Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 18, Problem 19P
You are traveling in the Netherlands and overhear a tulip breeder describe a puzzling event. Tulips normally have two outer whorls of brightly colored petal
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Chapter 18 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 18 - 18.1 Explain why many developmental genes encode...Ch. 18 - Bird beaks develop from an embryonic group of...Ch. 18 - 18.3 How is positional information provided along...Ch. 18 - Early development in Drosophila is atypical in...Ch. 18 - 18.5 Consider the evenskipped regulatory sequences...Ch. 18 - What is the difference between a parasegment and...Ch. 18 - Why do loss-of-function mutations in Hox genes...Ch. 18 - 18.8 Compare and contrast the specification of...Ch. 18 - Prob. 9PCh. 18 - Ablation of the anchor cell in wild type C....
Ch. 18 - 18.11 In gain-of-function and. elegans mutants,...Ch. 18 - Prob. 12PCh. 18 - Prob. 13PCh. 18 - 18.14 Given that maternal Bicoid activates the...Ch. 18 - What phenotypes do you expect in flies homozygous...Ch. 18 - The pair rule gene fushitarazu is expressed in...Ch. 18 - 18.17 In contrast to Drosophila, some insects...Ch. 18 - Prob. 18PCh. 18 - 18.19 You are traveling in the Netherlands and...Ch. 18 - 19.20 A powerful approach to identifying genes of...Ch. 18 - The Hoxd 913 genes are thought to specify digit...Ch. 18 - Three-spined stickleback fish live in lakes formed...Ch. 18 - The flowering jungle plant Lacandoniaschismatica,...Ch. 18 - 18.24 Homeotic genes are thought to regulate each...Ch. 18 - Prob. 25PCh. 18 - Basidiomycota is a monophyletic group of fungi...Ch. 18 - Prob. 27PCh. 18 - In C. elegans there are two sexes: hermaphrodite...Ch. 18 - In Drosophila, recessive mutations in the...
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- Hybridization of a homozygous dominant and homozygous recessive plant was conducted. What is the probability that the F2 progeny will have the both pink flowers and fruits?arrow_forwardWaxy endosperm (wx), shrunken endosperm (sh), and yellow seedlings (v) are encoded by three recessive genes in corn that are linked on chromosome 5. A corn plant homozygous for all three recessive alleles is crossed with a plant homozygous for all the dominant alleles. The resulting F1 are then crossed with a plant homozygous for the recessive alleles in a three-point testcross. The progeny of the testcross are wx sh V 87 Wx Sh v 94 Wx Sh V 3,479 wx sh v 3,478 Wx sh V 1,515 wx Sh v 1,531 wx Sh V 292 Wx sh v 280 Total 10,756 a. Determine the order of these genes on the chromosome. b. Calculate the map distances between the genes. c. Determine the coefficient of coincidence and the interference among these genes.arrow_forwardYou are studying a plant with tissue comprising both green and white sectors. You wish to decide whether this phenomenon is due (1) to a chloroplast mutation of the type considered in this chapter or (2) to a dominant nuclear mutation that inhibits chlorophyll production and is present only in certain tissue layers of the plant as a mosaic. Outline the experimental approach that you would use to resolve this problem.arrow_forward
- Round (R) seed shape is dominant to wrinkled (r) seed shape in pea plants. If an RR plant is crossed with an rr plant, what is the frequency of phenotypes in the F2 generation? 1)1/4 RR, 1/2 Rr, 1/4 rr 2) All round seeds 3) 3 roundseeds, 1 wrinkled seed 4) All wrinkled seedsarrow_forward4. (a) Please fill out the following table to describe the classic floral phenotypes of A, B, and C class homeotic mutants. The organ identities of the four whorls in a wild type Arabidopsis flower are filled out for you. Please fill out the rest of the table to indicate the organ identities in different whorls of the mutant flowers. ( Whorl 1 Whorl 2 Whorl 3 Whorl 4 Wild type sepals petals stamens carpels A class gene mutants B class gene mutants C class gene mutantsarrow_forwardWaxy endosperm (wx), shrunken endosperm (sh) and yellow seedling (v) are encoded by three recessive genes in corn that are linked on chromosome 5. A corn plant homozygous for all three recessive alleles is crossed with a plant homozygous for all the dominant alleles. The resulting F1 are then crossed with a plant homozygous for the recessive alleles in a three point test cross. The progeny of the test cross are: wx sh WX SH V WX SH V Wx sh WX sh V SH v SH V V 87 1,515 94 WX 1,531 3,479 292 WX Wx sh v 3,478 280 a. Determine the order of the genes on the chromosome. b. Calculate the map distances between the genes. c. Determine the cc and I.arrow_forward
