Chapter 1.3, Problem 13PSB

a.

To determine

To Find: The number by which AC is smaller.

Answer to Problem 13PSB

  $AC<15$

Explanation of Solution

Given:

  

Concept Used:

Sum of two sides is greater than third side.

Calculation:

Here, we have

  $\begin{array}{l}AB=6,BC=9\\ \Rightarrow AB+BC>AC\\ \Rightarrow 6+9>AC\\ AC<15\end{array}$

Conclusion:

  $AC<15$

b.

To determine

To Find: The number by which AC is greater.

Answer to Problem 13PSB

  $AC>3$

Explanation of Solution

Given:

  

Concept Used:

Sum of two sides is greater than third side.

Calculation:

Here, we have

  $\begin{array}{l}AB=6,BC=9\\ \Rightarrow AC>3\end{array}$

Conclusion:

  $AC>3$