Starting Out with C++ from Control Structures to Objects (9th Edition)
9th Edition
ISBN: 9780134498379
Author: Tony Gaddis
Publisher: PEARSON
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Question
Chapter 18, Problem 16RQE
The “appending” a node means adding it to the end of a list.
Program Plan Intro
Linked list:
Linked list is a linear and dynamic data structure which is used to organize data; it contains sequence of elements which are connected together in memory to form a chain. The every element of linked list is called as a node.
Liked list operations:
The basic linked list operations used to manipulate a list are as follows:
- Appending a node into the list
- Inserting a node into the list
- Deleting a node from the list
- Traversing the list
- Destroying the list
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6. __________ a node means adding it to the end of a list.
a) Write a function to get the value of the Nu node in a Linked List. [Note: The first (N=1) item in
the list means the item at index 0.] It takes two parameters: the list or its head, and N. Return
False if the list has fewer than N elements. The Linked List structure supports the following
function.
def getlead(self):
return selt.head # it points to a Node structure
The Node structure supports the following functions.
def getData(self):
return self.data # it returns the value stored in the Node
def getNext(self):
return self next # it points to the next Node
b) Write a function that counts the number of times a given integer occurs in a Linked List.
Assume similar structures as defined in 1.
A list that contains no data elements is said to be __________.
Chapter 18 Solutions
Starting Out with C++ from Control Structures to Objects (9th Edition)
Ch. 18.1 - Prob. 18.1CPCh. 18.1 - Prob. 18.2CPCh. 18.1 - Prob. 18.3CPCh. 18.1 - Prob. 18.4CPCh. 18.2 - Prob. 18.5CPCh. 18.2 - Prob. 18.6CPCh. 18.2 - Prob. 18.7CPCh. 18.2 - Prob. 18.8CPCh. 18.2 - Prob. 18.9CPCh. 18.2 - Prob. 18.10CP
Ch. 18 - Prob. 1RQECh. 18 - Prob. 2RQECh. 18 - Prob. 3RQECh. 18 - Prob. 4RQECh. 18 - Prob. 5RQECh. 18 - Prob. 6RQECh. 18 - Prob. 7RQECh. 18 - Prob. 8RQECh. 18 - Prob. 9RQECh. 18 - Prob. 10RQECh. 18 - Prob. 11RQECh. 18 - Prob. 12RQECh. 18 - Prob. 13RQECh. 18 - Prob. 14RQECh. 18 - Prob. 15RQECh. 18 - Prob. 16RQECh. 18 - Prob. 17RQECh. 18 - Prob. 18RQECh. 18 - Prob. 19RQECh. 18 - Prob. 20RQECh. 18 - Prob. 21RQECh. 18 - Prob. 22RQECh. 18 - Prob. 23RQECh. 18 - Prob. 24RQECh. 18 - Prob. 25RQECh. 18 - T F The programmer must know in advance how many...Ch. 18 - T F It is not necessary for each node in a linked...Ch. 18 - Prob. 28RQECh. 18 - Prob. 29RQECh. 18 - Prob. 30RQECh. 18 - Prob. 31RQECh. 18 - Prob. 32RQECh. 18 - Prob. 33RQECh. 18 - Prob. 34RQECh. 18 - Prob. 35RQECh. 18 - Prob. 1PCCh. 18 - Prob. 2PCCh. 18 - Prob. 3PCCh. 18 - Prob. 4PCCh. 18 - Prob. 5PCCh. 18 - Prob. 6PCCh. 18 - Prob. 7PCCh. 18 - List Template Create a list class template based...Ch. 18 - Prob. 9PCCh. 18 - Prob. 10PCCh. 18 - Prob. 11PCCh. 18 - Prob. 12PCCh. 18 - Prob. 13PCCh. 18 - Prob. 14PCCh. 18 - Prob. 15PC
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- 2-) In a double linked list, the structure of a node is defined as follows: struct node { int employeeNo; char name[20]; struct node *next; structnode *prev; }node; the nodes in the list are sorted according to employeeNo in ascending order (from smaller to larger ). Write a function to insert a node with a given name and employeeNo into the list so that the list will remain the sorted. employeeNo değerine göre kiüçükten büyüğe sıralanmış bir çift bağlı liste olsun. Verilen bir isim ve employeeNo değerine sahip düğümü listeye sıra bozulmayacak şekilde ekleyen bir fonksyion yazınız.arrow_forwardFunctions that look at a linked list but do not modify it are referred to as______________arrow_forward#include <bits/stdc++.h> using namespace std; // Structure of a Node struct Node { int data;s struct Node *next; struct Node *prev; }; // Function to insert at the end void insertEnd(struct Node** start, int value) { // If the list is empty, create a single node // circular and doubly list if (*start == NULL) { struct Node* new_node = new Node; new_node->data = value; new_node->next = new_node->prev = new_node; *start = new_node; return; } // If list is not empty /* Find last node */ Node *last = (*start)->prev; // Create Node dynamically struct Node* new_node = new Node; new_node->data = value; // Start is going to be next of new_node new_node->next = *start; // Make new node previous of start (*start)->prev = new_node; // Make last preivous of new node new_node->prev = last; // Make new node next of old last last->next = new_node; } // Function to insert Node at the beginning // of the List, void insertBegin(struct…arrow_forward
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