Biology
5th Edition
ISBN: 9781260487947
Author: BROOKER
Publisher: MCG
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Chapter 18, Problem 2COQ
Mendel studied seven traits in garden pea plants, and this species happens to have seven different chromosomes. It has been pointed out that Mendel was very lucky not to have conducted crosses involving two traits governed by genes that are closely linked on the same chromosome, because the results would have confounded his theory of independent assortment. It has even been suggested that Mendel may not have published data involving traits that were linked! An article by Stig Blixt 1975. (Why Didn’t Gregor Mendel Find Linkage? Nature 256: 206, 1975) considers this issue. Look up this article, and discuss why Mendel did not find linkage.
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Mendel describes subjecting each of the 34 varieties of peas he obtained to a two-year trial. During this time he let the plants self-fertilize and observed their offspring. What was he looking for, and what was the purpose of doing this two-year trial?
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Someone gives you a bag of yellow peas and you plant them in the Spring. Can you predict the color of the peas that will appear in the pods on the plants grown from these peas? Would your answer be different if you had received a bag of green peas?
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Chapter 18 Solutions
Biology
Ch. 18.2 - Prob. 1CCCh. 18.3 - Prob. 1CCCh. 18.3 - Prob. 1CSCh. 18.5 - Prob. 1CSCh. 18.5 - Prob. 1CCCh. 18.6 - Prob. 1EQCh. 18.6 - Prob. 2EQCh. 18.6 - Prob. 3EQCh. 18.6 - Prob. 1CCCh. 18.6 - Prob. 2CC
Ch. 18 - Which of the following is an example of an...Ch. 18 - Prob. 2TYCh. 18 - A female mouse that is Igf2 Igf2 is crossed to a...Ch. 18 - Prob. 4TYCh. 18 - Prob. 5TYCh. 18 - Prob. 6TYCh. 18 - Prob. 7TYCh. 18 - Prob. 8TYCh. 18 - Based on the ideas proposed by Morgan, which of...Ch. 18 - Extranuclear inheritance occurs because a. certain...Ch. 18 - Define epigenetics. Are all epigenetic changes...Ch. 18 - What is a Barr body? How is its structure...Ch. 18 - Core Concept: Information A core concept of...Ch. 18 - Prob. 1COQCh. 18 - Mendel studied seven traits in garden pea plants,...
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- B B BB Bb b Bb bb Brown rabbits have the genotype BB or Bb. White rabbits have the genotype bb. If two brown rabbits, with the genotypes seen in the Punnett square above, have baby rabbits, what is the probability that the baby rabbits will also be brown? A B) 50% 75% D) 100% 5) According to Mendel's is why gametes have half the usual number of chromosomes. one copy of a gene is passed randomly from each parent to their offspring. This Sign out acerarrow_forwardA pure strain of Mendel's peas, dominant for all seven of his independently assorting genes, was testcrossed. How many different kind of gametes could each of the parents produced?arrow_forwardWhen Mendel did his experiments, it was the case that the genes for each trait were on separate pairs of homologous chromosomes. For example, the genes for pod color were on one pair of chromosomes and the genes for the seed coat were on a different pair of chromosomes. What if the genes for the two traits were on the same chromosome? (That is, if the gene for pod color was on the same chromosome as the gene for seed coat.) Would Mendel’s 2nd Law still hold? Why or why not?arrow_forward
- We have crossed true-breeding flies today. Wild type to mutant. Their phenotypes were wt and vg se. (Let’s not worry about males and females for now, just assume both genes are autosomal, which is normal in a Mendelian experiment). The results of a cross are phenotypes. I will be asking you for numbers or a ratio of phenotype numbers you expect to see in the offspring from this cross. To answer this, you’ll need to start with the genotypes of parents, then write their gametes, then write the offspring genotypes, then get the phenotypes based on them. Predict the results of this cross: In case both mutations are recessive; In case both mutations are dominant; In case vestigial wings are recessive and the sepia eyes are dominant.arrow_forwardMendel crossed pea plants that produced round seeds with those that produced wrinkled seeds and self-fertilized the progeny. In the F2, he observed 5474 round seeds and 1850 wrinkled seeds. Using the letters W and w for the seed texture alleles, diagram Mendel's crosses, showing the genotypes of the plants in each generation. Are the results consistent with the Principle of Segregation?arrow_forwardMendel obtained his initial pea plant varieties from local breeders who were developing new varieties that might be useful or interesting. To generate these new varieties, breeders formed hybrids between existing varieties of different phenotypic characteristics by cross-pollination, using techniques they doubtless taught to Mendel. After producing a hybrid, they allowed several generations of self-pollination, as happens naturally if the flowers are not disturbed. i. How many generations would it take for a breeder to have produced new pure-breeding varieties using this approach? ii. What is the probability that an individual in each of these generations (F2, F3, and F10) would be homozygous for one or the other allele of this gene? [Broad hint: if they’re not heterozygous, they’re homozygous!] please answer and explain properlyarrow_forward
