Starting Out with C++ from Control Structures to Objects (9th Edition)
9th Edition
ISBN: 9780134498379
Author: Tony Gaddis
Publisher: PEARSON
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Chapter 18, Problem 31RQE
Program Plan Intro
Linked list:
Linked list is a linear and dynamic data structure which is used to organize data; it contains sequence of elements which are connected together in memory to form a chain. The every element of linked list is called as a node.
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Circular linked list is a form of the linked list data structure where all nodes are connected as in a circle, which
means there is no NULL at the end. Circular lists are generally used in applications which needs to go
around the list repeatedly.
struct Node * insertTONull (struct Node *last, int data)
// This function is only for empty list
11
5
15
struct Node insertStart (struct Node +last, int data)
In this question, you are going to implement the insert functions of a circular linked list in C. The
Node struct, print function and the main function with its output is given below:
struct Node
{
int data;
struct Node *next;
};
struct Node insertEnd (struct Node *last, int data)
void print(struct Node *tailNode)
struct Node *p;
if (tailNode -- NULL)
struct Node * insertSubseq (struct Node *last, int data, int item)
puts("Empty");
return;
p - tailNode → next;
do{
printf("%d ",p→data);
p - p > next;
while(p !- tailNode →next);
void main(void)
{
struct Node *tailNode - NULL;
tailNode -…
struct nodeType {
int infoData;
nodeType * next;
};
nodeType *first;
… and containing the values(see image)
Using a loop to reach the end of the list, write a code segment that deletes all the nodes in the list. Ensure the code performs all memory ‘cleanup’ functions.
Multiple choice in data structures
void doo(node<int>*root){
if(root !=0) { node<int>*p=root;
while(root->next!=0) root=root->next;
p->data=root->data;
}
What is this code do?
a.
swap the first item with the last item in the linked list
b.
set the first item in the linked list as the last item
c.
doesn't do anything because the root parameter is passed by value
d.
change the root item in the binary tree with the farthest leaf item
Chapter 18 Solutions
Starting Out with C++ from Control Structures to Objects (9th Edition)
Ch. 18.1 - Prob. 18.1CPCh. 18.1 - Prob. 18.2CPCh. 18.1 - Prob. 18.3CPCh. 18.1 - Prob. 18.4CPCh. 18.2 - Prob. 18.5CPCh. 18.2 - Prob. 18.6CPCh. 18.2 - Prob. 18.7CPCh. 18.2 - Prob. 18.8CPCh. 18.2 - Prob. 18.9CPCh. 18.2 - Prob. 18.10CP
Ch. 18 - Prob. 1RQECh. 18 - Prob. 2RQECh. 18 - Prob. 3RQECh. 18 - Prob. 4RQECh. 18 - Prob. 5RQECh. 18 - Prob. 6RQECh. 18 - Prob. 7RQECh. 18 - Prob. 8RQECh. 18 - Prob. 9RQECh. 18 - Prob. 10RQECh. 18 - Prob. 11RQECh. 18 - Prob. 12RQECh. 18 - Prob. 13RQECh. 18 - Prob. 14RQECh. 18 - Prob. 15RQECh. 18 - Prob. 16RQECh. 18 - Prob. 17RQECh. 18 - Prob. 18RQECh. 18 - Prob. 19RQECh. 18 - Prob. 20RQECh. 18 - Prob. 21RQECh. 18 - Prob. 22RQECh. 18 - Prob. 23RQECh. 18 - Prob. 24RQECh. 18 - Prob. 25RQECh. 18 - T F The programmer must know in advance how many...Ch. 18 - T F It is not necessary for each node in a linked...Ch. 18 - Prob. 28RQECh. 18 - Prob. 29RQECh. 18 - Prob. 30RQECh. 18 - Prob. 31RQECh. 18 - Prob. 32RQECh. 18 - Prob. 33RQECh. 18 - Prob. 34RQECh. 18 - Prob. 35RQECh. 18 - Prob. 1PCCh. 18 - Prob. 2PCCh. 18 - Prob. 3PCCh. 18 - Prob. 4PCCh. 18 - Prob. 5PCCh. 18 - Prob. 6PCCh. 18 - Prob. 7PCCh. 18 - List Template Create a list class template based...Ch. 18 - Prob. 9PCCh. 18 - Prob. 10PCCh. 18 - Prob. 11PCCh. 18 - Prob. 12PCCh. 18 - Prob. 13PCCh. 18 - Prob. 14PCCh. 18 - Prob. 15PC
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