- In tomatoes, the red fruit color is completely dominant to yellow. Suppose a tomato plant homozygous for red is crossed with one homozygous for yellow and the progeny are allowed to self pollinate. What phenotypes do you predict in the F2 generation? a) 3 red: 1 yellow b) 9 red : 3 orange : 1 yellow c) 1 red : 2 orange : 1 yellow d) 1 red : 1 yellowarrow_forwardA) Describe the data you collect from the Purple 1 x Purple 2 cross. Predict the genotype of each of the parent plants. Explain your predictions using data from the experiment. B) Consider the offspring, the next generation (F1), from the Purple 1 x Purple 2 cross. What is the probability of a green stem plant? How do you know this? C) What is the probability in the F2 generation of a green stem offspring? Use a Punnett square(s) and quantitative data to explain your thinking. Upload your Punnett square(s).arrow_forwardA male plant with genotype AaBBCcDdee was crossed with one heterozygous for all thegenes. (a) what is the probability of getting a pollen with ABcDe genes? (b) of producing anovum with three dominant and two recessive genes? (c) of getting a progeny with samephenotype as the female parent? (d) of progeny with exactly same genotype as the femaleparent? (e) If instead of the above male, the cross was with one heterozygous for all thegenes, what proportion of the offspring will have three dominant phenotypic traits. (f) willbe genotypically like the parents?arrow_forward
- 3) Some pea plant varieties show reduced growth (pygmy) and abnormal leaf formation (crinkly). Both characteristics are recessive to the normal sized plant and normal leaf. If a plant, heterozygour for both characteristics, is self pollinated and 320 seeds are subsequently collected and germinated, how many of the offspring would you expect to show... a) normal leaves and pygmy size b) crinkly leaves c) normal leaves and normal size d) normal size?arrow_forwardA GENETICIST DISCOVERS A NEW MUTATION IN PEAS THAT CAUSES MOTTLED FLOWER COLOR. SHE CALLS THIS MUTATION SPOTTY AND DETERMINES THAT IT IS DUE TO AN AUTOSOMAL RECESSIVE ALLELE (S). SHE WANTS TO DETERMINE WHETHER THE GENE ENCODING SPOTTY IS LINKED TO THE RECESSIVE GENE FOR FLOWER COLOR (WHITE, W, IS RECESSIVE TO PURPLE). SHE CROSSES A PLANT HETEROZYGOUS FOR BOTH TRAITS WITH A PLANT HOMOZYGOUS RECESSIVE FOR BOTH TRAITS AND OBTAINED THE FOLLOWING PROGENY: NORMAL, PURPLE: 86 NORMAL, WHITE: 14 SPOTTY, PURPLE: 10 SPOTTY, WHITE: 90 WHAT ARE THE GENOTYPES FOR EACH OF THESE FOUR PROGENY TYPES? WHICH ALLELES ARE FOUND ON EACH CHROMOSOME OF THE DOUBLE HETEROZYGOTE PARENT? (USE SLASH NOTATION.) WHAT IS THE DISTANCE IN CM BETWEEN THESE TWO GENES? .arrow_forwardA GENETICIST DISCOVERS A NEW MUTATION IN PEAS THAT CAUSES MOTTLED FLOWER COLOR. SHE CALLS THIS MUTATION SPOTTY AND DETERMINES THAT IT IS DUE TO AN AUTOSOMAL RECESSIVE ALLELE (S). SHE WANTS TO DETERMINE WHETHER THE GENE ENCODING SPOTTY IS LINKED TO THE RECESSIVE GENE FOR FLOWER COLOR (WHITE, W, IS RECESSIVE TO PURPLE). SHE CROSSES A PLANT HETEROZYGOUS FOR BOTH TRAITS WITH A PLANT HOMOZYGOUS RECESSIVE FOR BOTH TRAITS AND OBTAINED THE FOLLOWING PROGENY:NORMAL, PURPLE: 86 NORMAL, WHITE: 14 SPOTTY, PURPLE: 10 SPOTTY, WHITE: 90• WHAT ARE THE GENOTYPES FOR EACH OF THESE FOUR PROGENY TYPES?• WHICH ALLELES ARE FOUND ON EACH CHROMOSOME OF THE DOUBLE HETEROZYGOTE PARENT? (USE SLASH NOTATION.)• WHAT IS THE DISTANCE IN CM BETWEEN THESE TWO GENES?arrow_forward
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