Chapter 18, Problem 67A

(a)

Interpretation Introduction

Interpretation: Weather reactant or product favored at equilibrium for the reaction ${\text{H}}_{\text{2}}\left(g\right)+{\text{F}}_2\left(g\right)\rightleftharpoons 2\text{HF}\left(g\right);K_{\text{eq}}=1\times {10}^{13}$ is to be predicted.

Concept Introduction: When the equilibrium constant $\left(K_{\text{eq}}\right)$ is more than $1$ , products are favored over reactants. When $K_{\text{eq}}$ is less than $1$ , reactants are favored over products.

Answer to Problem 67A

The product is favored over the reactant at equilibrium for the reaction.

Explanation of Solution

The given reaction is as follows:

  ${\text{H}}_{\text{2}}\left(g\right)+{\text{F}}_2\left(g\right)\rightleftharpoons 2\text{HF}\left(g\right)$

The equilibrium constant is $1\times {10}^{13}$ .

Since $K_{\text{eq}}$ is greater than $1$ , the products are favored over the reactants at equilibrium in this reaction.

(b)

Interpretation Introduction

Interpretation: Weather reactant or product favored at equilibrium for the reaction ${\text{SO}}_{\text{2}}\left(g\right)+{\text{NO}}_2\left(g\right)\rightleftharpoons \text{NO}\left(g\right)+{\text{SO}}_3\left(g\right);K_{\text{eq}}=1\times {10}^2$ is to be predicted.

Concept Introduction: When the equilibrium constant $\left(K_{\text{eq}}\right)$ is more than $1$ , products are favored over reactants. When $K_{\text{eq}}$ is less than $1$ , reactants are favored over products.

Answer to Problem 67A

The product is favored over the reactant at equilibrium for the reaction.

Explanation of Solution

The given reaction is as follows:

  ${\text{SO}}_{\text{2}}\left(g\right)+{\text{NO}}_2\left(g\right)\rightleftharpoons \text{NO}\left(g\right)+{\text{SO}}_3\left(g\right)$

The equilibrium constant is $1\times {10}^2$ .

Since $K_{\text{eq}}$ is greater than $1$ , the products are favored over the reactants at equilibrium in this reaction.

(c)

Interpretation Introduction

Interpretation: Weather reactant or product favored at equilibrium for the reaction ${\text{2H}}_{\text{2}}\text{O}\left(g\right)\rightleftharpoons 2{\text{H}}_{\text{2}}\left(g\right)+{\text{O}}_2\left(g\right);K_{\text{eq}}=6\times {10}^{-28}$ is to be predicted.

Concept Introduction: When the equilibrium constant $\left(K_{\text{eq}}\right)$ is more than $1$ , products are favored over reactants. When $K_{\text{eq}}$ is less than $1$ , reactants are favored over products.

Answer to Problem 67A

The reactant is favored over the product at equilibrium for the reaction.

Explanation of Solution

The given reaction is as follows:

  ${\text{2H}}_{\text{2}}\text{O}\left(g\right)\rightleftharpoons 2{\text{H}}_{\text{2}}\left(g\right)+{\text{O}}_2\left(g\right)$

The equilibrium constant is $6\times {10}^{-28}$ .

Since $K_{\text{eq}}$ is less than $1$ , the reactants are favored over the products at equilibrium in this reaction.