation of Solution

Given information:

A figure is given as below.

  

Calculation:

A figure is given as below.

  

From above figure PQ is the distance between points P and Q.

So, $PQ=3-(-2)=5$ .

b.

To determine

To find: If $PQ\cong QR$ .

Answer to Problem 10PSA

  $PQ\ne QR$ .

Explanation of Solution

Given information:

Same as part $a$ of this exercise.

Calculation:

A figure is given as below.

  

From above figure PQ is the distance between points P and Q.

So, $PQ=3-(-2)=5$ .

Similarly, $QR=7-3=4$ .

(as coordinate of R is $7$ ).

Thus $PQ\ne QR$ .

c.

To determine

To find: What should be the value of R so Q is the midpoint of PR.

Answer to Problem 10PSA

  $8$ .

Explanation of Solution

Given information:

Same as part $a$ of this exercise.

Calculation:

A figure is given as below.

  

From above figure PQ is the distance between points P and Q.

So, $PQ=3-(-2)=5$ .

For Q to be midpoint of PR, $PQ$ should be equal to $QR$ .

Thus, coordinate of R must be $8$ .