Integrated Science
Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 18, Problem 8PEA
To determine

The speed of longshore current.

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A submarine dives down to a depth 80 metres beneath the surface of the ocean. Calculate the pressure in atmospheres at that depth, assuming the density of water is 1029 kg/m3, and the air pressure at the surface is 105.2 kPa. Give your answer with two digits of precision. Note: 1 standard atmosphere is 101325 Pa. Your Answer: Answer
"A standard 1 kilogram weight is a cylinder 48.5 mm in height and 44.5 mm in diameter. What is the density of the material in kg/m^3 ?"I keep trying this problem and it's just a practice problem and the program is telling me the answer is 13300 kg/m^3, but I'd like to see it worked out in full so I can figure it out for myself. My answers are similar so I think I might just be making rounding errors.
The density of the atmosphere varies drastically with height, but you can use an average density from sea floor to the space in order to calculate its height. If we approximate this average density to be = 1 Kg/m³, what would be height of the atmosphere? HINT: Since the atmosphere is a fluid (in gas form), you can use the hydrostatic pressure formula (P pgh), just solve for h and use P = 1 atm. BTW, this is how the edge of space is defined, if you make it pass the height of the atmosphere you have reached space :)
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