- In this program, you are provided with phenotype pair counts of F2 offspring at two research institutes. The key different between this work and previous work is that now we consider two genes instead of one. The phenotype pairs are the (shape, color) of peas from a pea plant. It turns out that there are two separate genes that code for these phenotypes. We shall call them Shape and Color. Gregor Mendel originally recorded these experiments in green peas. Using the notation: R = Round (dominant) allele at Shape gene; r = Wrinkled (recessive) allele at Shape gene; Y = Yellow (dominant) allele at Color gene; y = Green (recessive) allele at Color gene; then the shape and color of any pea can be determined by studying the genotypes at each gene. It turns out that, when one mates a plant that is homozygous for the dominant alleles (RRYY) with a plant that is homozygous for the recessive alleles (rryy), the F1 generation are heterozygous at both genes, as with a single gene disorder.…arrow_forwardGenes A and B are on two different chromosomes. You construct a Punnett Square to to show the expected genotypes in the offspring of a cross between these two genotypes: AaBB x AaBb. What are the dimensions of the smallest Punnett square you can make to show the expected results? (e.g., 2x2, 4x1. Don’t worry about the order of the two numbers if they differ. That is, 4x8 is the same as 8x4)arrow_forwardWhy did Mendel perform "reciprocal crosses"? Someone gives you a bag of yellow peas and you plant them in the Spring. Can you predict the color of the peas that will appear in the pods on the plants grown from these peas? Would your answer be different if you had received a bag of green peas? Explain what Mendel means when he writes that the 3:1 ratio observed in the first generation from the hybrids "resolves itself" into a ratio of 2:1:1arrow_forward
- A geneticist discovers an obese mouse in his laboratory colony. He breeds this obese mouse with a normal mouse. All the F1 mice from this cross are normal in size. When he interbreeds two F1 mice, eight of the F2 mice are normal in size and two are obese. The geneticist then intercrosses two of his obese mice, and he finds that all the progeny from this cross are obese. These results lead the geneticist to conclude that obesity in mice results from a recessive allele. A second geneticist at a different university also discovers an obese mouse in her laboratory colony. She carries out the same crosses as the first geneticist and obtains the same results. She also concludes that obesity in mice results from a recessive allele. One day the two geneticists meet at a genetics conference, learn of each other’s experiments, and decide to exchange mice. They both find that, when they cross two obese mice from the different laboratories, all the offspring are normal; however, when they cross…arrow_forwardA pure strain of Mendel’s peas, dominant for all seven of his independently assorting genes, was testcrossed. (a) How many different kinds of gametes could each of the parents produce? (b) How many different gametes could the F1 produce? (c) If the F1, was testcrossed, how many phenotypes would be expected in the offspring and in what proportions? d) How many genotypes would be expected in the F2? (e) How many combinations of F1 gametes are theoretically possible (considering, e.g., AABBCCDDEEFFGG sperm nucleus x aabbccddeefigg egg nucleus a different combination than AABBCCDDEEFFGG egg nucleus x aabbccddeeflgg sperm nucleus)? (f) How many different kinds of matings could theoretically be made among the F2?arrow_forwardA dihybrid cross is performed between two heterozygous individuals (heterozygous for two traits). The resulting offspring had 62 individuals that were dominant for trait 1 and 2 (D/D), 7 individuals that were R/R, 21 individuals that were R/D, and 25 individuals that were D/R. Using Mendelian inheritance as the null hypothesis, use χ2 analysis to determine if the trait follows Mendelian inheritance. A. How many D/D phenotype offspring are expected? B. How many R/D phenotype offspring are expected? C. How many degrees of freedom are there? D. What is your calculated χ2 value? E. What is the critical value if using a probability of 0.05? F. Does the trait follow Mendelian inheritance?arrow_forward
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